1050. String Subtraction (20)
this problem is from PAT, which website is http://pat.zju.edu.cn/contests/pat-a-practise/1050.
firstly i think i can use double circulation to solve it ,however the result of two examples is
proofed to be running time out. So as the problem said, it is not that simple to make it fast.
then i search the problem , there are many people using the search table. i think it is a very
good idea. so i changed the algorithm.
#include<iostream>
#include<string>
#include<vector>
using namespace std; int MAX=; int main()
{
string s1,s2;
getline(cin,s1);
getline(cin,s2);
vector<bool> isExisted(MAX,false);
for (int i = ; i < s2.size(); i++)
{
isExisted[s2[i]] = true;
}
for (int i = ; i < s1.size(); i++)
{
if (!isExisted[s1[i]]) cout<<s1[i];
}
cout<<endl;
}
so this time the Time complexity is O(n) ,which is much faster than the previous one.
1050. String Subtraction (20)的更多相关文章
- PAT 解题报告 1050. String Subtraction (20)
1050. String Subtraction (20) Given two strings S1 and S2, S = S1 - S2 is defined to be the remainin ...
- PAT 甲级 1050 String Subtraction (20 分) (简单送分,getline(cin,s)的使用)
1050 String Subtraction (20 分) Given two strings S1 and S2, S=S1−S2 is defined to be t ...
- PAT (Advanced Level) 1050. String Subtraction (20)
简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> ...
- PAT甲题题解-1050. String Subtraction (20)-水题
#include <iostream> #include <cstdio> #include <string.h> #include <algorithm&g ...
- PAT Advanced 1050 String Subtraction (20 分)
Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking ...
- PAT Advanced 1050 String Subtraction (20) [Hash散列]
题目 Given two strings S1 and S2, S = S1 – S2 is defined to be the remaining string afer taking all th ...
- 1050 String Subtraction (20分)
Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking ...
- PAT练习--1050 String Subtraction (20 分)
题⽬⼤意:给出两个字符串,在第⼀个字符串中删除第⼆个字符串中出现过的所有字符并输出. 这道题的思路:将哈希表里关于字符串s2的所有字符都置为true,再对s1的每个字符进行判断,若Hash[s1[i] ...
- 【PAT甲级】1050 String Subtraction (20 分)
题意: 输入两个串,长度小于10000,输出第一个串去掉第二个串含有的字符的余串. trick: ascii码为0的是NULL,减去'0','a','A',均会导致可能减成负数. AAAAAccept ...
随机推荐
- Linux Systemd——在RHEL/CentOS 7中启动/停止/重启服务
RHEL/CentOS 7.0中一个最主要的改变,就是切换到了systemd.它用于替代红帽企业版Linux前任版本中的SysV和Upstart,对系统和服务进行管理.systemd兼容SysV和Li ...
- 感知器Perceptron
Perceptron: 1.一种基于监督的线性分类器,其特点是:1)模型简单,具有很少的学习参数:2)具有可视性,一条直线即可划分:3)基于人工神经网络的原理. 其结构图为: 2.学习的关键技术: ...
- mvc JavaScriptResult的用法
一.JavaScriptResult在MVC中的定义的代码片段 C# 代码 复制 public class JavaScriptResult : ActionResult { public o ...
- python 常用模块
1.os模块 os模块包装了不同操作系统的通用接口,使用户在不同操作系统下,可以使用相同的函数接口,返回相同结构的结果. os.name:返回当前操作系统名称('posix', 'nt', 'os2' ...
- HDFS体系结构
HDFS的设计目标 检测以及快速恢复硬件问题. 流式的数据访问. 移动计算比移动数据的代价小. 简化一致性模型. 超大规模数据集 异构软硬件平台之间的可移植性. HDFS的结构模型HDFS是一个主从的 ...
- CDH5.5.1 安装Spark ON Yarn环境
CDH对我们已经封装了,我们如果需要Spark on Yarn,只需要yum安装几个包就可以了. 前面的文章我有写过如果搭建自己内网的CDH Yum服务器,请参考<CDH 5.5.1 Yum源服 ...
- 软件工程个人项目--Word frequency program
(一)工程设计时间预计 1.代码编写:2小时 (1)文件夹的遍历以及筛选: (2)文件夹的读取,以及对读取字符的操作: (3)所得结果排序,以及文件输出. 2.程序调试:1小时 (1)编写数据. (2 ...
- BAT-使用BAT方法结束进程(删除进程)
@echo off taskkill /f /im GAM.exe taskkill /f /im GCL10.exe
- 【C语言】-循环的嵌套
循环的嵌套:当在一个循环语句中嵌入另一个循环时,成为循环的嵌套. 循环嵌套的形式: (1)for语句中嵌入for语句: for ( ) { for ( ) { ... } } (2)for语句嵌入wh ...
- codeforces 629BFar Relative’s Problem
B. Far Relative’s Problem time limit per test 2 seconds memory limit per test 256 megabytes input st ...