[题目描述] There are n coins with different value in a line. Two players take turns to take one or two coins from left side until there are no more coins left. The player who take the coins with the most value wins. Could you please decide the first play…
变型:如果是最后拿走所有石子那个人输,则f[0] = true 394. Coins in a Line dp[n]表示n个石子,先手的人,是必胜还是必输.拿1个石子,2个石子之后都是必胜,则当前必败:拿1个石子,2个石子之后都是必败,则当前必胜:如果拿1个石子,2个石子之后有必败,则当前必胜. class Solution { public: /** * @param n: An integer * @return: A boolean which equals to true if the…
There are n coins with different value in a line. Two players take turns to take one or two coins from left side until there are no more coins left. The player who take the coins with the most value wins. Could you please decide the first player will…
There are n coins with different value in a line. Two players take turns to take one or two coins from left side until there are no more coins left. The player who take the coins with the most value wins. Could you please decide the first player will…
最后更新 这个题做得也不好,dp[n]尝试写了几下,不太对. 应该是类似于gem theory的题. 当只有1个硬币剩下的时候直接拿走,不BB. 剩俩的时候也都拿了.. dp[n]表示剩下多少个硬币. 轮到我们拿第i个硬币的时候,有2种情况: 我们拿这个 i . 对手选择拿1个,就是第i+1个,然后第i+ 2轮到我们,我们再决定. 对手选择拿2个,i+1和i+2, 然后i+3轮到我们. 我们拿这个i,再拿下一个i+1. 对手选择拿1个,就是第i+2, 然后i+3轮到我们. 对手选择拿2个,i+2…
Nice one to learn: DP + Game Theoryhttps://lefttree.gitbooks.io/leetcode/content/dynamicProgramming2/coinsInLine2.html In game theory, we assume the other player always take optimal step too. Combining with DP, we put this assumption together with ea…
[题目描述] For an array, we can build a Segment Tree for it, each node stores an extra attribute count to denote the number of elements in the the array which value is between interval start and end. (The array may not fully filled by elements) Design a…
[题目描述] You have two numbers represented by a linked list, where each node contains a single digit. The digits are stored in forward order, such that the 1's digit is at the head of the list. Write a function that adds the two numbers and returns the…
Coins in a Line I There are n coins in a line. Two players take turns to take one or two coins from right side until there are no more coins left. The player who take the last coin wins. Could you please decide the first play will win or lose? Exampl…
刷 July-31-2019 换成只能从左边或者右边拿.这个确实和Coins in a Line II有关系. 和上面思路一致,也是MinMax思路,只不过是从左边和右边选,相应对方也是这样. public class Solution { public boolean firstWillWin(int[] values) { // write your code here if (values == null || values.length == 0) return false; if (v…