题目描述:Generate Parentheses Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())",…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" 解题思路一:…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" 思路: 有关P…

https://leetcode.com/problems/generate-parentheses/ Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()&q…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ]   …

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] pub…

题目简述: Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" 解…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" 思路:产生所有…

题目描述: Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" 解…

题目:http://oj.leetcode.com/problems/generate-parentheses/ 描述:给定一个非负整数n,生成n对括号的所有合法排列. 解答: 该问题解的个数就是卡特兰数,但是现在不是求个数,而是要将所有合法的括号排列打印出来. 该问题和<编程之美>的买票找零问题一样,通过买票找零问题我们可以知道,针对一个长度为2n的合法排列,第1到2n个位置都满足如下规则:左括号的个数大于等于右括号的个数.所以,我们就可以按照这个规则去打印括号:假设在位置k我们还剩余lef…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 题意:…

题目 Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ]…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" 题解: 很容易…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 解法:…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" 还是类似的括号…

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 根据题…

[题目] Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()()" [思…

原文链接:https://leetcode.com/problems/generate-parentheses 给出数字n,求n对括号组成的合法字符串. 刚做出来,敲完代码,修改了一次,然后提交,accepted ~ 还是小有成就感的..菜鸟... 先记录下自己的笨方法.再研究更高妙的方法. 刚看到题也是一头雾水.没法深入思考,感觉就是不断的罗列,被题目吓到了. 仔细观察,合法字符串的第一个字母肯定是( ,最后一个肯定是). 对于合法字符串的每一位,必定有 左括号的个数 >= 右括号的个数.每一…

题目链接 : https://leetcode.com/problems/generate-parentheses/?tab=Description   给一个整数n,找到所有合法的 () pairs    For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 递归程…

原题地址:https://leetcode.com/problems/generate-parentheses/ 解决方法:回溯法 class Solution { private: vector<string> coll; void helper(string s, int left, int right){ || right < ) return; == left && == right){ coll.push_back(s); return; } string lS…

给 n 对括号,写一个函数生成所有合适的括号组合.比如,给定 n = 3,一个结果为:[  "((()))",  "(()())",  "(())()",  "()(())",  "()()()"]详见:https://leetcode.com/problems/generate-parentheses/description/ 由于字符串只有左括号和右括号两种字符,而且最终结果必定是左括号3个,右括号3个…

原题 思路: 利用DFS,搜索每一种情况,同时先加"("后加")",保证()匹配正确. 最近开始学习前端,尝试用js来写. const generate = function (res,content, left, right) { if (left === 0) { res.push(content + ')'.repeat(right)); return; } if (left <= right && left > 0) { gene…

题目大意:给n个'(' 和 ')',构造出所有的长度为2*n并且有效的(可匹配的)字符串. 题目分析:这道题不难,可以直接搜索出所有可能的字符串,然后再逐一判断是否合法即可.但是还有更好的办法,实际上,“判断是否合法”这一操作是冗余的,如果可以直接朝着满足可匹配性的方向进行构造,就可避免这一冗余操作,这需要换一个角度思考. 一个有效(可匹配)字符串中, '(' 的个数决定了 ')' 的个数(从左向右看).所以,初始时,可以看成是 “有n个 '('  还没有用.有0个 ')'  必须要用”.这样,…

backtracking and invariant during generating the parathese righjt > left  (open bracket and cloase barckst) class Solution { //["((()))","(()())","(())()","()(())","()()()","())(()"] wrong cas…

leetcode 022. Generate Parentheses Concise recursive C++ solution class Solution { public: vector<string> generateParenthesis(int n) { vector<string> res; addingpar(res, "", n, 0); return res; } private: void addingpar(vector<stri…

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same type of brackets. Open brackets must be closed in the correct…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 22: Generate Parentheseshttps://oj.leetcode.com/problems/generate-parentheses/ Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.For exa…

回溯法 百度百科:回溯法(探索与回溯法)是一种选优搜索法,按选优条件向前搜索,以达到目标.但当探索到某一步时,发现原先选择并不优或达不到目标,就退回一步又一次选择,这样的走不通就退回再走的技术为回溯法,而满足回溯条件的某个状态的点称为"回溯点". 在包括问题的全部解的解空间树中,依照深度优先搜索的策略,从根结点出发深度探索解空间树.当探索到某一结点时,要先推断该结点是否包括问题的解,假设包括,就从该结点出发继续探索下去,假设该结点不包括问题的解,则逐层向其祖先结点回溯.(事实上回溯法就…

目录 题目链接 注意点 解法 小结 题目链接 Generate Parentheses - LeetCode 注意点 解法 解法一:递归.当left>right的时候返回(为了防止出现 )( ) class Solution { public: void recursion(int left,int right,string str,vector<string> &ret) { if(left > right) return; else if(left== 0&&a…

Leetcode之回溯法专题-22. 括号生成(Generate Parentheses) 给出 n 代表生成括号的对数,请你写出一个函数,使其能够生成所有可能的并且有效的括号组合. 例如,给出 n = 3,生成结果为: [ "((()))", "(()())", "(())()", "()(())", "()()()"] 分析:给定一个n,生成所有可能的括号组合. 举个例子,n=3,需要生成三个括号,那最…