LeetCode Permutaions II】的更多相关文章

LeetCode解题之Permutaions II 原题 输出一个有反复数字的数组的全排列. 注意点: 反复数字的可能导致反复的排列 样例: 输入: nums = [1, 2, 1] 输出: [[1, 1, 2], [1, 2, 1], [2, 1, 1]] 解题思路 这道题是上一题 Permutations 的加强版,如今要考虑反复的数字了,採用了偷懒的办法,先把数组排序.遍历时直接无视反复的数字,在原来的基础上仅仅要加入两行代码. AC源代码 class Solution(object):…
作者:jostree  转载请注明出处 http://www.cnblogs.com/jostree/p/4051169.html 题目链接:leetcode Permutations II 无重全排列 题目要求对有重复的数组进行无重全排列.为了保证不重复,类似于全排列算法使用dfs,将第一个数字与后面第一次出现的数字交换即可.例如对于序列1,1,2,2 有如下过程: ,1,2,2 -> 1,,2,2 -> 1,1,,2 -> 1,1,2,  -> 1,2,,2 -> 1,2…
Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example,[1,1,2] have the following unique permutations:[1,1,2], [1,2,1], and [2,1,1]. 这道题是之前那道Permutations 全排列的延伸,由于输入数组有可能出现重复数字,如果按照之前的算法运算,会有…
Given four lists A, B, C, D of integer values, compute how many tuples (i, j, k, l) there are such that A[i] + B[j] + C[k] + D[l] is zero. To make problem a bit easier, all A, B, C, D have same length of N where 0 ≤ N ≤ 500. All integers are in the r…
Follow up for H-Index: What if the citations array is sorted in ascending order? Could you optimize your algorithm? Hint: Expected runtime complexity is in O(log n) and the input is sorted. 这题是之前那道H-Index 求H指数的拓展,输入数组是有序的,让我们在O(log n)的时间内完成计算,看到这个时间复…
Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a solution is:…
Follow up for N-Queens problem. Now, instead outputting board configurations, return the total number of distinct solutions. 这道题是之前那道N-Queens N皇后问题 的延伸,说是延伸其实我觉得两者顺序应该颠倒一样,上一道题比这道题还要稍稍复杂一些,两者本质上没有啥区别,都是要用回溯法Backtracking来解,如果理解了之前那道题的思路,此题只要做很小的改动即可,不…
原题链接在这里:https://leetcode.com/problems/h-index-ii/ 题目: Follow up for H-Index: What if the citations array is sorted in ascending order? Could you optimize your algorithm? 题解: 与H-Index类似.已经排好序,直接二分法查找即可. Time Complexity: O(logn). Space: O(1). AC Java:…
题意: 给一个集合,有n个可能相同的元素,求出所有的子集(包括空集,但是不能重复). 思路: 看这个就差不多了.LEETCODE SUBSETS (DFS) class Solution { public: vector<vector<int>> subsets(vector<int>& nums) { sort(nums.begin(),nums.end()); DFS(,nums,tmp); ans.push_back(vector<int>()…
Follow up for N-Queens problem. Now, instead outputting board configurations, return the total number of distinct solutions. 原题链接:https://oj.leetcode.com/problems/n-queens-ii/ 题目:求有多少个独立的解决方式. 与上题一致,仅仅要每次成功后记录一下次数就可以. package leetcode; import java.ut…
原题地址:https://oj.leetcode.com/problems/permutations-ii/ 题意: Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example,[1,1,2] have the following unique permutations:[1,1,2], [1,2,1], and [2,1,1].…
原题地址:https://oj.leetcode.com/problems/subsets-ii/ 题意: Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicat…
原题地址:https://oj.leetcode.com/problems/n-queens-ii/ 题意:和N-Queens这道题其实是一样的,只不过这次要求返回的时N皇后的解的个数的问题. 解题思路:上道题使用了递归回溯的解法,这道题我们可以使用非递归回溯来解决,因为如果使用递归回溯来解决,那么代码和上道题几乎一样.在非递归的编程中,比较有技巧性的是如何来进行回溯. 代码: class Solution: # @return an integer def totalNQueens(self,…
N-Queens II (LEVEL 4 难度级别,最高级5) Follow up for N-Queens problem.…
Permutations II Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example,[1,1,2] have the following unique permutations:[1,1,2], [1,2,1], and [2,1,1]. SOLUTION 1: 还是经典的递归模板.需要处理的情况是:我们先把Num排序,然…
