Given an array nums sorted in ascending order, return true if and only if you can split it into 1 or more subsequences such that each subsequence consists of consecutive integers and has length at least 3.

Example 1:

Input: [1,2,3,3,4,5]
Output: True
Explanation:
You can split them into two consecutive subsequences :
1, 2, 3
3, 4, 5

Example 2:

Input: [1,2,3,3,4,4,5,5]
Output: True
Explanation:
You can split them into two consecutive subsequences :
1, 2, 3, 4, 5
3, 4, 5
class Solution {
public boolean isPossible(int[] nums) {
Map<Integer, Integer> freqMap = new HashMap<>();
Map<Integer, Integer> hypoMap = new HashMap<>();
for (int num: nums) {
freqMap.put(num, freqMap.getOrDefault(num, 0) + 1);
} for (int num : nums) {
// base case
if (freqMap.get(num) == 0) {
continue;
}
if (hypoMap.getOrDefault(num, 0) > 0) {
hypoMap.put(num, hypoMap.get(num) - 1);
freqMap.put(num, freqMap.get(num) - 1);
hypoMap.put(num + 1, hypoMap.getOrDefault(num + 1, 0) + 1);
} else if (freqMap.getOrDefault(num, 0) > 0 && freqMap.getOrDefault(num + 1, 0) > 0 && freqMap.getOrDefault(num + 2, 0) > 0) {
freqMap.put(num, freqMap.get(num) - 1);
freqMap.put(num + 1, freqMap.get(num + 1) - 1);
freqMap.put(num + 2, freqMap.get(num + 2) - 1);
hypoMap.put(num + 3, hypoMap.getOrDefault(num + 3, 0) + 1);
} else {
return false;
}
}
return true;
}
}

[LC] 659. Split Array into Consecutive Subsequences的更多相关文章

  1. 【LeetCode】659. Split Array into Consecutive Subsequences 解题报告(Python)

    [LeetCode]659. Split Array into Consecutive Subsequences 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id ...

  2. [LeetCode] 659. Split Array into Consecutive Subsequences 将数组分割成连续子序列

    You are given an integer array sorted in ascending order (may contain duplicates), you need to split ...

  3. 659. Split Array into Consecutive Subsequences

    You are given an integer array sorted in ascending order (may contain duplicates), you need to split ...

  4. leetcode 659. Split Array into Consecutive Subsequences

    You are given an integer array sorted in ascending order (may contain duplicates), you need to split ...

  5. 【leetcode】659. Split Array into Consecutive Subsequences

    题目如下: 解题思路:本题可以维护三个字典,dic_1保存没有组成序列的单元素,dic_2保存组成了包含两个元素的序列中的较大的元素,dic_3保存组成了包括三个或者三个以上元素的序列中的最大值.因为 ...

  6. Split Array into Consecutive Subsequences

    659. Split Array into Consecutive Subsequences You are given an integer array sorted in ascending or ...

  7. leetcode659. Split Array into Consecutive Subsequences

    leetcode659. Split Array into Consecutive Subsequences 题意: 您将获得按升序排列的整数数组(可能包含重复项),您需要将它们拆分成多个子序列,其中 ...

  8. [LeetCode] Split Array into Consecutive Subsequences 将数组分割成连续子序列

    You are given an integer array sorted in ascending order (may contain duplicates), you need to split ...

  9. [Swift]LeetCode659. 分割数组为连续子序列 | Split Array into Consecutive Subsequences

    You are given an integer array sorted in ascending order (may contain duplicates), you need to split ...

随机推荐

  1. C#构造函数调用其他构造函数

    http://blog.csdn.net/dogfish/article/details/6990266  <-- 虏来的地 public class Class1 { public Class ...

  2. POJ 2251:Dungeon Master

    Dungeon Master Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 20687   Accepted: 8004 D ...

  3. SpringCloud学习之Ribbon使用(四)

    1.关于 Ribbon Spring Cloud Ribbon 是基于 Netflix Ribbon 实现的一套客户端负载均衡的工具.Ribbon 是 Netflix 发布的开源项目,主要功能是提供客 ...

  4. SpringCloud----服务注册中心Eureka

    Eureka是Netflix开源的一个RESTful服务,主要用于服务的注册发现.Eureka由两个组件组成:Eureka服务器和Eureka客户端.Eureka服务器用作服务注册服务器.Eureka ...

  5. Linux基础应用

    Linux刚面世时并没有图形界面,因此所有的操作全靠命令完成,如磁盘操作.文件读取.目录操作.进程管理.文件权限等都要通过命令完成.且在职场中,大量的服务器维护都是通过远程命令来完成. 常用的7个命令 ...

  6. [前端] VUE基础 (8) (vue-cli脚手架)

    一.安装vue-cli脚手架 官方文档:https://cli.vuejs.org/zh/guide/cli-service.html Vue CLI 的包名称由 vue-cli改成了  @vue/c ...

  7. hdu1312题解

    这道题从名称来看看不出什么. 所以我们先读一下题干 There is a rectangular room, covered with square tiles. Each tile is color ...

  8. ref与out区别

    ref与out   out.ref都是传递引用(内存地址),使用后都将改变原来参数的数值.   ref 当调用方法时,在方法中会对ref传入的参数数值进行改变,若使用ref参数,则方法定义和调用方法都 ...

  9. JavaWeb乱码问题及统一全站编码(通过Filter实现)

    1. public class CharacterFilter implements Filter { private String characterEncoding = null; FilterC ...

  10. 机器学习分布式框架horovod安装 (Linux环境)

    1.openmi 下载安装 下载连接: https://download.open-mpi.org/release/open-mpi/v4.0/openmpi-4.0.1.tar.gz 安装命令 1 ...