poj2506 Tiling】的更多相关文章

Tiling Description In how many ways can you tile a 2xn rectangle by 2x1 or 2x2 tiles? Here is a sample tiling of a 2x17 rectangle.  Input Input is a sequence of lines, each line containing an integer number 0 <= n <= 250. Output For each line of inp…
http://poj.org/problem?id=2506 题目大意:用多少种方法可以用2*1或2*2瓦片来铺一个2*n的矩形? 这是一个2*17长方形的样品. 输入是一行行的序列,每一行包含一个整数0 <= n <= 250.对于每一行输入,在单独的行中输出一个整数,给出一个2 * n矩形的可能摆放方式数. 也就是说给一个2*n的棋盘,用三种方块(2*2,1*2,2*1)将其铺满,求有多少种可能性,通过给出的案例可以发现,输出的结果很大long long类型也存不下,所以要运用大整数的加法…
http://poj.org/problem?id=2506 #include <iostream> #include <stdio.h> #include <string.h> #include <stdlib.h> using namespace std; ][]; int main() { int n,i,j; memset(a,,sizeof(a)); a[][]=; a[][]=; a[][]=; ; i<=; i++) { ; j<=…
Texture tiling and swizzling 原帖地址:http://fgiesen.wordpress.com If you’re working with images in your program, you’re most likely using a regular 2D array layout to store image data. Which is to say, it’s basically a 1D array of width * height pixels,…
图文详解Unity3D中Material的Tiling和Offset是怎么回事 Tiling和Offset概述 Tiling表示UV坐标的缩放倍数,Offset表示UV坐标的起始位置. 这样说当然是隔靴搔痒. 下面用*.3ds文件作为模型,介绍Tiling和Offset到底是怎么回事. 3DS格式解析 比如我有这样一个tank_player.3ds模型.右侧的'select'处的图片就是贴图. *.3ds文件最基本的内容包括顶点列表Vertices.贴图坐标列表UVs.面列表Faces.其中Ve…
Quad Tiling Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 3740 Accepted: 1684 Description Tired of the Tri Tiling game finally, Michael turns to a more challengeable game, Quad Tiling: In how many ways can you tile a 4 × N (1 ≤ N ≤ 109)…
Tri Tiling Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1631    Accepted Submission(s): 928 Problem DescriptionIn how many ways can you tile a 3xn rectangle with 2x1 dominoes? Here is a sampl…
Tiling Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8091   Accepted: 3918 Description In how many ways can you tile a 2xn rectangle by 2x1 or 2x2 tiles? Here is a sample tiling of a 2x17 rectangle. Input Input is a sequence of lines,…
Description Michael The Kid receives an interesting game set from his grandparent as his birthday gift. Inside the game set box, there are n tiling blocks and each block has a form as follows: Each tiling block is associated with two parameters (l,m)…
  Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status #include<cstdio> using namespace std; int f(int n) { ) ; ) ; else *f(n-)-f(n-); } int main() { int n; &&n!=-) ==) printf("%d\n",f(n));…