HDU 5636 Shortest Path(Floyd)】的更多相关文章

题目链接  HDU5636 n个点,其中编号相邻的两个点之间都有一条长度为1的边,然后除此之外还有3条长度为1的边. m个询问,每次询问求两个点之前的最短路. 我们把这三条边的6个点两两算最短路, 然后询问的时候用这6个点的距离来更新答案就可以了. (不过听说好像有更好的方法,先占个坑) 时间复杂度$O(216m)$ #include <bits/stdc++.h> using namespace std; #define rep(i, a, b) for (int i(a); i <=…
题目链接:pid=3631" style="font-size:18px">http://acm.hdu.edu.cn/showproblem.php?pid=3631 Shortest Path Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3962    Accepted Submission(s): 9…
Description When YY was a boy and LMY was a girl, they trained for NOI (National Olympiad in Informatics) in GD team. One day, GD team’s coach, Prof. GUO asked them to solve the following shortest-path problem. There is a weighted directed multigraph…
Shortest Path 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5636 Description There is a path graph G=(V,E) with n vertices. Vertices are numbered from 1 to n and there is an edge with unit length between i and i+1 (1≤i<n). To make the graph more in…
Shortest Path  Accepts: 40  Submissions: 610  Time Limit: 4000/2000 MS (Java/Others)  Memory Limit: 131072/131072 K (Java/Others) 问题描述 有一条长度为nn的链. 节点ii和i+1i+1之间有长度为11的边. 现在又新加了3条边, 每条边长度都是1. 给出mm个询问, 每次询问两点之间的最短路. 输入描述 输入包含多组数据. 第一行有一个整数TT, 表示测试数据的组数…
Shortest Path Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 1146 Accepted Submission(s): 358 Problem Description There is a path graph G=(V,E) with n vertices. Vertices are numbered from 1 to…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5636 题解: 1.暴力枚举: #include<cmath> #include<cstdio> #include<iostream> #include<algorithm> using namespace std; typedef long long LL; ; ; int n, m; ], b[]; int main() { int T; scanf(&qu…
题意:bc round 74 分析(官方题解): 你可以选择分类讨论, 但是估计可能会写漏一些地方. 只要抽出新增边的端点作为关键点, 建立一个新图, 然后跑一遍floyd就好了. 复杂度大概O(6^2m) 注:然后我不会这种,这种floyd我觉得复杂度应该是复杂度应该是O(8^3m) 大概在千万级别,其实应该可以过,然后,其实只需要求单元最短路就行,然后是不是可以dij,然后就快一点 反正我也没写 我在比赛的时候写的是分治,考虑走不走新加的边每次走几条,以及走的顺序就好 然后全排列,时间复杂度…
Prime Path Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 987    Accepted Submission(s): 635 Problem Description The ministers of the cabinet were quite upset by the message from the Chief of S…
六度分离 Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2927    Accepted Submission(s): 1127 [题目链接]http://acm.hdu.edu.cn/showproblem.php?pid=1869 [解题思路]Floyd算法,要证明两个素不相识的人通过中间的六个人就能联系起来,这就意味着这两个素不相…
题目来源:https://leetcode.com/problems/find-the-shortest-superstring/description/ 标记难度:Hard 提交次数:3/4 代码效率:2.93% -> 79.31% 题意 有N个字符串,找到最小的字符串S,使得这N个字符串都是S的子串.其中N<=12,字符串的长度<=20. 分析 这道题比赛的时候我没有做出来,但我自认为自己已经找到了正确的解法(确实差不多是正确的),只要再调一小会就能调出来了!结果事实是又花了两天才弄…
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HDU 1711 Number Sequence(数列) Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) [Description] [题目描述] Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N…
HDU 1005 Number Sequence(数列) Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) [Description] [题目描述] A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, an…
HDU 1176 免费馅饼 (动态规划) Description 都说天上不会掉馅饼,但有一天gameboy正走在回家的小径上,忽然天上掉下大把大把的馅饼.说来gameboy的人品实在是太好了,这馅饼别处都不掉,就掉落在他身旁的10米范围内.馅饼如果掉在了地上当然就不能吃了,所以gameboy马上卸下身上的背包去接.但由于小径两侧都不能站人,所以他只能在小径上接.由于gameboy平时老呆在房间里玩游戏,虽然在游戏中是个身手敏捷的高手,但在现实中运动神经特别迟钝,每秒种只有在移动不超过一米的范围…
