Theorem 16.3 If \(A\) is a subspace of \(X\) and \(B\) is a subspace of \(Y\), then the product topology on \(A \times B\) is the same as the topology \(A \times B\) inherits as a subspace of \(X \times Y\).

Comment: To prove the identity of two topologies, we can either show they mutually contain each other or prove the equivalence of their bases. Because a topological basis has smaller number of elements or cardinality than the corresponding topology, proof via basis is more efficient.

Proof: Let \(\mathcal{C}\) be the topological basis of \(X\) and \(\mathcal{D}\) be the basis of \(Y\). Because \(A \subset X\) and \(B \subset Y\), the subspace topological bases of them are \(\mathcal{B}_A = \{C \cap A \vert \forall C \in \mathcal{C} \}\) and \(\mathcal{B}_B = \{D \cap B \vert \forall D \in \mathcal{D} \}\) respectively according to Lemma 16.1.

Due to Lemma 15.1, the basis of the product topology on \(A \times B\) is

\[
\mathcal{B}_{A \times B} = \{ (C \cap A) \times (D \cap B) \vert \forall C \in \mathcal{C}, \forall D \in \mathcal{D} \}.
\]

Meanwhile, the basis of the product topology on \(X \times Y\) is

\[
\mathcal{B}_{X \times Y} = \{ C \times D \vert \forall C \in \mathcal{C}, \forall D \in \mathcal{D} \}.
\]

Restricting \(\mathcal{B}_{X \times Y}\) to the subset \(A \times B\), the basis of the subspace topology on \(A \times B\) is

\[
\begin{aligned}
\tilde{\mathcal{B}}_{A \times B} &= \{ (C \times D) \cap (A \times B) \vert \forall C \in \mathcal{C}, \forall D \in \mathcal{D} \} \\
&= \{ (C \cap A) \times (D \cap B) \vert \forall C \in \mathcal{C}, \forall D \in \mathcal{D} \},
\end{aligned}
\]

which is the same as that of the product topology on \(A \times B\). Hence, this theorem is proved.

The above process of proof can be illustrated as below.

Remark: The above two routes for generating topology on \(A \times B\) must lead to the same result, otherwise, the theory itself is inappropriately proposed. A theory must be at least self-consistent before its debut in reality.

James Munkres Topology: Theorem 16.3的更多相关文章

  1. James Munkres Topology: Theorem 20.3 and metric equivalence

    Proof of Theorem 20.3 Theorem 20.3 The topologies on \(\mathbb{R}^n\) induced by the euclidean metri ...

  2. James Munkres Topology: Theorem 20.4

    Theorem 20.4 The uniform topology on \(\mathbb{R}^J\) is finer than the product topology and coarser ...

  3. James Munkres Topology: Theorem 19.6

    Theorem 19.6 Let \(f: A \rightarrow \prod_{\alpha \in J} X_{\alpha}\) be given by the equation \[ f( ...

  4. James Munkres Topology: Sec 18 Exer 12

    Theorem 18.4 in James Munkres “Topology” states that if a function \(f : A \rightarrow X \times Y\) ...

  5. James Munkres Topology: Sec 22 Exer 6

    Exercise 22.6 Recall that \(\mathbb{R}_{K}\) denotes the real line in the \(K\)-topology. Let \(Y\) ...

  6. James Munkres Topology: Sec 22 Exer 3

    Exercise 22.3 Let \(\pi_1: \mathbb{R} \times \mathbb{R} \rightarrow \mathbb{R}\) be projection on th ...

  7. James Munkres Topology: Lemma 21.2 The sequence lemma

    Lemma 21.2 (The sequence lemma) Let \(X\) be a topological space; let \(A \subset X\). If there is a ...

  8. James Munkres Topology: Sec 37 Exer 1

    Exercise 1. Let \(X\) be a space. Let \(\mathcal{D}\) be a collection of subsets of \(X\) that is ma ...

  9. James Munkres Topology: Sec 22 Example 1

    Example 1 Let \(X\) be the subspace \([0,1]\cup[2,3]\) of \(\mathbb{R}\), and let \(Y\) be the subsp ...

随机推荐

  1. 舵机&数据处理&stm32内存之堆栈溢出(遇到的问题)

    产品名称:TOWER PRO(辉盛)大扭力舵机MG996R (MG995升级产品)6v/11Kg厂家编号:MG996R产品净重: 55g产品尺寸: 40.7*19.7*42.9mm产品拉力: 9.4k ...

  2. Codeforce Round #554 Div.2 C - Neko does Maths

    数论 gcd 看到这个题其实知道应该是和(a+k)(b+k)/gcd(a+k,b+k)有关,但是之后推了半天,思路全无. 然而..有一个引理: gcd(a, b) = gcd(a, b - a) = ...

  3. ueditor 插件集成到 xadmin 中的相关操作

    安装 点击这里下载源码包 在相关的虚拟环境下安装源码方式安装 切入解压后路径进行 python setup.py install 注册 安装成功按照普通app一般注册在 django 程序的app 中 ...

  4. 记录一次Oracle注入绕waf

    这个注入挺特殊的,是ip头注入.我们进行简单的探测: 首先正常发起一次请求,我们发现content-type是76 探测注入我习惯性的一个单引号: 一个单引号我发现长度还是76 我开始尝试单引号,双引 ...

  5. 第三十九篇-RecyclerView的使用

    RecyclerView介绍 RecyclerView的出现可以替代ListView,并且比ListView更高级且更具灵活性.如果有数据集合,其中的元素将因用户操作或网络事件而在运行时发生改变,请使 ...

  6. mysql 单列无重复

    ALTER TABLE jeesite.bb_bill ADD UNIQUE (object_id);

  7. (最短路 Floyd) P2910 [USACO08OPEN]寻宝之路Clear And Present Danger 洛谷

    题意翻译 题目描述 农夫约翰正驾驶一条小艇在牛勒比海上航行. 海上有N(1≤N≤100)个岛屿,用1到N编号.约翰从1号小岛出发,最后到达N号小岛. 一张藏宝图上说,如果他的路程上经过的小岛依次出现了 ...

  8. 2017-12-19python全栈9期第四天第一节之昨日内容回顾与作业讲解之插入insert和extend

    #!/user/bin/python# -*- coding:utf-8 -*-li = ['zs','ls','ww','zl']li.insert(4,'cc')print(li)li.exten ...

  9. 结合别人的文章,做RocketMQ的一点原理分析,结合源码(尽量)----未完待续

    Broker 与Namesrv的关系 1.从namesrv获取配置信息 /** * BrokerConfig类 * * broker每隔30秒(此时间无法更改)向所有nameserver发送心跳,心跳 ...

  10. Nginx反向代理、负载均衡、动静分离、缓存、压缩、防盗链、跨域访问

    一.反向代理 1.在192.168.189.130机器启动tomcat服务,http://192.168.189.130:8080/ 访问服务正常 2.在192.168.189.131机器配置ngin ...