151 Reverse Words in a String class Solution { public: void reverseWords(string &s) { string result; ; i >= ;) { && s[i] == ' ') { i--; } ) { break; } string word; && s[i] != ' ') { word += s[i]; i--; } reverse(word.begin(), word.en…
Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example,[1,1,2] have the following unique permutations:[1,1,2], [1,2,1], and [2,1,1]. 解题思路: Permutations 那题输入是不包含重复元素的,故生成的排列都是不同的,II中输入元素可能相同 因…
https://oj.leetcode.com/problems/n-queens-ii/ N皇后问题,计算解的个数 class Solution { public: int totalNQueens(int n) { ) ; vector<); ; placeQueen(, n, ans, places); return ans; } // col and lines bool valid(int i, int j, vector<int> &places) { ; p<…
https://oj.leetcode.com/problems/subsets-ii/ 求一个集合的子集,但集合中有重复元素. 求子集的问题,对应着数的二进制,相当于对二进制的一个遍历. #include <iostream> #include <vector> #include <algorithm> using namespace std; class Solution { public: vector<vector<int> > subs…
Follow up for N-Queens problem. Now, instead outputting board configurations, return the total number of distinct solutions. class Solution { public: int totalNQueens(int n) { vector<); ; i < n; ++ i) queen[i] = i; ; do{ bool flag = false; ; i <…
Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a solution is:…
Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example,[1,1,2] have the following unique permutations:[1,1,2], [1,2,1], and [2,1,1]. Solution: public class Solution { public List<List<Intege…
Given four lists A, B, C, D of integer values, compute how many tuples (i, j, k, l) there are such that A[i] + B[j] + C[k] + D[l] is zero. To make problem a bit easier, all A, B, C, D have same length of N where 0 ≤ N ≤ 500. All integers are in the r…
题意: 给出n个元素(可能有重复的),请产生出所有的全排列. 思路: 同版本1的有点不同,这次有可能含有重复的元素,很容易就TLE,节省时间才是关键点. 如果将一个序列中两个相同的元素交换,这个序列是仍然没有发生改变的,这也是省时间的关键点.考虑第i个位置可取的元素是nums[i-1,nums.size()-1],那么交换的时候不必要将与num[i-1]相同的元素交换到第i位了.这可以预先通过排一次序解决.排序后变成多段相同的元素接在一起,而通常只会将每段的第一个元素被换到第i个位置,考虑每段的…
Description: Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. How many unique paths would there be? An obstacle and empty space is marked as 1 and 0 respectively in the grid. 分析:这道题目跟之前的UniquePath基本都是一样的,只是在格子…
class Solution { public: vector<vector<int> > combinationSum2(vector<int> &num, int target) { sort(num.begin(), num.end()); vector<vector<int> > tmp; vector<int> sel; dfs(num, , target, sel, tmp); return tmp; } void…
题目 Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If S = [1,2,2], a solution…
Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example,[1,1,2]have the following unique permutations:[1,1,2],[1,2,1], and[2,1,1]. 题意:当数列中有重复数字时,求其全排列. 思路:和permutation一样.以[1,1,2]为例,以第一个1为开始,得到…
Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S =[1,2,2], a solution is: […
Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example,[1,1,2] have the following unique permutations:[1,1,2], [1,2,1], and [2,1,1]. Show Tags Backtracking       这个就是输入一个数组,可能有重复,输出全部的排列.    …