在struts.xml中配置默认action遇到的问题

初始代码：

<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd">
<struts>

<package name="default" namespace="/" extends="struts-default">

　　<action name="login_*" class="action.LoginAction" method="{1}">
        <result name="success">/success.jsp</result>
        <result name="input">/login.jsp</result>
        <result name="{1}">/test1.jsp</result>
    </action>

    <default-action-ref name="error"></default-action-ref>

    <action name="error">
        <result>/error.jsp</result>
    </action>   
</package>
</struts>    

报错，后查阅资料

原因 action与result-type顺序搞错了

package里元素必须按照一定的顺序排列：

result-types
interceptors
default-interceptor-ref
default-action-ref
default-class-ref
global-results
global-exception-mappings
action*

修改后代码

<struts>
<package name="default" namespace="/" extends="struts-default">
    <default-action-ref name="error"></default-action-ref>
    <action name="error">
        <result>/error.jsp</result>
    </action>

        <action name="login_*" class="action.LoginAction" method="{1}">
        <result name="success">/success.jsp</result>
        <result name="input">/login.jsp</result>
        <result name="{1}">/test1.jsp</result>
    </action>
</package>
</struts>    

就搞定了