Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note:Try to come up as many solutions as you can, there are at least 3 different ways to solve this pro…

Given an array, rotate the array to the right by k steps, where k is non-negative. Example 1: Input: [1,2,3,4,5,6,7] and k = 3 Output: [5,6,7,1,2,3,4] Explanation: rotate 1 steps to the right: [7,1,2,3,4,5,6] rotate 2 steps to the right: [6,7,1,2,3,4…

题意:给定一个数组,将该数组的后k位移动到前n-k位之前.(本题在编程珠玑中第二章有讲) 思路: 方法一:将后K位用vector容器装起来,再移动前n-k位到后面,再将容器内k位插到前面. class Solution { public: void rotate(int nums[], int n, int k) { || k==n ) return; k %= n; vector<int> cha; cha.reserve(k); int i; for(i=n-k; i<n; i++)…

Given an array, rotate the array to the right by k steps, where k is non-negative. 给定一个数组,并且给定一个非负数的值k, 把数组往右旋转k步,要求不返回新的数组,直接改变原数组 例子1: 给定数组: [1,2,3,4,5,6,7] 给定 k = 3 输出数组: [5,6,7,1,2,3,4] 解析: 往右旋转1步: [7,1,2,3,4,5,6] 往右旋转2步: [6,7,1,2,3,4,5] 往右旋转3步:…

class Solution {public: void rotate(vector<int>& nums, int k) { int n=nums.size(); int i=0; //------------------- //解法一  会超时 //-------------------- k=k%n; while(i<k){ int temp=nums[n-1]; for(int j=n-1;j>0;j--){ nums[j]=nums[j-1]; } nums[0]…

将包含 n 个元素的数组向右旋转 k 步.例如,如果  n = 7 ,  k = 3,给定数组  [1,2,3,4,5,6,7]  ,向右旋转后的结果为 [5,6,7,1,2,3,4].注意:尽可能找到更多的解决方案,这里最少有三种不同的方法解决这个问题. 详见:https://leetcode.com/problems/rotate-array/description/ Java实现: 方法一: class Solution { public void rotate(int[] nums, i…

Given a list, rotate the list to the right by k places, where k is non-negative. For example:Given 1->2->3->4->5->NULL and k = 2,return 4->5->1->2->3->NULL. 这道旋转链表的题和之前那道Rotate Array 旋转数组 很类似,但是比那道要难一些,因为链表的值不能通过下表来访问,只能一个一个的…

STL中的list就是一双向链表,可高效地进行插入删除元素. List 是 C++标准程式库 中的一个 类 ,可以简单视之为双向 连结串行 ,以线性列的方式管理物件集合.list 的特色是在集合的任何位置增加或删除元素都很快,但是不支持随机存取.list 是 C++标准程式库 提供的众多容器(container)之一,除此之外还有 vector .set.map.…等等.list 以模板方式实现(即泛型),可以处理任意型别的变量,包括使用者自定义的资料型态,例如:它可以是一个放置整数(int)型…

Rotate Array 本题目收获: 题目: Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. 思路: 我的思路:新建一个数组存放旋转后的内容,但是怎么把原数组的内容存放在数组中,不清楚. leetcode/discuss思路: 思路一:新建数组,复制原…

问题描述: Given an array, rotate the array to the right by k steps, where k is non-negative. Example 1: Input: [1,2,3,4,5,6,7] and k = 3 Output: [5,6,7,1,2,3,4] Explanation: rotate 1 steps to the right: [7,1,2,3,4,5,6] rotate 2 steps to the right: [6,7,1…

寻找旋转数组中的最小值 假设按照升序排序的数组在预先未知的某个点上进行了旋转. ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] ). 请找出其中最小的元素. 你可以假设数组中不存在重复元素. 示例 1: 输入: [3,4,5,1,2] 输出: 1 示例 2: 输入: [4,5,6,7,0,1,2] 输出: 0 思路 这个题是<剑指offer>中非常经典的一道题. 对于没有重复数字的数组, 旋转之后的数组可以看做两个升序数组,而且前面数组的元素都比后面数…

公众号:爱写bug(ID:icodebugs) 给定一个数组,将数组中的元素向右移动 k 个位置,其中 k 是非负数. Given an array, rotate the array to the right by k steps, where k is non-negative. 示例 1: 输入: [1,2,3,4,5,6,7] 和 k = 3 输出: [5,6,7,1,2,3,4] 解释: 向右旋转 1 步: [7,1,2,3,4,5,6] 向右旋转 2 步: [6,7,1,2,3,4,…

