Description 题目描述 While skimming his phone directory in 1982, Albert Wilansky, a mathematician of Lehigh University, noticed that the telephone number of his brother-in-law H. Smith had the following peculiar property: The sum of the digits of that nu…

Description While skimming his phone directory in 1982, Albert Wilansky, a mathematician of Lehigh University,noticed that the telephone number of his brother-in-law H. Smith had the following peculiar property: The sum of the digits of that number w…

http://poj.org/problem?id=1142 题意: 给出一个数n,求大于n的最小数,它满足各位数相加等于该数分解质因数的各位相加. 思路:直接暴力. #include <iostream> #include <cstring> #include <algorithm> #include <vector> #include <queue> #include <cmath> using namespace std; in…

题意:给定一个N,求一个大于N的最小的Smith Numbers,Smith Numbers是一个合数,且分解质因数之后上质因子每一位上的数字之和 等于 其本身每一位数字之和(别的博客偷的题意) 思路:主要是分治:分解成质因子使用递归即可. #include<cstdio> #include<cmath> // 检测素数 bool is_prime(int n) { ; i*i <= n;++i) ){ ; } ; } //数位 int sumfun(int n) { ; ;…

                               Smith Numbers Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 14521   Accepted: 4906 Description While skimming his phone directory in 1982, Albert Wilansky, a mathematician of Lehigh University,noticed tha…

While skimming his phone directory in 1982, Albert Wilansky, a mathematician of Lehigh University,noticed that the telephone number of his brother-in-law H. Smith had the following peculiar property: The sum of the digits of that number was equal to…

欢迎访问我的新博客:http://www.milkcu.com/blog/ 原文地址:http://www.milkcu.com/blog/archives/uva10042.html 原创:Smith Numbers - PC110706 作者:MilkCu 题目描述 Smith Numbers   While skimming his phone directory in 1982, mathematician Albert Wilansky noticed that the telepho…

一.题目大意 本题要求写出前5482个仅能被2,3,5, 7 整除的数. 二.题解 这道题从本质上和Poj 1338 Ugly Numbers(数学推导)是一样的原理,只需要在原来的基础上加上7的运算即可.还有一个不同之处在于输出上,这个题要求第n的英语表示.而英语中的表示呢,如果n的个位数是1,用nst表示个位数是2的用,nnd表示:个位数是3的,用nrd表示.但是n的最后两位是11.12.13的还是用nth表示,其他的也是用th表示. 三.java代码 import java.util.Sc…

Poj1142 Smith Numbers Smith Numbers Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 13854 Accepted: 4716 Description While skimming his phone directory in 1982, Albert Wilansky, a mathematician of Lehigh University,noticed that the telepho…

Smith Numbers Background While skimming his phone directory in 1982, Albert Wilansky, a mathematician of Lehigh University , noticed that the telephone number of his brother-in-law H. Smith had the following peculiar property: The sum of the digits o…

Smith Numbers Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 14173   Accepted: 4838 Description While skimming his phone directory in 1982, Albert Wilansky, a mathematician of Lehigh University,noticed that the telephone number of his b…

题意: 给你一个数x,把这个分解成素数之积(假设是x1*x2*x3),如果   x的每一数位的和   等于  x1每一数位的和加上x2每一数位的和加上x3每一数位的和,那么他就是题目要找的数 示例: 4937775 = 3 * 5 * 5 * 65837 电话号码的所有数字的和为4+9+3+7+7+7+5= 42,其质因数的数字的和为3+5+5+6+5+ 5+8+3+7=42. 题解: 暴力,具体见代码 代码: 1 #include<stdio.h> 2 #include<string.…

题目连接 http://poj.org/problem?id=3641 Pseudoprime numbers Description Fermat's theorem states that for any prime number p and for any integer a > 1, ap = a (mod p). That is, if we raise a to the pth power and divide by p, the remainder is a. Some (but…

题目链接:http://poj.org/problem?id=3252 题意: 一个数的二进制表示中0的个数大于等于1的个数则称作Round Numbers.求区间[L,R]内的 Round Numbers的个数. 思路: int c[N][N]; void init(){    int i,j;    FOR0(i,N)     {        c[i][0]=c[i][i]=1;        for(j=1;j<i;j++) c[i][j]=c[i-1][j-1]+c[i-1][j]; …

