例子1

from tkinter import *
import tkinter.ttk as ttk

win = Tk()
win.title("Treeview 学习")

col = [1,2,3,4]
data = {"item0":["1a","2a","3a","4a"], "item1":{"num0":["1n", "2n", "3n"," 4n"],"num1":["1m","2m","3m","4m"]}, "item2":["1c","2c","3c","4c"]}

tree = ttk.Treeview(win, columns = col, height = 10, show = "tree")
#show = "tree", 第一列也会被显示出来
#也可用show = "headings" 把第一列隐藏起来
#height 的单位是字符,本例里可以显示10行

tree.column('0',width=150,anchor='center') #指定第一列的宽度和名称, 如果show = "headings", 这一列就被隐藏。
tree.column('1',width=100,anchor='center')
tree.column('2',width=100,anchor='w')
tree.column('3',width=100,anchor='center')
tree.column('4',width=100,anchor='center')
tree.heading('0',text='column0')
tree.heading('1',text='column1')
tree.heading('2',text='column2')
tree.heading('3',text='column3')
tree.heading('4',text='column4')

tree.insert('','end',values= data["item0"])
tree.insert('','end',values= data["item2"])

tree.pack()

win.mainloop()
代码运行结果:

例子2, subtrree

from tkinter import *
import tkinter.ttk as ttk

win = Tk()
win.title("Treeview 学习")

col = [1,2,3,4]
data = {"item0":["1a","2a","3a","4a"], "item1":{"num0":["1n", "2n", "3n"," 4n"],"num1":["1m","2m","3m","4m"]}, "item2":["1c","2c","3c","4c"]}

tree = ttk.Treeview(win, columns = col, height = 10, show = "tree")
#show = "tree", 第一列也会被显示出来
#也可用show = "headings" 把第一列隐藏起来
#height 的单位是字符,本例里可以显示10行

tree.column('0',width=www.hjylp178.com 150,anchor='center') #指定第一列的宽度和名称, 如果show = "headings", 这一列就被隐藏。
tree.column('1',width=www.dfgjyl.cn 100,anchor='center')
tree.column('2',width=www.yongxinzaixian.cn100,anchor='w')
tree.column('3',width=100,anchor='center')
tree.column('4',width=100,anchor='center')
tree.heading('0'www.gangchengyuLe178.com ,text='column0')
tree.heading('1',text=www.ysyl157.com 'column1')
tree.heading('2',text=www.mcyllpt.com 'column2')
tree.heading('3',text=www.meiwanyule.cn 'column3')
tree.heading('4',text='column4')

#用递归法遍历带子字典或列表的数据
def process_dict(d, tree, tr):
for k,v in d.items():
if type(v) == list:
if type(v[0]) == dict:
trr www.yigouyule2.cn = tree.insert(tr, 'end', text=k, open=True)
for ls in v:
process_dict(ls, tree, trr)
else:
tree.insert(tr, 'end', text=k, values= v)
elif type(v) == dict:
trr = tree.insert(tr, 'end', text=k, open = True)
process_dict(v, tree, trr)
process_dict(data,tree, "")

tree.pack()

win.mainloop()
代码运行结果:

例子3, 添加滚动条

from tkinter import *
import tkinter.ttk as ttk

win = Tk()
win.geometry("100x100")
win.title("Treeview 学习")

col = [1,2,3,4]
data = {"item0":["1a","2a","3a","4a"], \
"item1":{"num0":["1n", "2n", "3n"," 4n"],"num1":["1m","2m","3m","4m"]},
"item2":["1c","2c","3c","4c"], \
"item3": ["1a", "2a", "3a", "4a"], \
"item4": {"num40": ["1n", "2n", "3n", " 4n"], "num41": ["1m", "2m", "3m", "4m"]},
"item6": ["1c", "2c", "3c", "4c"],\
"item7":["1a","2a","3a","4a"], \
"item8":{"num80":["1n", "2n", "3n"," 4n"],"num81":["1m","2m","3m","4m"]},
"item9":["1c","2c","3c","4c"],\
"item10":["1a","2a","3a","4a"], \
"item11":{"num110":["1n", "2n", "3n"," 4n"],"num111":["1m","2m","3m","4m"]},
"item12":["1c","2c","3c","4c"]
}

tree = ttk.Treeview(win, columns = col, height = 10, show = "tree")
#show = "tree", 第一列也会被显示出来
#也可用show = "headings" 把第一列隐藏起来
#height 的单位是字符,本例里可以显示10行

tree.column('0',width=150,anchor='center') #指定第一列的宽度和名称, 如果show = "headings", 这一列就被隐藏。
tree.column('1',width=100,anchor='center')
tree.column('2',width=100,anchor='w')
tree.column('3',width=100,anchor='center')
tree.column('4',width=100,anchor='center')
tree.heading('0',text='column0')
tree.heading('1',text='column1')
tree.heading('2',text='column2')
tree.heading('3',text='column3')
tree.heading('4',text='column4')

#用递归法遍历带子字典或列表的数据
def process_dict(d, tree, tr):
for k,v in d.items():
if type(v) == list:
if type(v[0]) == dict:
trr = tree.insert(tr, 'end', text=k, open=True)
for ls in v:
process_dict(ls, tree, trr)
else:
tree.insert(tr, 'end', text=k, values= v)
elif type(v) == dict:
trr = tree.insert(tr, 'end', text=k, open = True)
process_dict(v, tree, trr)
process_dict(data,tree, "")

#y滚动条
yscrollbar = Scrollbar(win, orient=VERTICAL, command=tree.yview)
tree.configure(yscrollcommand = yscrollbar.set)
yscrollbar.pack(side = RIGHT, fill = Y)
#x滚动条
xscroll = Scrollbar(win, orient=HORIZONTAL, command=tree.xview)
tree.configure(xscrollcommand = xscroll.set)
xscroll.pack(side = BOTTOM, fill = X)

tree.pack(side = TOP, expand = 1, fill = BOTH)

win.mainloop()
代码运行结果:
---------------------
作者:weixin_41501380
来源:CSDN
原文:https://blog.csdn.net/weixin_41501380/article/details/83933484
版权声明:本文为博主原创文章,转载请附上博文链接!

