poj 1265 Area(Pick定理)
| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 5666 | Accepted: 2533 |
Description

Figure 1: Example area.
You are hired to write a program that calculates the area occupied
by the new facility from the movements of a robot along its walls. You
can assume that this area is a polygon with corners on a rectangular
grid. However, your boss insists that you use a formula he is so proud
to have found somewhere. The formula relates the number I of grid points
inside the polygon, the number E of grid points on the edges, and the
total area A of the polygon. Unfortunately, you have lost the sheet on
which he had written down that simple formula for you, so your first
task is to find the formula yourself.
Input
For each scenario, you are given the number m, 3 <= m < 100,
of movements of the robot in the first line. The following m lines
contain pairs 揹x dy�of integers, separated by a single blank, satisfying
.-100 <= dx, dy <= 100 and (dx, dy) != (0, 0). Such a pair means
that the robot moves on to a grid point dx units to the right and dy
units upwards on the grid (with respect to the current position). You
can assume that the curve along which the robot moves is closed and that
it does not intersect or even touch itself except for the start and end
points. The robot moves anti-clockwise around the building, so the area
to be calculated lies to the left of the curve. It is known in advance
that the whole polygon would fit into a square on the grid with a side
length of 100 units.
Output
output for every scenario begins with a line containing 揝cenario #i:�
where i is the number of the scenario starting at 1. Then print a single
line containing I, E, and A, the area A rounded to one digit after the
decimal point. Separate the three numbers by two single blanks.
Terminate the output for the scenario with a blank line.
Sample Input
2
4
1 0
0 1
-1 0
0 -1
7
5 0
1 3
-2 2
-1 0
0 -3
-3 1
0 -3
Sample Output
Scenario #1:
0 4 1.0 Scenario #2:
12 16 19.0
Source
【思路】
Pick定理
同上题。
【代码】
#include<cstdio>
using namespace std; struct Pt {
int x,y;
Pt(int x=,int y=) :x(x),y(y){};
};
Pt p[];
typedef Pt vec;
vec operator - (Pt a,Pt b) { return vec(a.x-b.x,a.y-b.y); } int abs(int x) { return x<? -x:x; }
int gcd(int a,int b) { return b==? a:gcd(b,a%b); }
int cross(Pt a,Pt b) { return a.x*b.y-a.y*b.x; }
int calc(Pt a,Pt b) { return gcd(abs(a.x-b.x),abs(a.y-b.y)); } int n;
int main() {
int T,kase=;
scanf("%d",&T);
while(T--) {
scanf("%d",&n);
n++;
p[]=Pt(,);
for(int i=;i<n;i++) {
scanf("%d%d",&p[i].x,&p[i].y);
p[i].x+=p[i-].x , p[i].y+=p[i-].y;
}
int S=,b=;
for(int i=;i<n-;i++) {
S += cross(p[i],p[i+]);
b += calc(p[i],p[i+]);
}
b += calc(p[n-],p[])+calc(p[],p[]);
printf("Scenario #%d:\n%d %d %.1f\n\n",++kase,(S-b+)/,b,0.5*S);
}
return ;
}
poj 1265 Area(Pick定理)的更多相关文章
- poj 1265 Area (Pick定理+求面积)
链接:http://poj.org/problem?id=1265 Area Time Limit: 1000MS Memory Limit: 10000K Total Submissions: ...
- POJ 1265 Area (Pick定理 & 多边形面积)
题目链接:POJ 1265 Problem Description Being well known for its highly innovative products, Merck would d ...
- poj 1265 Area(pick定理)
Area Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 4373 Accepted: 1983 Description Bein ...
- [poj 1265]Area[Pick定理][三角剖分]
题意: 给出机器人移动的向量, 计算包围区域的内部整点, 边上整点, 面积. 思路: 面积是用三角剖分, 边上整点与GCD有关, 内部整点套用Pick定理. S = I + E / 2 - 1 I 为 ...
- poj 1265 Area( pick 定理 )
题目:http://poj.org/problem?id=1265 题意:已知机器人行走步数及每一步的坐标 变化量 ,求机器人所走路径围成的多边形的面积.多边形边上和内部的点的数量. 思路:1.以 ...
- Area - POJ 1265(pick定理求格点数+求多边形面积)
题目大意:以原点为起点然后每次增加一个x,y的值,求出来最后在多边形边上的点有多少个,内部的点有多少个,多边形的面积是多少. 分析: 1.以格子点为顶点的线段,覆盖的点的个数为GCD(dx,dy),其 ...
- poj 1265 Area 面积+多边形内点数
Area Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 5861 Accepted: 2612 Description ...
- POJ 1265 Area POJ 2954 Triangle Pick定理
Area Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 5227 Accepted: 2342 Description ...
- POJ 1265 Area (pick定理)
题目大意:已知机器人行走步数及每一步的坐标变化量,求机器人所走路径围成的多边形的面积.多边形边上和内部的点的数量. 思路:叉积求面积,pick定理求点. pick定理:面积=内部点数+边上点数/2-1 ...
随机推荐
- Hibernate的检索策略
hibernate 的中的session依照load()和get()按照参数的制定OID(ObjctID)去加载一个持久化对象.另外Query.list()方法则按照HQL语句去加载持久化的对象. 以 ...
- linux下shell编程示例-获取进程id
今天初步学习了一下linux下的shell编程,简单记录一下测试用例 1.编辑shell脚本文件如下: #!/bin/bashecho "hello bash linux"echo ...
- thinkphp 缓存写入失败,网站报错
周末,正在家里休息,同事突然call 我,说网站打不开了,网站一直很正常的,突然成这样,肯定某个地方出问题了, 原来是网站所在的硬盘分区,没空间了,被mysql的日志占满了!!! 哎,好好的周末,在公 ...
- Mongoengine 使用笔记
1.直接将某个document对象导出对应的json数据. #models class Feed(Document): """ @summary: 所有订阅内容 &quo ...
- java MYSQL做分页
MySql中查询语句实现分页功能 语句: select * from 表名 where 条件 limit 要找第几页,每页多少行; import java.util.*; import java.sq ...
- 导航 -MapKit - 获取路线信息绘制导航路线
#import "PPViewController.h" #import <MapKit/MapKit.h> #import "PPAnnotation.h& ...
- hdu 1116
欧拉回路,利用并查集来实现: 代码: #include<cstdio> #include<cstring> #include<vector> using names ...
- ECshop 在迁移到 PHP7 时遇到的兼容性问题
在 PHP7 上安装 ECShop V2.7.3时,报错! Deprecated: Methods with the same name as their class will not be cons ...
- java.lang.UnsupportedClassVersionError(java项目版本一致问题)
报此错误,一般都是由于在myeclipse中的java项目是用高版本(jdk1.6之后)的jdk进行编译后生成的class文件,却要运行在低版本的jdk虚拟机上,导致这个错误 解决办法: 在myecl ...
- 【HDU 5370】 Tree Maker(卡特兰数+dp)
Tree Maker Problem Description Tree Lover loves trees crazily. One day he invents an interesting gam ...