Aggressive cows
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 18599   Accepted: 8841

Description

Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight line at positions x1,...,xN (0 <= xi <= 1,000,000,000). 

His C (2 <= C <= N) cows don't like this barn layout and become aggressive towards each other once put into a stall. To prevent the cows from hurting each other, FJ want to assign the cows to the stalls, such that the minimum distance between any two of them is as large as possible. What is the largest minimum distance?

Input

* Line 1: Two space-separated integers: N and C 

* Lines 2..N+1: Line i+1 contains an integer stall location, xi

Output

* Line 1: One integer: the largest minimum distance

Sample Input

5 3
1
2
8
4
9

Sample Output

3

#include<stdio.h>
#include<algorithm>
#include<math.h>
using namespace std;
#define INF 999999999
const int MAX_N=100005;
int N,M;
int x[MAX_N];

//判断是否满足条件
bool C(int d)
{
    int last=0;
    for(int i=1;i<M;i++)
    {
        int crt=last+1;
        while(crt<N&&x[crt]-x[last]<d)
        {
            crt++;
        }
        if(crt==N)return false;
        last = crt;
    }
    return true;
}
void solve()
{
    sort(x,x+N);
    int lb=0,ub=INF;
    int mid;
    while(ub-lb>1)
    {
        mid=(lb+ub)/2;
        if(C(mid))lb=mid;
        else ub=mid;
    }
    printf("%d\n",lb);
}

int main()
{
    //freopen("C://Users/Administrator/Desktop/acm.txt","r",stdin);
    scanf("%d%d",&N,&M);
    for(int i=0;i<N;i++)
    {
        scanf("%d",&x[i]);
    }
    solve();
    return 0;
}

POJ 2456 编程技巧之------二分查找思想的巧妙应用的更多相关文章

  1. [ACM] poj 2456 Aggressive cows (二分查找)

    Aggressive cows Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5436   Accepted: 2720 D ...

  2. POJ 1064 Cable master(二分查找+精度)(神坑题)

    POJ 1064 Cable master 一开始把 int C(double x) 里面写成了  int C(int x) ,莫名奇妙竟然过了样例,交了以后直接就wa. 后来发现又把二分查找的判断条 ...

  3. POJ 2456 Aggressive cows (二分)

    题目传送门 POJ 2456 Description Farmer John has built a new long barn, with N (2 <= N <= 100,000) s ...

  4. poj 2456 Aggressive cows 贪心+二分

    Aggressive cows Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 25944   Accepted: 11982 ...

  5. noi题库(noi.openjudge.cn) 1.11编程基础之二分查找T01、02、04

    T01 查找最接近的元素 描述 在一个非降序列中,查找与给定值最接近的元素. 输入 第一行包含一个整数n,为非降序列长度.1 <= n <= 100000.第二行包含n个整数,为非降序列各 ...

  6. POJ 1019:Number Sequence 二分查找

    Number Sequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 36013   Accepted: 10409 ...

  7. [ACM] poj 1064 Cable master (二分查找)

    Cable master Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 21071   Accepted: 4542 Des ...

  8. POJ 3258 River Hopscotch(二分查找答案)

    一个不错的二分,注释在代码里 #include <stdio.h> #include <cstring> #include <algorithm> #include ...

  9. POJ 1064 Cable master (二分查找)

    题目链接 Description Inhabitants of the Wonderland have decided to hold a regional programming contest. ...

随机推荐

  1. 【转贴】龙芯内核发展策略 已经支持k8s

    龙芯内核发展策略 时间:2019-06-27 15:48  来源:未知   作者:龙芯中科   点击:1002次 http://www.loongson.cn/m/view.php?aid=1118 ...

  2. C++多线程基础学习笔记(六)

    condition_variable.wait.notifiy_one.notify_all的使用方式 condition_variable:条件变量 wait:等待被唤醒 notify_one:随机 ...

  3. SYN攻击源码

    一.linux下源代码实现/* syn flood by wqfhenanxc. * random soruce ip and random sourec port. * use #include & ...

  4. 爬取百度贴吧前1000页内容(requests库面向对象思想实现)

    此程序以李毅吧为例子,以面向对象的设计思想实现爬取保存网页数据,暂时并未用到并发处理,以后有机会的话会加以改善 首先去百度贴吧分析贴吧地址栏中url后的参数,找到分页对应的参数pn,贴吧名字对应的参数 ...

  5. C++练习 | 铁轨问题

    #include <iostream> #include <cmath> #include <cstring> #include <string> #i ...

  6. 1,全局变量;2,图形验证码;3,解决bug的毅力

    通过这一整天的学习,主要解决了这三个: 1,全局变量 在函数外部定义: var gloabl: function test(){ global = " ":    //不能写成va ...

  7. cut--修剪小能手

    cut命令 cut原理:以每一行位一个处理对象. 参数选项 解释说明 -b 以字节为单位进行分割 -c 以字符为单位进行分割(对切割中文有奇效) -d 自定义分隔符号,默认以tab为分隔符 1:-b ...

  8. loj 2392「JOISC 2017 Day 1」烟花棒

    loj 答案显然满足二分性,先二分一个速度\(v\) 然后显然所有没有点火的都会往中间点火的人方向走,并且如果两个人相遇不会马上点火,要等到火快熄灭的时候才点火,所以这两个人之后应该在一起行动.另外有 ...

  9. avascript中实现垃圾桶的功能

    javascript中实现垃圾桶的功能,就像折垃圾桶在拖动目标上触发事件 (源元素):ondragstart - 用户开始拖动元素时触发ondrag - 元素正在拖动时触发ondragend - 用户 ...

  10. Q2Day79

    requests Python标准库中提供了:urllib.urllib2.httplib等模块以供Http请求,但是,它的 API 太渣了.它是为另一个时代.另一个互联网所创建的.它需要巨量的工作, ...