1、Definition

Linked list consists of a series of nodes. Each nodes contains the element and a pointer which points to the next node. The last node's next link points to NULL.

Linked=data+pointer

use the pointer to describe the logical relationship

2、Implementation

template<class List_entry>
class List
{
public:
List();
int size();
bool empty();
bool full();
...
protected:
int count;
Node<List_entry> *head; //当声明一个linked时,只会拥有一个头指针
} template<class List_entry>
struct Node
{
List_entry entry; // data
Node<List_entry> *next; // point to the next node
Node();
Node(List_entry, Node<List_entry>*link=NULL);
}

3、Operations

(1)two types of insert

①在p节点所在位置插入

New(S)
S->data=a;
q->next=S;
S->next=p;

②在p节点之后插入

New(S)
S->data=a;
S->next=p->next;
p->next=S;

(2) create a linked list

In order to create a linked list, we have this algorithm

①To create a head

②To create new node S

③Insert S

void CreateList(Head)
{
new(Head);
Head->next=NULL;
scanf("%c",ch);
while(ch<>'#')do
{
new(S);
S->data=ch;
S->next=Head->next;
Head->next=S;
}
}

上述构造方式为从头构造,在头元素出一个一个地插入

下面一种是从链尾增添

void CreateList(Head)
{
new(Head);
Head->next=NULL;
Last=Head;
scanf("%c",ch);
while(ch<>'#')do
{
new(S);
S->data=ch;
S->next=NULL;
Last->next=S;
Last=S;
}
}

(3)insert an element at location i

Status ListInsert L(LinkList &L, int i, DataType e)
{
LinkList p, s;
p=L;
int j=0; while(p&&j<i-1)
{
p=p->next;
j++;
} if(!p) return ERROR;
s=(LinkList)malloc(sizeof(LNode));
s->data=e;
s->next=p->next;
p->next=s; return OK;
}

(4)Delete

Status ListDelete(LinkList &L, int i)
{
LinkList p, q;
p=L;
int j=0; while(p&&j<i-1)
{
p=p->next;
j++;
} if(!p) return ERROR; q=p->next;
p->next=q->next;
free(q);
}

(5)Search

①按位查找

Status ListSearch(LinkList &L, int i)
{
LinkList p;
int j=0;
while(p&&j<i-1)
{
p=p->next;
j++;
}
if(!p)return ERROR;
e=p->next;
return OK;
}

③按值查找

Status ListSearch(LinkList &L, DataType e)
{
LinkList p;
p=L;
int j=0;
while(p&&(p->next)!=e)
{
p=p->next;
j++;
}
if(!p)
{
cout<<"Not found"<<endl;
return ERROR;
}
else
{
return (j);
}
}

3、circular linked list

4、Doubly linked list

(1)Insert

p->next=current->next;
p->prior=current;
current->next->prior=p;
current->next=p;

(2)Delete

current->next->prior=current->prior;
current->prior->next=current->next;

 C++style code

//C++style构建链表,有头结点
//operations
/*
LenList(L)链长
GetElem(i, e)换值
SearchElem(e, i)按值查找
InertElem(i, e)插值
DeleteElem(i) 删值
*/ template<typename Type>
struct Node
{
Type data;
Node<Type>*next;
}; template<typename Type>
class LinkList
{
public:
LinkList()
{
head = new Node<Type>;
head->next = NULL;
len = 0;
Type ch;
Node<Type>*p;
while (cin >> ch)
{
p = new Node<Type>;
p->data = ch;
p->next = head->next;
head->next = p;
len++;
}
}
~LinkList()
{
Node<Type>*p = head;
while (p->next)
{
DeleteElem();
}
delete head;
} //LenList(L)链长
int LenList()
{
return len;
} //InertElem(e)从尾插值
void InsertElem(Type e)
{
Node<Type>*p = head;
while (p->next)
{
p = p->next;
} Node<Type>*q = new Node<Type>;
q->data = e;
q->next = p->next;
p->next = q;
len++;
} //InertElem(i, e)从第i位插值
void InsertElem(int i, Type e)
{
Node<Type>*p = head;
int j = 0;
while (p->next && j<i - 1)
{
j++;
p = p->next;
}
Node<Type>*q = new Node<Type>;
q->data = e;
q->next = p->next;
p->next = q;
len++;
} //GetElem(i, e)换值
void GetElem(int i, Type e)
{
int j = 0;
Node<Type>*p = head;
while (p->next && j<i - 1)
{
j++;
p = p->next;
}
p->next->data = e;
} //DeleteElem(i) 第i位删值
void DeleteElem(int i)
{
int j = 0;
Node<Type>*p = new Node;
while (p->next && j<i - 1)
{
j++;
p = p->next;
} Node<Type>*q = p->next;
p->next = q->next;
delete q; len--;
} //DeleteElem() 尾删值
void DeleteElem()
{
Node<Type>*p = head;
while (p->next->next)
{
p = p->next;
}
Node<Type>*q = p->next;
p->next = q->next;
delete q;
len--;
} //SearchElem(e)按值查找
int SearchElem(Type e)
{
Node<Type>*p = head;
int i = 0;
while (p->next && p->data != e)
{
i++;
p = p->next;
} if (i == 0)
return -1;
else return i;
}
//SearchElem(i)按位查找
Type SearchElem(int i)
{
Node<Type>*p = head;
int j = 0;
while (p->next && j<i)
{
j++;
p = p->next;
}
return p->data;
} private:
Node<Type>*head;
int len;
};

  

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