Java Learning Path(四) 方法篇 Java作为一门编程语言,最好的学习方法就是写代码.当你学习一个类以后,你就可以自己写个简单的例子程序来运行一下,看看有什么结果,然后再多调用几个类的方法,看看运行结果,这样非常直观的把类给学会了,而且记忆非常深刻.然后不应该满足把代码调通,你应该想想看如果我不这样写,换个方式,再试试行不行.记得哪个高人说过学习编程就是个破坏的过程,把书上的例子,自己学习Documentation编写的例子在运行通过以后,不断的尝试着用不同的方法实现,不断的尝…
Java Learning Path(五)资源篇 1. http://java.sun.com/ (英文) Sun的Java网站,是一个应该经常去看的地方.不用多说. 2.http://www-900.ibm.com/developerWorks/cn/ IBM的developerWorks网站,英语好的直接去英文主站点看.这里不但是一个极好的面向对象的分析设计网站,也是Web Services,Java,Linux极好的网站.强烈推荐!!! 3.http://www.javaworld.com…
Java Learning Path(三)过程篇 每个人的学习方法是不同的,一个人的方法不见得适合另一个人,我只能是谈自己的学习方法.因为我学习Java是完全自学的,从来没有问过别人,所以学习的过程基本上完全是自己摸索出来的.我也不知道这种方法是否是比较好的方法,只能给大家提供一点参考了. 学习Java的第一步是安装好JDK,写一个Hello World,? 其实JDK的学习没有那么简单,关于JDK有两个问题是很容易一直困扰Java程序员的地方:一个是CLASSPATH的问题,其实从原理上来说,…
Shortest Path Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 627    Accepted Submission(s): 204 Problem Description There is a path graph G=(V,E) with n vertices. Vertices are numbered from 1…
The Shortest Path Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3164    Accepted Submission(s): 1030 Problem Description There are N cities in the country. Each city is represent by a matrix s…
Description Given a weighted directed graph, we define the shortest path as the path who has the smallest length among all the path connecting the source vertex to the target vertex. And if two path is said to be non-overlapping, it means that the tw…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2544 题目大意:找点1到点n的最短路(无向图) 练一下最短路... dijkstra+队列优化: #include<iostream> #include<functional> #include<vector> #include<queue> using namespace std; typedef pair<int, int> p;//first是…
http://acm.hdu.edu.cn/showproblem.php?pid=1869 六度分离 Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4355    Accepted Submission(s): 1768 Problem Description 1967年,美国著名的社会学家斯坦利·米尔格兰姆提出了一个名为“小世界现象…
Shortest Path Time Limit: 1000MS Memory Limit: 32768KB 64bit IO Format: %I64d & %I64u SubmitStatus Description When YY was a boy and LMY was a girl, they trained for NOI (National Olympiad in Informatics) in GD team. One day, GD team's coach, Prof. G…
题目链接:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=GRL_1_A Single Source Shortest Path Input An edge-weighted graph G (V, E) and the source r. |V| |E| r s0 t0 d0 s1 t1 d1 : s|E|−1 t|E|−1 d|E|−1 |V| is the number of vertices and |E| is the…
The Shortest Path Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2440    Accepted Submission(s): 784 Problem Description There are N cities in the country. Each city is represent by a matrix si…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1869 转载请注明出处:http://blog.csdn.net/u012860063?viewmode=contents Problem Description 1967年,美国著名的社会学家斯坦利·米尔格兰姆提出了一个名为"小世界现象(small world phenomenon)"的著名假说,大意是说,不论什么2个素不相识的人中间最多仅仅隔着6个人,即仅仅用6个人就能够将他们联系在一起…
http://acm.hdu.edu.cn/showproblem.php?pid=4034 Graph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65768/65768 K (Java/Others)Total Submission(s): 2058    Accepted Submission(s): 1030 Problem Description Everyone knows how to calculate the…
Floyd–Warshall(简称Floyd算法)是一种著名的解决任意两点间的最短路径(All Paris Shortest Paths,APSP)的算法.从表面上粗看,Floyd算法是一个非常简单的三重循环,而且纯粹的Floyd算法的循环体内的语句也十分简洁.我认为,正是由于“Floyd算法是一种动态规划(Dynamic Programming)算法”的本质,才导致了Floyd算法如此精妙.因此,这里我将从Floyd算法的状态定义.动态转移方程以及滚动数组等重要方面,来简单剖析一下图论中这一重…