1.order by:全局排序 select * from emp order by sal; 2.sort by:对于每个reduce进行排序 set mapreduce.job.reduces=3; insert overwrite local directory '/opt/datas/emp_sort' row format delimited fields terminated by '\t' select * from emp sort by sal; 结果: 3.distribu
hive的排序,分組练习 数据: 添加表和插入数据(数据在Linux本地中) create table if not exists tab1( IP string, SOURCE string, TYPE string ) row format delimited fields terminated by '|' stored as textfile; load data local inpath '/home/data/data1.txt' into table tab1; 1.问题:(top
hive 分组排序,topN 语法格式:row_number() OVER (partition by COL1 order by COL2 desc ) rankpartition by:类似hive的建表,分区的意思:order by :排序,默认是升序,加desc降序:rank:表示别名表示根据COL1分组,在分组内部根据 COL2排序,而此函数计算的值就表示每组内部排序后的顺序编号(组内连续的唯一的) -- 分组排序-- 求某用户日期最大的3天select a.* from( selec
基本排序函数 语法: rank()over([partition by col1] order by col2) dense_rank()over([partition by col1] order by col2) row_number()over([partition by col1] order by col2) 其中[partition by col1]可省略 案例: selectname,score,rank() over(partition by name order by scor
pig可以轻松获取TOP n.书上有例子 hive中比较麻烦,没有直接实现的函数,可以写udf实现.还有个比较简单的实现方法: 用row_number,生成排名序列号.然后外部分组后按这个序列号多虑,样例代码如下 select a.* from( select 品牌,渠道,档期,count/sum/其它() as num row_number() over (partition by 品牌,渠道 order by num desc ) rank from table_name where 品牌,
//五种子句是有严格顺序的: where → group by → having → order by → limit ; //distinct关键字返回唯一不同的值(返回age和id均不相同的记录)hive> select distinct age,id from tea; //hive只支持Union All,不支持Union//hive的Union All相对sql有所不同,要求列的数量相同,并且对应的列名也相同,但不要求类的类型相同(可能是存在隐式转换吧)select name,age
String Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 524288/524288 K (Java/Others) Problem DescriptionBob has a dictionary with N words in it.Now there is a list of words in which the middle part of the word has continuous letters disappeared.
语法:row_number() over (partition by 字段a order by 计算项b desc ) rank --这里rank是别名 partition by:类似hive的建表,分区的意思: order by :排序,默认是升序,加desc降序: 这里按字段a分区,对计算项b进行降序排序 实例: 要取top10品牌,各品牌的top10渠道,各品牌的top10渠道中各渠道的top10档期 1.取top10品牌 select 品牌,count/sum/其它() as num
不分发数据,使用单个reducer ; select * from dw.dw_app where dt>='2016-09-01' and dt <='2016-09-18' order by stime limit ; 包多一层,是用order by select t.* from ( select * from dw.dw_app where dt>='2016-09-01' and dt <='2016-09-18' and app_id=' and msgtype = '