【hdu1003 1024 Max Sum&Max Sum Plus Plus【基础dp】】的更多相关文章

hdu1003 1024 Max Sum&Max Sum Plus Plus【基础dp】

转载请注明出处,谢谢:http://www.cnblogs.com/KirisameMarisa/p/4302208.html   ---by 墨染之樱花 dp是竞赛中常见的问题,也是我的弱项orz,更要多加练习.看到邝巨巨的dp专题练习第一道是Max Sum Plus Plus,所以我顺便把之前做过的hdu1003 Max Sum拿出来又做了一遍 HDU 1003 Max Sum 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1003 题目描述:…

Max Sum Plus Plus HDU - 1024 基础dp 二维变一维的过程，有点难想

/* dp[i][j]=max(dp[i][j-1]+a[j],max(dp[i-1][k])+a[j]) (0<k<j) dp[i][j-1]+a[j]表示的是前j-1分成i组,第j个必须放在前一组里面. max( dp[i-1][k] ) + a[j] )表示的前(0<k<j)分成i-1组,第j个单独分成一组. */ #include <iostream> #include <cstdio> #include <cstring> #inclu…

HDU 1003 Max Sum && HDU 1231 最大连续子序列 (DP)

Max Sum Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 154155    Accepted Submission(s): 35958 Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max su…

POJ 3415 Max Sum of Max-K-sub-sequence （线段树+dp思想）

Max Sum of Max-K-sub-sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5084    Accepted Submission(s): 1842 Problem Description Given a circle sequence A[1],A[2],A[3]......A[n]. Circle s…

6.组函数（avg(),sum(),max(),min(),count()）、多行函数，分组数据（group by，求各部门的平均工资），分组过滤(having和where)，sql优化

 1组函数 avg(),sum(),max(),min(),count()案例: selectavg(sal),sum(sal),max(sal),min(sal),count(sal) from emp / 截图: watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvdG90b3R1enVvcXVhbg==/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEas…

A - Max Sum Plus Plus （好题&&dp）

A - Max Sum Plus Plus  I think you have got an AC in Ignatius.L's "Max Sum" problem. To be a brave ACMer, we always challenge ourselves to more difficult problems. Now you are faced with a more difficult problem. Given a consecutive number seque…

hdu 3415 Max Sum of Max-K-sub-sequence 单调队列优化DP

题目链接: https://www.cnblogs.com/Draymonder/p/9536681.html 同上一篇文章,只是 需要记录最大值的开始和结束的位置 #include <iostream> #include <string.h> #include <cmath> using namespace std; ; int n,k; ],sum[N<<]; ]; int main () { freopen("in.txt",&qu…

poj 1050 To the Max(最大子矩阵之和，基础DP题)

To the Max Time Limit: 1000MSMemory Limit: 10000K Total Submissions: 38573Accepted: 20350 Description Given a two-dimensional array of positive and negative integers, a sub-rectangle is any contiguous sub-array of size 1*1 or greater located within t…

URAL 1146 Maximum Sum（最大子矩阵的和 DP）

Maximum Sum 大意:给你一个n*n的矩阵,求最大的子矩阵的和是多少. 思路:最開始我想的是预处理矩阵,遍历子矩阵的端点,发现复杂度是O(n^4).就不知道该怎么办了.问了一下,是压缩矩阵,转换成最大字段和的问题. 压缩行或者列都是能够的. int n, m, x, y, T, t; int Map[1010][1010]; int main() { while(~scanf("%d", &n)) { memset(Map, 0, sizeof(Map)); for(i…

hdu 5586 Sum 基础dp

Sum Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description There is a number sequence A1,A2....An,you can select a interval [l,r] or not,all the numbers Ai(l≤i≤r) will become f(Ai).f(x)=(1890x+143)mod1…