Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.

For example, given the range [5, 7], you should return 4.

解题思路:

本题有很多思路,最简单的方法:

result就是m和n二进制前面相同的部分!!!

JAVA实现如下:

    public int rangeBitwiseAnd(int m, int n) {
int count=0;
while(m!=n){
n>>>=1;
m>>>=1;
count++;
}
return m<<count;
}

Java for LeetCode 201 Bitwise AND of Numbers Range的更多相关文章

  1. [LeetCode] 201. Bitwise AND of Numbers Range ☆☆☆(数字范围按位与)

    https://leetcode.com/problems/bitwise-and-of-numbers-range/discuss/56729/Bit-operation-solution(JAVA ...

  2. [LeetCode#201] Bitwise AND of Numbers Range

    Problem: Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of al ...

  3. leetcode 201. Bitwise AND of Numbers Range(位运算,dp)

    Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers ...

  4. LeetCode 201 Bitwise AND of Numbers Range 位运算 难度:0

    https://leetcode.com/problems/bitwise-and-of-numbers-range/ [n,m]区间的合取总值就是n,m对齐后前面一段相同的数位的值 比如 5:101 ...

  5. 【LeetCode】201. Bitwise AND of Numbers Range 解题报告(Python)

    [LeetCode]201. Bitwise AND of Numbers Range 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/prob ...

  6. 【LeetCode】201. Bitwise AND of Numbers Range

    Bitwise AND of Numbers Range  Given a range [m, n] where 0 <= m <= n <= 2147483647, return ...

  7. 【刷题-LeetCode】201 Bitwise AND of Numbers Range

    Bitwise AND of Numbers Range Given a range [m, n] where 0 <= m <= n <= 2147483647, return t ...

  8. Java 位运算2-LeetCode 201 Bitwise AND of Numbers Range

    在Java位运算总结-leetcode题目博文中总结了Java提供的按位运算操作符,今天又碰到LeetCode中一道按位操作的题目 Given a range [m, n] where 0 <= ...

  9. 201. Bitwise AND of Numbers Range

    题目: Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all num ...

随机推荐

  1. c#创建ISS站点

    private void CreateWebSite() { try { string installPath = "C:\\Program Files\\MyWeb"; stri ...

  2. 如何查询Oracle中用户所有信息

    1.查看所有用户:   select * from dba_users;     select * from all_users;     select * from user_users;   2. ...

  3. 【转】KMP算法

    转载请注明来源,并包含相关链接.http://www.cnblogs.com/yjiyjige/p/3263858.html 网上有很多讲解KMP算法的博客,我就不浪费时间再写一份了.直接推荐一个当初 ...

  4. Putty远程登录VMware虚拟机Linux(Ubuntu)

    安装SSH服务 Ubuntu默认并没有安装ssh服务,如果通过ssh链接ubuntu,需要自己手动安装ssh-server.判断是否安装ssh服务,可以通过如下命令进行: www.linuxidc.c ...

  5. stl-基本知识

    摘要:本文列出几个基本的STL map和STL set的问题,通过解答这些问题讲解了STL关联容器内部的数据结构,最后提出了关于UNIX/LINUX自带平衡二叉树库函数和map, set选择问题,并分 ...

  6. 【2011图灵奖得主】我眼中的Judea Pearl

    [2011图灵奖得主]我眼中的Judea Pearl 来源: 叶星遥的日志 2011年的图灵奖花落UCLA计算机系的Judea Pearl教授.图灵奖是计算领域的最高奖,由于近年来这个领域的兴盛也算是 ...

  7. Yii2事件

    namespace app\components; use yii\base\Component; use yii\base\Event; class MessageEvent extends Eve ...

  8. express快速搭建web server

    安装express4.x npm install -g express npm install -g express-generator //express命令行工具在4.x分离出来了 express ...

  9. C++关键字 explicit

    C++提供了关键字explicit,可以阻止不应该允许的经过转换构造函数进行的隐式转换的发生.声明为explicit的构造函数不能在隐式转换中使用. C++中, 一个参数的构造函数(或者除了第一个参数 ...

  10. Spark Streaming和Flume-NG对接实验

    Spark Streaming是一个新的实时计算的利器,而且还在快速的发展.它将输入流切分成一个个的DStream转换为RDD,从而可以使用Spark来处理.它直接支持多种数据源:Kafka, Flu ...