转载请注明出处:viewmode=contents">http://blog.csdn.net/u012860063? viewmode=contents 题目链接:id=1338">http://poj.org/problem?id=1338 Description Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence  1, 2, 3, 4, 5, 6, 8, 9, 1…

题目链接 题意:题目定义了Carmichael Numbers 即 a^p % p = a.并且p不是素数.之后输入p,a问p是否为Carmichael Numbers? 坑点:先是各种RE,因为poj不能用srand()...之后各种WA..因为里面(a,p) ?= 1不一定互素,即这时Fermat定理的性质并不能直接用欧拉定理来判定..即 a^(p-1)%p = 1判断是错误的..作的 #include<iostream> #include<cstdio> #include&l…

1.链接地址: http://poj.org/problem?id=1316 http://bailian.openjudge.cn/practice/1316 2.题目: 总时间限制: 1000ms 内存限制: 65536kB 描述 In 1949 the Indian mathematician D.R. Kaprekar discovered a class of numbers called self-numbers. For any positive integer n, define…

任意门:http://poj.org/problem?id=1320 Street Numbers Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 3181   Accepted: 1776 Description A computer programmer lives in a street with houses numbered consecutively (from 1) down one side of the…

题目链接:POJ 3641 Description Fermat's theorem states that for any prime number p and for any integer a > 1, ap = a (mod p). That is, if we raise a to the pth power and divide by p, the remainder is a. Some (but not very many) non-prime values of p, know…

 组合数学...(每做一题都是这么艰难) Round Numbers Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 7607 Accepted: 2615 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, P…

原题链接:http://poj.org/problem?id=1338 优先队列的应用,如下: #include<cstdio> #include<cstdlib> #include<queue> #include<functional> #include<iostream> #include<algorithm> using namespace std; typedef long long ll; ; ll ans[Max_N];…

Description Fermat's theorem states that for any prime number p and for any integer a > 1, ap = a (mod p). That is, if we raise a to the pth power and divide by p, the remainder is a. Some (but not very many) non-prime values of p, known as base-a ps…

Round Numbers Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 8590   Accepted: 3003 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors',…

Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo', and a host of other names) in order to make arbitrary decisions such as who gets…

A number whose only prime factors are 2,3,5 or 7 is called a humble number. The sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 24, 25, 27, ... shows the first 20 humble numbers. Write a program to find and print the nth element i…

传送门 Street Numbers Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 2529   Accepted: 1406 Description A computer programmer lives in a street with houses numbered consecutively (from 1) down one side of the street. Every evening she walks…

Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo', and a host of other names) in order to make arbitrary decisions such as who gets…

一.题目大意 本题要求写出前1500个仅能被2,3,5整除的数. 二.题解 最初的想法是从1开始检验该数是否只能被2,3,5整除,方法是这样的,对于一个数,如果它能被2整除,就除以2,如果它能被3整除,就除以3,如果它能被5整除,就除以5,直到不能被2,3,5整除,看结果是不是1,如果是1就满足条件,否则不满足条件.但是第1500个数大约近10亿,显然是1s内不可以完成的. 然后仔细分析发现:满足条件的数是2^x*3^y*5^z,可以转换为这样的定义,定义一个集合,该集合中有元素1,如果x在集合…

一.Description In 1949 the Indian mathematician D.R. Kaprekar discovered a class of numbers called self-numbers. For any positive integer n, define d(n) to be n plus the sum of the digits of n. (The d stands for digitadition, a term coined by Kaprekar…

http://www.51nod.com/onlineJudge/questionCode.html#!problemId=1010 http://poj.org/problem?id=1338 首先poj这题要找出第n个丑数,想到要打表,因为每一个丑数都是由前一个丑数*2或者*3或者*5得到,每次取3种结果种较小的那一个放入数组中. 打表的时候要注意保持数组有序. #include <iostream> #include <cstdio> #include <cmath&g…