Leetcode: Design Snake Game
Design a Snake game that is played on a device with screen size = width x height. Play the game online if you are not familiar with the game. The snake is initially positioned at the top left corner (0,0) with length = 1 unit. You are given a list of food's positions in row-column order. When a snake eats the food, its length and the game's score both increase by 1. Each food appears one by one on the screen. For example, the second food will not appear until the first food was eaten by the snake. When a food does appear on the screen, it is guaranteed that it will not appear on a block occupied by the snake. Example:
Given width = 3, height = 2, and food = [[1,2],[0,1]]. Snake snake = new Snake(width, height, food); Initially the snake appears at position (0,0) and the food at (1,2). |S| | |
| | |F| snake.move("R"); -> Returns 0 | |S| |
| | |F| snake.move("D"); -> Returns 0 | | | |
| |S|F| snake.move("R"); -> Returns 1 (Snake eats the first food and right after that, the second food appears at (0,1) ) | |F| |
| |S|S| snake.move("U"); -> Returns 1 | |F|S|
| | |S| snake.move("L"); -> Returns 2 (Snake eats the second food) | |S|S|
| | |S| snake.move("U"); -> Returns -1 (Game over because snake collides with border)
HashSet + Queue:
吃东西的时候保留尾巴,不吃的时候删去尾巴
one case to notice蛇转弯的时候,要先删去尾巴,再把新的点加进去。如果这个顺序不对的话,本来不会撞上尾巴的结果会判断会撞上
public class SnakeGame {
int m;
int n;
int[][] foods;
Queue<Integer> queue;
HashSet<Integer> set;
int[] headPos;
int foodSeq;
/** Initialize your data structure here.
@param width - screen width
@param height - screen height
@param food - A list of food positions
E.g food = [[1,1], [1,0]] means the first food is positioned at [1,1], the second is at [1,0]. */
public SnakeGame(int width, int height, int[][] food) {
this.m = height;
this.n = width;
this.foods = food;
this.queue = new LinkedList<Integer>();
this.set = new HashSet<Integer>();
this.headPos = new int[]{0, 0};
this.foodSeq = 0;
queue.offer(0);
set.add(0);
}
/** Moves the snake.
@param direction - 'U' = Up, 'L' = Left, 'R' = Right, 'D' = Down
@return The game's score after the move. Return -1 if game over.
Game over when snake crosses the screen boundary or bites its body. */
public int move(String direction) {
int[] dir;
switch(direction) {
case "U": dir = new int[]{-1, 0}; break;
case "L": dir = new int[]{0, -1}; break;
case "R": dir = new int[]{0, 1}; break;
case "D": dir = new int[]{1, 0}; break;
default: dir = new int[2];
}
int row = headPos[0] + dir[0]; // new position row
int col = headPos[1] + dir[1]; // new position col
//delete tail first, before push into a new cell
if (foodSeq<foods.length && calcPosId(foods[foodSeq][0], foods[foodSeq][1]) == calcPosId(row, col)) {
foodSeq++;
}
else {
set.remove(queue.poll());
}
if (row<0 || row>=m || col<0 || col>=n) return -1; // hit border
if (set.contains(calcPosId(row, col))) return -1; // hit its own body
set.add(calcPosId(row, col));
queue.offer(calcPosId(row, col));
headPos[0] = row;
headPos[1] = col;
return set.size()-1;
}
public int calcPosId(int x, int y) {
return x*n+y;
}
}
/**
* Your SnakeGame object will be instantiated and called as such:
* SnakeGame obj = new SnakeGame(width, height, food);
* int param_1 = obj.move(direction);
*/
如果没有39行,程序会说dir没有initialize,
其实更好的写法应该是
int rowHead = body.peekFirst() / width;
int colHead = body.peekFirst() % width;
switch (direction) {
case "U" : rowHead--;
break;
case "D" : rowHead++;
break;
case "L" : colHead--;
break;
default : colHead++;
}
Leetcode: Design Snake Game的更多相关文章
- [LeetCode] Design Snake Game 设计贪吃蛇游戏
Design a Snake game that is played on a device with screen size = width x height. Play the game onli ...
- [Swift]LeetCode353. 设计贪吃蛇游戏 $ Design Snake Game
Design a Snake game that is played on a device with screen size = width x height. Play the game onli ...
- LeetCode Design TinyURL
原题链接在这里:https://leetcode.com/problems/design-tinyurl/description/ 题目: How would you design a URL sho ...
- [LeetCode] Design Phone Directory 设计电话目录
Design a Phone Directory which supports the following operations: get: Provide a number which is not ...
- [LeetCode] Design Hit Counter 设计点击计数器
Design a hit counter which counts the number of hits received in the past 5 minutes. Each function a ...
- [LeetCode] Design Twitter 设计推特
Design a simplified version of Twitter where users can post tweets, follow/unfollow another user and ...
- [LeetCode] Design Tic-Tac-Toe 设计井字棋游戏
Design a Tic-tac-toe game that is played between two players on a n x n grid. You may assume the fol ...
- LeetCode Design Hit Counter
原题链接在这里:https://leetcode.com/problems/design-hit-counter/. 题目: Design a hit counter which counts the ...
- [LeetCode] Design Search Autocomplete System 设计搜索自动补全系统
Design a search autocomplete system for a search engine. Users may input a sentence (at least one wo ...
随机推荐
- htaccess分布式配置文件常用写法
htaccess 写法 Apache中的.htaccess(或者”分布式配置”了针对目录改变配置的方法,即,在特定的文档目录中放置包含或多个指令的,以作用于此目录及其子目录.作为,所能的命令受到限制. ...
- appium依赖pom文件注解
<!-- appium部分 依赖--> <dependency> <groupId>io.appium</groupId> <artifactId ...
- 分布式缓存技术memcached学习(三)——memcached内存管理机制
几个重要概念 Slab memcached通过slab机制进行内存的分配和回收,slab是一个内存块,它是memcached一次申请内存的最小单位,.在启动memcached的时候一般会使用参数-m指 ...
- JS: How to detect my browser version and operating system using JavaScript?
Example: 1. for IE 11, navigator.userAgent returns "Mozilla/5.0 (Windows NT 6.1; WOW64; Tride ...
- 【转】iOS学习之容易造成循环引用的三种场景
ARC已经出来很久了,自动释放内存的确很方便,但是并非绝对安全绝对不会产生内存泄露.导致iOS对象无法按预期释放的一个无形杀手是——循环引用.循环引用可以简单理解为A引用了B,而B又引用了A,双方都同 ...
- linux errno使用
errno详解 http://blog.csdn.net/wang_517766334/article/details/7561495 #include <errno.h> 就可以直接打印 ...
- Jquery_类选择器笔记
$("[id^=percent]").size() ^=:表示以什么开头 $=:表示以什么结尾 ~=:表示包含什么 id:表示按id选择
- C# 线程调用主线程中的控件
由于项目的需要,最近几天一直在做串口和数据库.由于C#使用的时间不长,所以在编写代码和调试的过程中总是遇到意想不到的问题,比如在使用串口接收数据的时候,在接收数据事件中想把接收的数据放入一个textb ...
- java分享第八天-01(线程)
创建线程:1 可以实现Runnable接口.2 可以扩展Thread类本身. 通过实现Runnable创建线程:创建一个线程,最简单的方法是创建一个实现Runnable接口的类.为了实现Runnab ...
- Node.js exports与module.exports的关系
今天搜索module.exports时看到CNode社区上发的Hack Sparrow一篇相关文章的链接 Node.js Module – exports vs module.exports 一篇5年 ...