Time Limit: 10 second Memory Limit: 2 MB 问题描述 给出一张地图,这张地图被分为n*m(n,m<=100)个方块,任何一个方块不是平地就是高山.平地可以通过,高山则不能.现在你处在地图的(x1,y1)这块平地,问:你至少需要拐几个弯才能到达目的地(x2,y2)?你只能沿着水平和垂直方向的平地上行进,拐弯次数就等于行进方向的改变(从水平垂直或从垂直到水平)次数 Input 第1行: n m 第1至n+1行:整个地图地形描述(0:空地:1:高山), 第2行地形
题目描述 Consider an N x N (1 <= N <= 100) square field composed of 1 by 1 tiles. Some of these tiles are impassible by cows and are marked with an 'x' in this 5 by 5 field that is challenging to navigate: . . B x . . x x A . . . . x . . x . . . . . x .
题意翻译 题目大意: 给定一个n∗m的矩阵,每次你可以选择前进一格或转弯(90度),求在不出这个矩阵的情况下遍历全部格点所需最少转弯次数.有多组数据 输入格式: 第一行一个整数k,表示数据组数 以下k行,每行两个整数n,m,表示矩阵大小 输出格式: 输出一个整数,即最少转弯次数 感谢@守望 提供翻译 题目描述 Mirko wants to buy land on which he will build a house for his family. So far, he’s seen K pie
题目描述 Consider an N x N (1 <= N <= 100) square field composed of 1 by 1 tiles. Some of these tiles are impassible by cows and are marked with an 'x' in this 5 by 5 field that is challenging to navigate: . . B x . . x x A . . . . x . . x . . . . . x .
题目描述 Consider an N x N (1 <= N <= 100) square field composed of 1 by 1 tiles. Some of these tiles are impassible by cows and are marked with an 'x' in this 5 by 5 field that is challenging to navigate: . . B x . . x x A . . . . x . . x . . . . . x .
P1649 [USACO07OCT]障碍路线Obstacle Course 题目描述 Consider an N x N (1 <= N <= 100) square field composed of 1 by 1 tiles. Some of these tiles are impassible by cows and are marked with an 'x' in this 5 by 5 field that is challenging to navigate: . . B x .
题目Description考虑一个 N x N (1 <= N <= 100)的有1个个方格组成的正方形牧场.有些方格是奶牛们不能踏上的,它们被标记为了’x’.例如下图: . . B x .. x x A .. . . x .. x . . .. . x . . 贝茜发现自己恰好在点A出,她想去B处的盐块添盐.缓慢而且笨拙的动物,比如奶牛,十分讨厌转弯.尽管如此当然在必要的时候她们还是会转弯的.对于一个给定的牧场,请你计算从A到B最少的转弯次数.开始的时候贝茜可以使面对任意一个方向.贝茜知道她
题目描述 Consider an N x N (1 <= N <= 100) square field composed of 1 by 1 tiles. Some of these tiles are impassible by cows and are marked with an 'x' in this 5 by 5 field that is challenging to navigate: . . B x . . x x A . . . . x . . x . . . . . x .
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1326 题目大意: 给n堵墙,每个墙的高度不同,求最少移动多少块转使得墙的的高度相同. 解题思路: 找到平均墙的高度(即最后墙的高度),遍历所有墙,如果小于平均墙,则用平均墙减去高度即是要移动的高度,统计所有需要"补"的高度即可.注意输出. AC Code: #include<bits/stdc++.h> using namespace std; int main() { ; w
Machine Schedule Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1150 Description As we all know, machine scheduling is a very classical problem in computer science and has been studied for a very long history.
最少拦截系统 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 35053 Accepted Submission(s): 13880 Problem Description 某国为了防御敌国的导弹袭击,发展出一种导弹拦截系统.但是这种导弹拦截系统有一个缺陷:虽然它的第一发炮弹能够到达任意的高度,但是以后每一发炮弹都不能超过前一发的