HDU 1686 Oulipo / POJ 3461 Oulipo / SCU 2652 Oulipo (字符串匹配,KMP) Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book: Tout avait…
POJ 3461 Oulipo(乌力波) Time Limit: 1000MS   Memory Limit: 65536K [Description] [题目描述] The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book: Tou…
题目传送门 /* 题意:一个串有字串重复n次产生,求最大的n KMP:nex[]的性质应用,感觉对nex加深了理解 */ /************************************************ * Author :Running_Time * Created Time :2015-8-10 10:51:54 * File Name :POJ_2406.cpp ************************************************/ #incl…
http://poj.org/problem?id=2406 Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 27003   Accepted: 11311 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = &q…
链接: http://poj.org/problem?id=2406 Power Strings Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc&qu…
Power Strings Time Limit: 3000MSMemory Limit: 65536K Total Submissions: 29663Accepted: 12387 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef…
连续重复子串问题 poj 2406 Power Strings http://poj.org/problem?id=2406 问一个串能否写成a^n次方这种形式. 虽然这题用kmp做比较合适,但是我们还是用后缀数组做一做,巩固后缀数组的能力. 对于一个串,如果能写出a^n这种形式,我们可以暴力枚举循环节长度L,那么后缀suffix(1)和suffix(1 + L)的LCP应该就是 lenstr - L.如果能满足,那就是,不能,就不是. 这题的话da算法还是超时,等我学了DC3再写上来. 其实这…
Power Strings POJ - 2406 时限: 3000MS   内存: 65536KB   64位IO格式: %I64d & %I64u 提交 状态 已开启划词翻译 问题描述 Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef".…
  E - Oulipo Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 3461 Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a memb…
传送门:http://poj.org/problem?id=3461 Oulipo Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 50450   Accepted: 20018 Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a…
  E - Oulipo Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 3461 Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a memb…
Power Strings Problem's Link: http://poj.org/problem?id=2406 Mean: 给你一个字符串,让你求这个字符串最多能够被表示成最小循环节重复多少次得到. analyse: KMP之next数组的运用.裸的求最小循环节. Time complexity: O(N) Source code:  ;;      ;);      ) ;}/* */…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 30069   Accepted: 12553 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…
点击打开链接 Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 27368   Accepted: 11454 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b =…
Language: Default Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 33205   Accepted: 13804 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def"…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 28859   Accepted: 12045 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…
F - Power Strings Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2406 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = &…
首先先讲一下KMP算法作用: KMP就是来求在给出的一串字符(我们把它放在str字符数组里面)中求另外一个比str数组短的字符数组(我们叫它为ptr)在str中的出现位置或者是次数 这个出现的次数是可以重叠的 例如:在数组   ababa    中  aba的出现次数-----------它的答案是2------分别是从[0---2]  [2---4] 他们是可以重叠的,但是不可以完全重叠(废话T_T) KMP算法主要有两个模板 1.https://blog.csdn.net/starstar1…
题目:POJ3080 http://poj.org/problem?id=3080 题意:对于输入的文本串,输出最长的公共子串,如果长度相同,输出字典序最小的. 这题数据量很小,用暴力也是16ms,用后缀数组可以到0ms,但我不会XD. 暴力: #include<cstdio> #include<cstring> using namespace std; ][],ans[]; int main(){ int T,n; scanf("%d", &T); w…
HDU题目 POJ题目 求目标串s中包含多少个模式串p KMP算法,必须好好利用next数组,, (kmp解析)——可参考 海子的博客  KMP算法 //写法一: #include<string> #include <stdio.h> #include <iostream> #include <algorithm> #include <string.h> using namespace std; void getNext(char *p,int…
传送门 Oulipo Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 32373   Accepted: 13093 Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A…
Oulipo Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 23667   Accepted: 9492 Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote…
Oulipo Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 36903   Accepted: 14898 Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quot…
Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book: Tout avait Pair normal, mais tout s'affirmait faux. Tout avait Fair normal,…
Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book: Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal,…
题意:统计其中一个子串的出现次数 题解:即KMP算法中j==m的次数 //作者:1085422276 #include <cstdio> #include <cmath> #include <cstring> #include <ctime> #include <iostream> #include <algorithm> #include <set> #include <vector> #include &l…
题意:给出几组数据,每组有字符串W和T,问你W在T中出现几次. 思路:字符串长度很大,用KMP算法. 一开始写的是:调用KMP算法查找W在T中是否匹配,若匹配,则个数+1.则接下来T的索引移动相应的距离,再调用函数判断T接下来的序列中是否存在W. 如果不能匹配,则终止. 结果,这样超时了...估计是调用函数上面花费了些时间. 后来直接在函数中记录出现的个数,这样就不超时了. #include <iostream> #include <stdio.h> #include <st…
2017-08-13 19:31:47 writer:pprp 对kmp算法有了大概的了解以后,虽然还不够深入,但是已经可以写出来代码,(可以说是背会了) 所以这道题就作为一个模板,为大家使用吧. 题目大意:给你一个子串P和一个主串S,求在主串中有多少个子串? 代码如下:(需要注意的点我都标记好了,两个函数可以直接用) #include <iostream> #include <cstdio> #include <cstdlib> #include <cstrin…
题意:统计子串出现在主串中的次数 思路:典型kmp #include<iostream> #include<stdio.h> #include<string.h> using namespace std; ]; void GetNext(char t[]){//求next数组 int j,k,len; j=; k=-; next[]=-; len=strlen(t); while(j<len){ ||t[j]==t[k]){ ++j; ++k; next[j]=k…
本题就是给出非常多对字符串,然后问一个字符串在另外一个字符串出现的次数. 就是所谓的Strstr函数啦. Leetcode有这道差点儿一模一样的题目. 使用KMP算法加速.算法高手必会的算法了. 另外看见讨论说什么使用KMP还超时,最大可能是没有真正理解next table的含义,写了错误的代码,故此尽管自己执行结果正确,可是却没有真正发挥next table的作用.使得算法退化为暴力法了,所以执行正确,但超时. KMP參考: http://blog.csdn.net/kenden23/arti…