之前去地平线面试的时候被问到了multicycle path的一点问题,其实这个问题我应该知道,看过<Constraining Designs for Synthesis and Timing Analysis A Practical Guide to Synopsys Design Constraints (SDC)>,但当时回答的不好. 0. 多周期路径 一般情况下数据在任意时钟沿发射,在下一个时钟沿被捕获,但是有时设计者需要延迟几个时钟周期data才被捕获,这就是多周期路径. 默认的建
前段时间细节的了解了Jedis的使用,Jedis是redis的java版本的客户端实现.本文做个总结,主要分享如下内容: [pipeline][分布式的id生成器][分布式锁[watch][multi]][redis分布式]好了,一个一个来.一. Pipeline官方的说明是:starts a pipeline,which is a very efficient way to send lots of command and read all the responses when you fin
A non-inclusive cache system includes an external cache and a plurality of on-chip caches each having a set of tags associated therewith, with at least one of the on-chip caches including data which is absent from the external cache. A pipelined snoo
在使用JSONObject.fromObject的时候,出现“There is a cycle in the hierarchy”异常. 意思是出现了死循环,也就是Model之间有循环包含关系: 解决办法: 使用setCycleDetectionStrategy防止自包含 代码: JsonConfig jsonConfig=new JsonConfig(); jsonConfig.setIgnoreDefaultExcludes(false); jsonConfig.se
Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Follow up: Can you solve it without using extra space? 这个求单链表中的环的起始点是之前那个判断单链表中是否有环的延伸,可参见我之前的一篇文章 (http://www.cnblogs.com/grandyang/p/4137187.html). 还是要设
Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using extra space? 这道题是快慢指针的经典应用.只需要设两个指针,一个每次走一步的慢指针和一个每次走两步的快指针,如果链表里有环的话,两个指针最终肯定会相遇.实在是太巧妙了,要是我肯定想不出来.代码如下: C++ 解法: class Solution { public: bool hasCycle
Given a linked list, determine if it has a cycle in it. ExampleGiven -21->10->4->5, tail connects to node index 1, return true Challenge Follow up:Can you solve it without using extra space? LeetCode上的原题,请参见我之前的博客Linked List Cycle. class Solution
题目要求 Linked List Cycle Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using extra space? 如何判断一个单链表中有环? Linked List Cycle II Given a linked list, return the node where the cycle begins. If there is no cycle
Life Cycle of Thread – Understanding Thread States in Java 深入理解java线程生命周期. Understanding Life Cycle of Thread and Thread States are very important when you are working with Threads and programming for multi-threaded environment. 理解线程的生命周期很重要滴,当你在你的程序
Linked List Cycle Given a linked list, determine if it has a cycle in it. Follow up:Can you solve it without using extra space? Linked List Two Pointers ''' Created on Nov 13, 2014 @author: ScottGu<gu.kai.66@gmail.com, 150316990@qq.com> ''' # De
We could take advantage of plist to bypass Trust Relationship so as to extract data from a iDevice. Now it becomes an impossible mission in iOS 10. As you could see the iOS version is iOS 10.0.2. Now my workstation trust this iDevice, and the plist i
python 关于redis的基本操作网上已经很多了,这里主要介绍点个人觉得有意思的内容1.redis的事务操作以及watch 乐观锁:后面描述2.tornado下异步使用redis的方式 redis是单进程单线程模型,本身应对外部请求的是单任务的,也是多线程安全的,这个大家都应该知道的, 所以才会经常有人用redis做计数服务. 首先redis 的事务处理只能使用pipeline:In redis-py MULTI and EXEC can only be used t
在使用JSONObject.fromObject的时候,出现“There is a cycle in the hierarchy”异常. 意思是出现了死循环,也就是Model之间有循环包含关系: 解决办法: 使用setCycleDetectionStrategy防止自包含 代码: JsonConfig jsonConfig = new JsonConfig(); jsonConfig.setCycleDetectionStrategy(CycleDetectionStrategy.LENIENT
Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Note: Do not modify the linked list. Follow up:Can you solve it without using extra space? 参考http://www.cnblogs.com/hiddenfox/p/3408931.html 方法: 第一次相遇时slo
Given a linked list, determine if it has a cycle in it. Follow up:Can you solve it without using extra space? 题意: 判断一个链表是否有环. 解决方案: 双指针,快指针每次走两步,慢指针每次走一步, 如果有环,快指针和慢指针会在环内相遇,fast == slow,这时候返回true. 如果没有环,返回false. /** * Definition for singly-linked li