Python GUI 之 Treeview 学习的更多相关文章

  1. Python:GUI之tkinter学习笔记1控件的介绍及使用

    相关内容: tkinter的使用 1.模块的导入 2.使用 3.控件介绍 Tk Button Label Frame Toplevel Menu Menubutton Canvas Entry Mes ...

  2. Python:GUI之tkinter学习笔记之messagebox、filedialog

    相关内容: messagebox 介绍 使用 filedialog 介绍 使用 首发时间:2018-03-04 22:18 messagebox: 介绍:messagebox是tkinter中的消息框 ...

  3. Python:GUI之tkinter学习笔记3事件绑定

    相关内容: command bind protocol 首发时间:2018-03-04 19:26 command: command是控件中的一个参数,如果使得command=函数,那么点击控件的时候 ...

  4. Python:GUI之tkinter学习笔记2界面布局显示

    相关内容: pack 介绍 常用参数 使用情况 常用函数 grid 介绍 常用参数 使用情况 常用函数 place 介绍 常用参数 使用情况 常用函数 首发时间:2018-03-04 14:20 pa ...

  5. python3.4学习笔记(九) Python GUI桌面应用开发工具选择

    python3.4学习笔记(九) Python GUI桌面应用开发工具选择 Python GUI开发工具选择 - WEB开发者http://www.admin10000.com/document/96 ...

  6. 使用PyQt来编写第一个Python GUI程序

    原文:使用PyQt来编写第一个Python GUI程序 本文由 伯乐在线 - Lane 翻译,Daetalus 校稿.未经许可,禁止转载!英文出处:pythonforengineers.com.欢迎加 ...

  7. Python GUI开发环境的搭建

    原文:Python GUI开发环境的搭建 最近对Python的开发又来了兴趣,对于Python的开发一直停留在一个表面层的认识,玩的部分比较大. Python的入手简单,语法让人爱不释手,在网络通信方 ...

  8. python GUI实战项目——tkinter库的简单实例

    一.项目说明: 本次通过实现一个小的功能模块对Python GUI进行实践学习.项目来源于软件制造工程的作业.记录在这里以复习下思路和总结编码过程.所有的源代码和文件放在这里: 链接: https:/ ...

  9. python GUI图形化编程-----wxpython

    一.python gui(图形化)模块介绍: Tkinter :是python最简单的图形化模块,总共只有14种组建 Pyqt     :是python最复杂也是使用最广泛的图形化 Wx       ...

随机推荐

  1. selenium-Python之定位下拉框选择

    1.通过select 进行定位下拉框 下拉框如图所示 通过代码定位 #通过index进行选择Select(driver.find_element_by_id("cardType") ...

  2. POJ 1741 Tree (树的分治,树的重心)

    题意:给一棵树,n个节点,给定一个数k,求任意满足dist(a,b)<=k的点对的数量. 思路: 这道题的思路比较简单,但是细节很多. 此题可以用分治法,如何分治? (1)如果path(a,b) ...

  3. HDU 4291 A Short problem 短问题 (递推,找规律)

    题意: 给出递推式 g(n) = 3g(n - 1) + g(n - 2),且g(1) = 1,g(0) = 0.求g( g( g(n))) mod 109 + 7. 思路: 要求的g( g( g(n ...

  4. ubuntu 14.04 构建openstack使用的ubunt 16 的桌面版的使用镜像

    1. 下载ubuntu 16.04桌面版的iso文件,我的个人网盘中有,可以下载 https://pan.baidu.com/s/14qT3lbbqLwDaejmz2VSkyw 2. 安装制作镜像文件 ...

  5. Android之父Andy Rubin:被乔布斯羡慕嫉妒的天才

    今年中国掀起一股“苹果热”,智能手机iPhone.平板电脑iPad遭疯抢,一度卖断货.然而,令许多人意想不到的是,在“苹果”的老家——美国市场,智能手机中卖得最火的并不是iPhone,而是Androi ...

  6. Codeforces Round #277.5 (Div. 2)-A. SwapSort

    http://codeforces.com/problemset/problem/489/A A. SwapSort time limit per test 1 second memory limit ...

  7. 使用一位数组解决 1 1 2 3 5 8 13 数列问题 斐波纳契数列 Fibonacci

    斐波纳契数列 Fibonacci 输出这个数列的前20个数是什么? 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 使用数组实现输出数列的前30 ...

  8. makeObjectsPerformSelector用法

    亲测 makeObjectsPerformSelector 的用法. - (void)makeObjectsPerformSelector:(SEL)aSelector NS_SWIFT_UNAVAI ...

  9. 洛谷 P2370 P2370 yyy2015c01的U盘

    https://www.luogu.org/problemnew/show/P2370 二分+背包 #include <algorithm> #include <iostream&g ...

  10. Qt读写excel

    今天在利用Qt进行excel操作时,代码总是走到打开excel这一步是总是出现程序崩溃.在网上查找了各种帖子  说法不一,尝试都没有解决.后来猜想是不是excel没有激活影响的.发现自己的excel没 ...