1042 Shuffling Machine (20 分)
 

Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techniques are seen as weak, and in order to avoid "inside jobs" where employees collaborate with gamblers by performing inadequate shuffles, many casinos employ automatic shuffling machines. Your task is to simulate a shuffling machine.

The machine shuffles a deck of 54 cards according to a given random order and repeats for a given number of times. It is assumed that the initial status of a card deck is in the following order:

S1, S2, ..., S13,
H1, H2, ..., H13,
C1, C2, ..., C13,
D1, D2, ..., D13,
J1, J2

where "S" stands for "Spade", "H" for "Heart", "C" for "Club", "D" for "Diamond", and "J" for "Joker". A given order is a permutation of distinct integers in [1, 54]. If the number at the i-th position is j, it means to move the card from position i to position j. For example, suppose we only have 5 cards: S3, H5, C1, D13 and J2. Given a shuffling order {4, 2, 5, 3, 1}, the result will be: J2, H5, D13, S3, C1. If we are to repeat the shuffling again, the result will be: C1, H5, S3, J2, D13.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer K (≤) which is the number of repeat times. Then the next line contains the given order. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print the shuffling results in one line. All the cards are separated by a space, and there must be no extra space at the end of the line.

Sample Input:

2
36 52 37 38 3 39 40 53 54 41 11 12 13 42 43 44 2 4 23 24 25 26 27 6 7 8 48 49 50 51 9 10 14 15 16 5 17 18 19 1 20 21 22 28 29 30 31 32 33 34 35 45 46 47

Sample Output:

S7 C11 C10 C12 S1 H7 H8 H9 D8 D9 S11 S12 S13 D10 D11 D12 S3 S4 S6 S10 H1 H2 C13 D2 D3 D4 H6 H3 D13 J1 J2 C1 C2 C3 C4 D1 S5 H5 H11 H12 C6 C7 C8 C9 S2 S8 S9 H10 D5 D6 D7 H4 H13 C5

题意:

有54张牌,编号为1~54,初始按编号从小到大排列。这些牌按初始排列给定花色,从左到右为13张S,13张H,13张C,13张D,2张J,接下来执行一操作,将牌的位置改变为指定位置,这样的操作执行k次。求最好的排列结果。

题解:

可以开两个数组,a与b分别用来存放每次执行操作前的牌序和执行操作后的牌序。

AC代码:

#include<iostream>
#include<algorithm>
#include<vector>
#include<queue>
#include<map>
#include<string>
#include<cstring>
using namespace std;
string a[];
string b[];
int n;
int change[];
int main()
{
cin>>n;
for(int i=;i<=;i++){
for(int j=;j<=;j++){
string c;
if(i==) c='S';
else if(i==) c='H';
else if(i==) c='C';
else if(i==) c='D';
char c2;
string s;
s=s+c;
if(j<){
c2=j+'';
s+=c2;
}else{
c2=+'';
s+=c2;
c2=j-+'';
s+=c2;
}
a[(i-)*+j]=s;
}
}
a[]="J1";
a[]="J2";
/*for(int i=1;i<=54;i++){
cout<<a[i]<<" ";
}*/
for(int i=;i<=;i++) cin>>change[i];
while(n--){
for(int i=;i<=;i++)
{
b[change[i]]=a[i];
}
for(int i=;i<=;i++)
{
a[i]=b[i];
}
}
for(int i=;i<=;i++)
{
cout<<a[i];
if(i!=){
cout<<" ";
}
}
return ;
}

PAT 甲级 1042 Shuffling Machine (20 分)(简单题)的更多相关文章

  1. PAT Advanced 1042 Shuffling Machine (20 分)(知识点:利用sstream进行转换int和string)

    Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techn ...

  2. PAT (Advanced Level) Practice 1042 Shuffling Machine (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1042 Shuffling Machine (20 分) 凌宸1642 题目描述: Shuffling is a procedure us ...

  3. PAT 1042 Shuffling Machine (20 分)

    1042 Shuffling Machine (20 分)   Shuffling is a procedure used to randomize a deck of playing cards. ...

  4. PAT甲级——1042 Shuffling Machine

    1042 Shuffling Machine Shuffling is a procedure used to randomize a deck of playing cards. Because s ...

  5. PAT 甲级 1042 Shuffling Machine

    https://pintia.cn/problem-sets/994805342720868352/problems/994805442671132672 Shuffling is a procedu ...

  6. PAT(A) 1042. Shuffling Machine (20)

    Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techn ...

  7. 1042 Shuffling Machine (20分)(水)

    Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techn ...

  8. 【PAT甲级】1042 Shuffling Machine (20 分)

    题意: 输入洗牌次数K(<=20),输入54张牌每次洗入的位置(不是交换的位置),输出洗好的牌. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC ...

  9. PAT 1042. Shuffling Machine (20)

    1042. Shuffling Machine (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Shu ...

随机推荐

  1. matlab(8) Regularized logistic regression : 不同的λ(0,1,10,100)值对regularization的影响,对应不同的decision boundary\ 预测新的值和计算模型的精度predict.m

    不同的λ(0,1,10,100)值对regularization的影响\ 预测新的值和计算模型的精度 %% ============= Part 2: Regularization and Accur ...

  2. SpringBoot项目启动报错:java.lang.RuntimeException: java.lang.reflect.InvocationTargetException

    .   ____          _            __ _ _ /\\ / ___'_ __ _ _(_)_ __  __ _ \ \ \ \( ( )\___ | '_ | '_| | ...

  3. glog的安装使用

    参考 :https://blog.csdn.net/Pig_Pig_Bang/article/details/81632962 https://blog.csdn.net/cywtd/article/ ...

  4. java对象转换

    对象转换: 对象的分层涉及到各个层级之间的对象转换(Entity2DTO , DTO2VO, VO2DTO,DTO2Entity等),传统的采用set/get 方法硬编码实现写的代码比较多:或者采用B ...

  5. Windows下有用的工具推荐

    1.ConEmu多标签命令行工具https://download.fosshub.com/Protected/expiretime=1495446879;badurl=aHR0cDovL3d3dy5m ...

  6. linux系列(二十四):du命令

    1.命令格式 du [选项][文件] 2.命令功能 显示每个文件和目录的磁盘使用空间. 3.命令参数 -a或-all 显示目录中个别文件的大小. -b或-bytes 显示目录或文件大小时,以byte为 ...

  7. (转)实验文档5:企业级kubernetes容器云自动化运维平台

    部署对象式存储minio 运维主机HDSS7-200.host.com上: 准备docker镜像 镜像下载地址 复制 12345678910111213141516 [root@hdss7-200 ~ ...

  8. 设计一个树型目录结构的文件系统,其根目录为 root,各分支可以是目录,也可以是文件,最后的叶子都是文件。

    设计一个树型目录结构的文件系统,其根目录为 root,各分支可以是目录,也可以是文件,最后的叶子都是文件. 我实现的功能是提供父目录(兄弟目录),输入文件名,创建树型目录结构,文本文件不可以再有子目录 ...

  9. docker 部署nestjs应用

    搭建nodejs运行环境,使用了node容器运行 1.安装运行node image docker pull node:latest docker run -itd --name mynode node ...

  10. Scrapy不同的item指定不同的Pipeline

    scrapy不同的item指定不同的Pipeline from items import AspiderItem, BspiderItem, CspiderItem class myspiderPip ...