你正在爬楼梯。需要 n 步你才能到达顶部。
每次你可以爬 1 或 2 个台阶。你有多少种不同的方式可以爬到楼顶呢?
注意:给定 n 将是一个正整数。
示例 1:
输入: 2
输出: 2
说明: 有两种方法可以爬到顶端。
1.  1 步 + 1 步
2.  2 步
示例 2:
输入: 3
输出: 3
说明: 有三种方法可以爬到顶端。
1.  1 步 + 1 步 + 1 步
2.  1 步 + 2 步
3.  2 步 + 1 步
详见:https://leetcode.com/problems/climbing-stairs/description/

Java实现:

方法一:

class Solution {
public int climbStairs(int n) {
if(n==0||n==1||n==2){
return n;
}
return climbStairs(n-1)+climbStairs(n-2);
}
}

方法二:

class Solution {
public int climbStairs(int n) {
if(n<2){
return n;
}
int tmp=0,pre=1,res=1;
for(int i=2;i<=n;++i){
tmp=res;
res=pre+res;
pre=tmp;
}
return res;
}
}

方法三:

class Solution {
public int climbStairs(int n) {
if(n==0||n==1||n==2){
return n;
}
int[] dp=new int[n];
dp[0]=1;
dp[1]=2;
for(int i=2;i<n;++i){
dp[i]=dp[i-1]+dp[i-2];
}
return dp[n-1];
}
}

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