代码:

%% ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
%% Output Info about this m-file
fprintf('\n***********************************************************\n');
fprintf(' <DSP using MATLAB> Problem 5.16 \n\n'); banner();
%% ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ % -------------------------------------------------------------------------------
% X(k) and Y(k) both 10-point DFTs of x(n) and y(n) respectively
% X(k) = exp(j0.2pi*k) k=[0:9]
% 1 y(n) = x((n-5))10
% ------------------------------------------------------------------------------- k1 = [0:9];
Xk_DFT = exp(j*0.2*pi*k1);
N1 = length(Xk_DFT); % length is 10 magXk_DFT = abs( [ Xk_DFT ] ); % DFT magnitude
angXk_DFT = angle( [Xk_DFT] )/pi; % DFT angle
realXk_DFT = real(Xk_DFT); imagXk_DFT = imag(Xk_DFT); figure('NumberTitle', 'off', 'Name', 'P5.16.1 DFT(k) of x(n)')
set(gcf,'Color','white');
subplot(2,1,1); stem(k1, magXk_DFT);
%axis([-N/2, N/2, -0.5, 50.5]);
xlabel('k'); ylabel('magnitude(k)');
title('DFT magnitude of x(n), N=10'); grid on;
subplot(2,1,2); stem(k1, angXk_DFT);
%axis([-N/2, N/2, -0.5, 50.5]);
xlabel('k'); ylabel('angle(k)');
title('DFT angle of x(n), N=10'); grid on; [xn] = idft(Xk_DFT, N1);
n = [0 : N1-1]; % +++++++++++++++++++++++++++++++++++++++++++++++++++++++
% 1st way to get y(n)-----circular shifft
% +++++++++++++++++++++++++++++++++++++++++++++++++++++++
m = 5; % shift
yn1 = cirshftt(xn, m, length(xn)); % +++++++++++++++++++++++++++++++++++++++++++++++++++++++
% 2ed way to get y(n)-----IDFT of Y(k)
% +++++++++++++++++++++++++++++++++++++++++++++++++++++++
k1 = [0:9];
Yk_DFT = exp(-j*0.8*pi*k1);
N1 = length(Yk_DFT); % length is 10 magYk_DFT = abs( [ Yk_DFT ] ); % DFT magnitude
angYk_DFT = angle( [Yk_DFT] )/pi; % DFT angle
realYk_DFT = real(Yk_DFT); imagYk_DFT = imag(Yk_DFT); figure('NumberTitle', 'off', 'Name', 'P5.16.1 DFT(k) of y(n)')
set(gcf,'Color','white');
subplot(2,1,1); stem(k1, magYk_DFT);
%axis([-N/2, N/2, -0.5, 50.5]);
xlabel('k'); ylabel('magnitude(k)');
title('DFT magnitude of y(n), N=10'); grid on;
subplot(2,1,2); stem(k1, angYk_DFT);
%axis([-N/2, N/2, -0.5, 50.5]);
xlabel('k'); ylabel('angle(k)');
title('DFT angle of y(n), N=10'); grid on; [yn2] = idft(Yk_DFT, N1);
n = [0 : N1-1]; figure('NumberTitle', 'off', 'Name', 'P5.16.1 x(n) & y(n)')
set(gcf,'Color','white');
subplot(3,1,1); stem(n, xn);
xlabel('n'); ylabel('x(n)');
title('x(n), IDFT of X(k)'); grid on;
subplot(3,1,2); stem(n, yn1);
xlabel('n'); ylabel('y(n)');
title('y(n) by circular shift x((n-5))_N N=10'); grid on;
subplot(3,1,3); stem(n, yn2);
xlabel('n'); ylabel('y(n)');
title('y(n) by IDFT of Y(k)'); grid on;

  运行结果:

代码:

%% ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
%% Output Info about this m-file
fprintf('\n***********************************************************\n');
fprintf(' <DSP using MATLAB> Problem 5.16 \n\n'); banner();
%% ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ % -------------------------------------------------------------------------------
% X(k) and Y(k) both 10-point DFTs of x(n) and y(n) respectively
% X(k) = exp(j0.2pi*k) k=[0:9]
% 3 y(n) = x((3-n))10
% ------------------------------------------------------------------------------- k1 = [0:9];
Xk_DFT = exp(j*0.2*pi*k1);
N1 = length(Xk_DFT); % length is 10 magXk_DFT = abs( [ Xk_DFT ] ); % DFT magnitude
angXk_DFT = angle( [Xk_DFT] )/pi; % DFT angle
realXk_DFT = real(Xk_DFT); imagXk_DFT = imag(Xk_DFT); figure('NumberTitle', 'off', 'Name', 'P5.16.3 DFT(k) of x(n)')
set(gcf,'Color','white');
subplot(2,1,1); stem(k1, magXk_DFT);
%axis([-N/2, N/2, -0.5, 50.5]);
xlabel('k'); ylabel('magnitude(k)');
title('DFT magnitude of x(n), N=10'); grid on;
subplot(2,1,2); stem(k1, angXk_DFT);
%axis([-N/2, N/2, -0.5, 50.5]);
xlabel('k'); ylabel('angle(k)');
title('DFT angle of x(n), N=10'); grid on; [xn] = real(idft(Xk_DFT, N1));
n = [0 : N1-1]; % +++++++++++++++++++++++++++++++++++++++++++++++++++++++
% 1st way to get y(n)-----circular shifft
% +++++++++++++++++++++++++++++++++++++++++++++++++++++++
xn_cirfold = xn(mod(-n,N1)+1);
m = 3; % shift
yn1 = cirshftt(xn_cirfold, m, length(xn)); % +++++++++++++++++++++++++++++++++++++++++++++++++++++++
% 2ed way to get y(n)-----IDFT of Y(k)
% +++++++++++++++++++++++++++++++++++++++++++++++++++++++
k1 = [0:9];
Yk_DFT = exp(j*2*pi*(10-4*k1)/10);
N1 = length(Yk_DFT); % length is 10 magYk_DFT = abs( [ Yk_DFT ] ); % DFT magnitude
angYk_DFT = angle( [Yk_DFT] )/pi; % DFT angle
realYk_DFT = real(Yk_DFT); imagYk_DFT = imag(Yk_DFT); figure('NumberTitle', 'off', 'Name', 'P5.16.3 DFT(k) of y(n)')
set(gcf,'Color','white');
subplot(2,1,1); stem(k1, magYk_DFT);
xlabel('k'); ylabel('magnitude(k)');
title('DFT magnitude of y(n), N=10'); grid on;
subplot(2,1,2); stem(k1, angYk_DFT);
xlabel('k'); ylabel('angle(k)');
title('DFT angle of y(n), N=10'); grid on; [yn2] = real(idft(Yk_DFT, N1));
n = [0 : N1-1]; figure('NumberTitle', 'off', 'Name', 'P5.16.3 x(n) & y(n)')
set(gcf,'Color','white');
subplot(3,1,1); stem(n, xn);
xlabel('n'); ylabel('x(n)');
title('x(n), IDFT of X(k)'); grid on;
subplot(3,1,2); stem(n, yn1);
xlabel('n'); ylabel('y(n)');
title('y(n) by circular shift x((3-n))_N N=10'); grid on;
subplot(3,1,3); stem(n, yn2);
xlabel('n'); ylabel('y(n)');
title('y(n) by IDFT of Y(k)'); grid on;

