poj 1265 Area(Pick定理)
| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 5666 | Accepted: 2533 |
Description

Figure 1: Example area.
You are hired to write a program that calculates the area occupied
by the new facility from the movements of a robot along its walls. You
can assume that this area is a polygon with corners on a rectangular
grid. However, your boss insists that you use a formula he is so proud
to have found somewhere. The formula relates the number I of grid points
inside the polygon, the number E of grid points on the edges, and the
total area A of the polygon. Unfortunately, you have lost the sheet on
which he had written down that simple formula for you, so your first
task is to find the formula yourself.
Input
For each scenario, you are given the number m, 3 <= m < 100,
of movements of the robot in the first line. The following m lines
contain pairs 揹x dy�of integers, separated by a single blank, satisfying
.-100 <= dx, dy <= 100 and (dx, dy) != (0, 0). Such a pair means
that the robot moves on to a grid point dx units to the right and dy
units upwards on the grid (with respect to the current position). You
can assume that the curve along which the robot moves is closed and that
it does not intersect or even touch itself except for the start and end
points. The robot moves anti-clockwise around the building, so the area
to be calculated lies to the left of the curve. It is known in advance
that the whole polygon would fit into a square on the grid with a side
length of 100 units.
Output
output for every scenario begins with a line containing 揝cenario #i:�
where i is the number of the scenario starting at 1. Then print a single
line containing I, E, and A, the area A rounded to one digit after the
decimal point. Separate the three numbers by two single blanks.
Terminate the output for the scenario with a blank line.
Sample Input
2
4
1 0
0 1
-1 0
0 -1
7
5 0
1 3
-2 2
-1 0
0 -3
-3 1
0 -3
Sample Output
Scenario #1:
0 4 1.0 Scenario #2:
12 16 19.0
Source
【思路】
Pick定理
同上题。
【代码】
#include<cstdio>
using namespace std; struct Pt {
int x,y;
Pt(int x=,int y=) :x(x),y(y){};
};
Pt p[];
typedef Pt vec;
vec operator - (Pt a,Pt b) { return vec(a.x-b.x,a.y-b.y); } int abs(int x) { return x<? -x:x; }
int gcd(int a,int b) { return b==? a:gcd(b,a%b); }
int cross(Pt a,Pt b) { return a.x*b.y-a.y*b.x; }
int calc(Pt a,Pt b) { return gcd(abs(a.x-b.x),abs(a.y-b.y)); } int n;
int main() {
int T,kase=;
scanf("%d",&T);
while(T--) {
scanf("%d",&n);
n++;
p[]=Pt(,);
for(int i=;i<n;i++) {
scanf("%d%d",&p[i].x,&p[i].y);
p[i].x+=p[i-].x , p[i].y+=p[i-].y;
}
int S=,b=;
for(int i=;i<n-;i++) {
S += cross(p[i],p[i+]);
b += calc(p[i],p[i+]);
}
b += calc(p[n-],p[])+calc(p[],p[]);
printf("Scenario #%d:\n%d %d %.1f\n\n",++kase,(S-b+)/,b,0.5*S);
}
return ;
}
poj 1265 Area(Pick定理)的更多相关文章
- poj 1265 Area (Pick定理+求面积)
链接:http://poj.org/problem?id=1265 Area Time Limit: 1000MS Memory Limit: 10000K Total Submissions: ...
- POJ 1265 Area (Pick定理 & 多边形面积)
题目链接:POJ 1265 Problem Description Being well known for its highly innovative products, Merck would d ...
- poj 1265 Area(pick定理)
Area Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 4373 Accepted: 1983 Description Bein ...
- [poj 1265]Area[Pick定理][三角剖分]
题意: 给出机器人移动的向量, 计算包围区域的内部整点, 边上整点, 面积. 思路: 面积是用三角剖分, 边上整点与GCD有关, 内部整点套用Pick定理. S = I + E / 2 - 1 I 为 ...
