（并查集添加关系）How Many Answers Are Wrong --Hdu --3038

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（并查集添加关系）How Many Answers Are Wrong --Hdu --3038

链接: http://acm.hdu.edu.cn/showproblem.php?pid=3038 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=82830#problem/D 代码: #include<stdio.h> #include<string.h> #include<stdlib.h> #include<math.h> #include<algorithm> #includ…

食物链--poj1182（并查集含有关系）

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（并查集带关系）Find them, Catch them -- poj -- 1703

链接: http://poj.org/problem?id=1703 Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 36768 Accepted: 11294 Description The police office in Tadu City decides to say ends to the chaos, as launch actions to root up the TWO gangs in the cit…

D - How Many Answers Are Wrong HDU - 3038【带权并查集】

How Many Answers Are Wrong Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 24151 Accepted Submission(s): 8191 Problem Description TT and FF are ... friends. Uh... very very good friends -____…

How Many Answers Are Wrong HDU - 3038 带边权并查集

#include<iostream> #include<cstring> using namespace std; ; int d[N],p[N]; int find(int x) { if(p[x]!=x) { int root=find(p[x]); d[x]+=d[p[x]]; p[x]=root; } return p[x]; } int main() { int n,m,a,b,sum; while(cin>>n>>m) { ;i<=n;i+…

How Many Answers Are Wrong HDU - 3038 （经典带权并查集）

题目大意:有一个区间,长度为n,然后跟着m个子区间,每个字区间的格式为x,y,z表示[x,y]的和为z.如果当前区间和与前面的区间和发生冲突,当前区间和会被判错,问:有多少个区间和会被判错. 题解:x,y,z表示从x开始到y的所有数字的和,那么x-1就表示从(x-1,y]的区间和.我们可以对区间的左边x-1寻找他的左端点,同时对区间右边y也寻找他的左端点,如果这两个左端点相等(设为l)那么他就是将区间了[l,y]拆分成了[l,x-1]和[x,y],我们判断一下区间和是不是相等的就可以了也就是w[…

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并查集的介绍可以看下https://www.cnblogs.com/jkzr/p/10290488.html A - Wireless Network POJ - 2236 An earthquake takes place in Southeast Asia. The ACM (Asia Cooperated Medical team) have set up a wireless network with the lap computers, but an unexpected afters…