O(n)的算法就不说了,这题主要考查的是 O(logn)的算法. 有序数组easy想到使用二分查找解决.这题就是在二分基础上做一些调整.数组仅仅有一次翻转,能够知道原有序递增数组被分成两部分,这俩部分都是有序递增的(这题仅仅须要考虑有序数组的递增情况). 假如翻转后的数组以第 x 个结点分为两部分 A[0..x] 和 A[x+1..n].则 A[0..x] 这一段是有序递增的, A[x+1..n] 这一段也是有序递增的. 而且由于原数组是有序递增的,A[0..x] 中全部数都会大于 A[x+1.…

Given a sorted positive integer array nums and an integer n, add/patch elements to the array such that any number in range [1, n] inclusive can be formed by the sum of some elements in the array. Return the minimum number of patches required. Example…

Given a binary array, find the maximum length of a contiguous subarray with equal number of 0 and 1. Example 1: Input: [0,1] Output: 2 Explanation: [0, 1] is the longest contiguous subarray with equal number of 0 and 1. Example 2: Input: [0,1,0] Outp…

假设一个按照升序排列的有序数组从某未知的位置旋转.(比如 0 1 2 4 5 6 7 可能变成 4 5 6 7 0 1 2).找到其中最小的元素.你可以假设数组中不存在重复的元素.详见:https://leetcode.com/problems/find-minimum-in-rotated-sorted-array/description/ Java实现: class Solution { public int findMin(int[] nums) { int low=0; int high…

A zero-indexed array A of length N contains all integers from 0 to N-1. Find and return the longest length of set S, where S[i] = {A[i], A[A[i]], A[A[A[i]]], ... } subjected to the rule below. Suppose the first element in S starts with the selection…

题目描述: Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., might become ). Find the minimum element. You may assume no duplicate exists in the array. 这道题<剑指offer>上有原题,直接上代码 solution: int findMin(vector<int>& nu…

Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k) = 0 * Bk[0] + 1 * Bk[1] + ... + (n-1) * Bk[n-1]. Ca…

in place交换 如果是k步,那么就是把后面k个放到前面了嘛. 我们先把整个数组reverse,然后把前面的reverse回来,再把后面的reverse回来 对于AB我们要通过reverse操作得到BA 那么先把AB reverse一次得到reverse(B)reverse(A) 然后再把reverse(B),reverse(A)分别reverse一次就得到了BA class Solution { public: void rotate(int nums[], int n, int k) {…

Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ways to solve this pr…

You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Note:You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the…

一句话思路:反正只是寻找一个最小区间,断开也能二分.根据m第一次的落点,来分情况讨论. 一刷报错: 结构上有根本性错误:应该是while里面包括if,不然会把代码重复写两遍,不好. //situation1 if (nums[mid] > nums[start]) { while (start + 1 < mid) { mid = start + (end - start) / 2; if (nums[mid] == target) { return mid; } else if (nums[…

You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up:Could you do this in-place? 方法一:常规思路: 将图片分为 行数/2 层,然后一层层进行旋转,由外到里.在这个过程中,比较关键的是下标的处理.可从n=3时得出一定的规律.每次旋转时,分析替换的元素对的下标和行.列的关系.如 i=0.j=0时 1:[0]…

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom…

## 假设升序,import random def find(y):    l,m=len(y),0    while l>1:        n=int(l/2)        if y[0]<y[n]:            y=y[n:]        else:            y=y[:n]            m+=l-n        l=len(y)           return m stop=1000x=[x for x in range(0,stop)]ans=…

Given a linked list, rotate the list to the right by k places, where k is non-negative. Example 1: Input: 1->2->3->4->5->NULL, k = 2 Output: 4->5->1->2->3->NULL Explanation: rotate 1 steps to the right: 5->1->2->3-&g…

​给定一个链表,旋转链表,将链表每个节点向右移动 k 个位置,其中 k 是非负数. Given a linked list, rotate the list to the right by k places, where k is non-negative. 示例 1: 输入: 1->2->3->4->5->NULL, k = 2 输出: 4->5->1->2->3->NULL 解释: 向右旋转 1 步: 5->1->2->3-…

Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note:Try to come up as many solutions as you can, there are at least 3 different ways to solve this pro…

189. 旋转数组 LeetCode189. Rotate Array 题目描述 给定一个数组,将数组中的元素向右移动 k 个位置,其中 k 是非负数. 示例 1: 输入: [1,2,3,4,5,6,7] 和 k = 3 输出: [5,6,7,1,2,3,4] 解释: 向右旋转 1 步: [7,1,2,3,4,5,6] 向右旋转 2 步: [6,7,1,2,3,4,5] 向右旋转 3 步: [5,6,7,1,2,3,4] 示例 2: 输入: [-1,-100,3,99] 和 k = 2 输出:…