  运行结果:

X(k)的图见第1小题,这里不附了。

《DSP using MATLAB》Problem5.16的更多相关文章

  1. 《DSP using MATLAB》Problem5.33

    代码: %% ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ %% Output In ...

  2. 《DSP using MATLAB》Problem5.23

    代码: %% ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ %% O ...

  3. 《DSP using MATLAB》示例Example7.25

    今天清明放假的第二天,早晨出去吃饭时天气有些阴,十点多开始“清明时节雨纷纷”了. 母亲远在他乡看孙子,挺劳累的.父亲照顾生病的爷爷…… 我打算今天把<DSP using MATLAB>第7 ...

  4. 《DSP using MATLAB》Problem 7.16

    使用一种固定窗函数法设计带通滤波器. 代码: %% ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ ...

  5. 《DSP using MATLAB》Problem 4.16

    代码: %% ------------------------------------------------------------------------ %% Output Info about ...

  6. 《DSP using MATLAB》Problem 2.16

    先由脉冲响应序列h(n)得到差分方程系数,过程如下: 代码: %% ------------------------------------------------------------------ ...

  7. 《DSP using MATLAB》 示例 Example 9.16

    代码: %% ------------------------------------------------------------------------ %% Output Info about ...

  8. 《DSP using MATLAB》示例Example 8.16

    %% ------------------------------------------------------------------------ %% Output Info about thi ...

  9. 《DSP using MATLAB》Problem 7.26

    注意:高通的线性相位FIR滤波器,不能是第2类,所以其长度必须为奇数.这里取M=31,过渡带里采样值抄书上的. 代码: %% +++++++++++++++++++++++++++++++++++++ ...

随机推荐

  1. 【原创】QString 函数 replace()indexOf()、 lastindexOf()

    1.替换函数 示例: QString x = "Say yes!"; QString y = "no"; x.replace(, , y); // x == & ...

  2. [leetcode121]股票买卖 Best Time to Buy and Sell Kadane算法

    [题目] Say you have an array for which the ith element is the price of a given stock on day i. If you ...

  3. CSS特性

    css的特性 css具有两大特性:继承性和层叠性 1.继承性 指的是子元素继承父元素的样式,但没有所有的样式都可以继承(那样就太可怕了) 所以具有继承性的属性主要分为三大类 a.文本属性 font-s ...

  4. Linux如何从零开始搭建rsync+serync服务器(centOS6)

    一.为什么要用Rsync+sersync架构? 1.sersync是基于Inotify开发的,类似于Inotify-tools的工具 2.sersync可以记录下被监听目录中发生变化的(包括增加.删除 ...

  5. L1-055 谁是赢家

    某电视台的娱乐节目有个表演评审环节,每次安排两位艺人表演,他们的胜负由观众投票和 3 名评委投票两部分共同决定.规则为:如果一位艺人的观众票数高,且得到至少 1 名评委的认可,该艺人就胜出:或艺人的观 ...

  6. matlab中的reshape快速理解,卷积和乘积之间的转换

    reshape: THe convertion between convolution and multiplication:

  7. L316 波音737Max 危机

    Boeing Scrambles To Restore Faith In Its 737 MAX Airplane After Crashes In the wake of two deadly cr ...

  8. C#窗体布局技巧

    using System;using System.Collections.Generic;using System.ComponentModel;using System.Data;using Sy ...

  9. socketserver 和 事件Event

    socketserver 处理socket服务端 # 服务端TCP: import socketserver from threading import current_thread # fork l ...

  10. 再谈kbmMW垃圾回收

    很早就写了关于kbmMW Server如何实现的垃圾回收,但最近一段时间还是为此遇到问题,实现的Server不能稳定运行,发生问题后不响应客户端的查询请求,在客户端得到服务端返回地址错误信息,只能重启 ...