- poj 1265 Area( pick 定理 )
题目:http://poj.org/problem?id=1265 题意:已知机器人行走步数及每一步的坐标 变化量 ,求机器人所走路径围成的多边形的面积.多边形边上和内部的点的数量. 思路:1.以 ...
- Area - POJ 1265(pick定理求格点数+求多边形面积)
题目大意:以原点为起点然后每次增加一个x,y的值,求出来最后在多边形边上的点有多少个,内部的点有多少个,多边形的面积是多少. 分析: 1.以格子点为顶点的线段,覆盖的点的个数为GCD(dx,dy),其 ...
- poj 1265 Area 面积+多边形内点数
Area Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 5861 Accepted: 2612 Description ...
- POJ 1265 Area POJ 2954 Triangle Pick定理
Area Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 5227 Accepted: 2342 Description ...
- POJ 1265 Area (pick定理)
题目大意:已知机器人行走步数及每一步的坐标变化量,求机器人所走路径围成的多边形的面积.多边形边上和内部的点的数量. 思路:叉积求面积,pick定理求点. pick定理:面积=内部点数+边上点数/2-1 ...
随机推荐
- IOS 学习笔记 2015-03-24 OC-API-常用结构体
一 标题 常用结构体 二 API 1 NSRange 表示一个范围 A 实例化 NSRange rg={3,5};//第一参数是起始位置第二个参数是长度 B 实例化 NSRange rg2=NSMak ...
- ubuntu thinkphp pathinfo 404等问题
这个问题 困扰了我一天,由于对nginx的配置文件中的各种变量不懂.配置起来很麻烦,从网上搜索的,感觉合适自己的不多!!! 找啊找啊..终于找一篇!!!! 我的环境: php ubuntu 12.04 ...
- 【实习记】2014-09-26恢复linux下误删的ntfs盘中的文件
情景,ubuntu下把NTFS格式的盘中的“实习记”文件夹彻底删除了,追毁莫及,粗心觉不是一件好的事情. linux下回复ntfs盘下的文件不能用ext3grep,而使用debugfs命令实在 ...
- Nginx 第三方模块-漫谈缘起
http://www.cnblogs.com/yjf512/archive/2012/03/30/2424726.html http://chenxiaoyu.org/2011/10/30/nginx ...
- mysql 事务类型表的用法
mysql关联表(references)的条件:1.两个表必须是 InnoDB表类型2.使用在外键关系的域必须为索引型(Index)3.使用外键关系的域必须与数据类型相似 以下是父表和子表的例子:创建 ...
- CSS三角形广告文字
街上经常碰到一些发各类广告传单的,有一次收到一张房地产广告的传单,顺手留下来,看着里面有些广告挺吸引人,同时也想练练自己css技术,故抽空做了一下. 原图某区域如下: 实现上图效果是需要一些想象力的, ...
- 如何在windows上安装部署设置SVN服务器
1 一.准备工作 1.SVN服务器:解压缩包,可以从官方网站下载最新版本. 2.SVN客户端:TortoiseSVN,即常说的小乌龟,是一个客户端程序,用来与服务器端通讯. 2 二.安装服务器和客 ...
- 转载的在DOS下操作mysql
转载原文地址:http://www.server110.com/mysql/201309/1070.html 一.连接MYSQL. 格式: mysql -h主机地址 -u用户名 -p用户密码 1.例1 ...
- xcode 必用插件二
本文大致整理了自己用过的一些插件的使用感想(就是好不好用). 在那之前先简单贴两条插件须知,知道的可以忽略. 1.Alcatraz 类似于管理第三方库的cocoapods,管理插件也有个Alcatra ...
- java 堆与栈的区别
1. 堆与栈的区别? 1-1. 数据存放位置: 数据都存放于RAM (Random Access Memory). 1-2. 存放数据的类型:stack栈中保存方法中的基本数据类型(int, do ...