A number system with moduli is defined by a vector of k moduli, [m1,m2, ···,mk].

The moduli must be pairwise co-prime, which means that, for any pair of moduli, the only common factor is 1.

In such a system each number n is represented by a string "-x1--x2-- ... --xk-" of its residues, one for each modulus. The product m1 ... mk must be greater than the given number n which is to be converted in the moduli number system.

For example, if we use the system [2, 3, 5] the number n = 11 is represented by "-1--2--1-",
the number n = 23 by "-1--2--3-". If we use the system [8, 7, 5, 3] the number n = 187 becomes "-3--5--2--1-".

You will be given a number n (n >= 0) and a system S = [m1,m2, ···,mk] and you will return a string "-x1--x2-- ...--xk-" representing the number n in the system S.

If the moduli are not pairwise co-prime or if the product m1 ... mk is not greater than n, return "Not applicable".

Examples:

fromNb2Str(11 [2,3,5]) -> "-1--2--1-"

fromNb2Str(6, [2, 3, 4]) -> "Not applicable", since 2 and 4 are not coprime

fromNb2Str(7, [2, 3]) -> "Not applicable" since 2 * 3 < 7

fromNb2Str 187 [8,7,5,3] -> "-3--5--2--1-"
fromNb2Str 6 [2, 3, 4] -> "Not applicable", since 2 and 4 are not coprime
fromNb2Str 7 [2, 3] -> "Not applicable", since 2 * 3 < 7
public static class Kata
{
public static String fromNb2Str(int n, int[] sys)
{
string str = "Not applicable";
bool flag = CoPrimeArray(sys);
if (flag)
{
IEnumerable<int> list = sys.Select(x => n % x);
int result = sys.Aggregate(, (sum, y) => sum * y);
if (result > n)
{
str = string.Join(string.Empty, list.Select(x => string.Format("-{0}-", x)));
}
}
return str;
} public static bool CoPrimeArray(int[] array)
{
bool coPrime = false;
int max = array.Max();
int sqrt = Convert.ToInt32(Math.Floor(Math.Sqrt(max)));
bool[] tempArray = new bool[max + ];
tempArray = tempArray.Select(x => x = true).ToArray();
int prime = ;//质数,从最小的开始
IEnumerable<int> dividePrime = array.Where(x => x % prime == );//获取能够被质数整除的数字的集合
while (true)
{
if (dividePrime.Count() > )
{
//这里的判断涉及到了Linq的延迟加载,随着prime的改变,每一次的dividePrime是不同的
break;
}
//被除数/除数=商
for (int i = prime; i <= sqrt; i++)
{
for (int j = i; j * i < max; j++)
{
//j*i这个位置的数据可以被i整除
if (tempArray[j * i])
{
tempArray[j * i] = false;
}
}
}
while (true)
{
prime++;
if (prime == max)
{
//除数已经达到最大值,说明数组里面的所有数字互质
coPrime = true;
break;
}
else
{
if (tempArray[prime])
{
//说明没有被前面prime个数字整除过,
//假如prime是3的话,并且符合的话,说明3没有被2整除过
//假如prime是7的话,并且符合的话,说明7没有被2到6的数字整除过
break;
}
}
}
if (coPrime)
{
break;
}
}
return coPrime;
}
}

Moduli number system的更多相关文章

  1. Find n‘th number in a number system with only 3 and 4

    这是在看geeksforgeeks时看到的一道题,挺不错的,题目是 Given a number system with only 3 and 4. Find the nth number in th ...

  2. F - The Fun Number System(第二季水)

    Description In a k bit 2's complement number, where the bits are indexed from 0 to k-1, the weight o ...

  3. The Stern-Brocot Number System(排序二进制)

    The Stern-Brocot Number System Input: standard input Output: standard output The Stern-Brocot tree i ...

  4. POJ 1023 The Fun Number System

    Description In a k bit 2's complement number, where the bits are indexed from 0 to k-1, the weight o ...

  5. 为什么实数系里不存在最小正数?(Why the smallest positive real number doesn't exist in the real number system ?)

    We define the smallest positive real number as the number which is explicitly greater than zero and ...

  6. POJ1023 The Fun Number System

    题目来源:http://poj.org/problem?id=1023 题目大意: 有一种有趣的数字系统.类似于我们熟知的二进制,区别是每一位的权重有正有负.(低位至高位编号0->k,第i位的权 ...

  7. lightOJ 1172 Krypton Number System(矩阵+DP)

    题目链接:http://lightoj.com/volume_showproblem.php?problem=1172 题意:一个n进制(2<=n<=6)的数字,满足以下条件:(1)至少包 ...

  8. uva 10077 - The Stern-Brocot Number System

    想法: 初始化三個數L=0/1, M=1/1, R=1/0,設輸入的分數為a: 如果a<M,那麼要往左邊走,    R = M;    M = (L分子+M分子)/(L分母+M分母); 如果a& ...

  9. UVa 11651 Krypton Number System DP + 矩阵快速幂

    题意: 有一个\(base(2 \leq base \leq 6)\)进制系统,这里面的数都是整数,不含前导0,相邻两个数字不相同. 而且每个数字有一个得分\(score(1 \leq score \ ...

随机推荐

  1. (转).Net平台开源作业调度框架Quartz.Net

    Quartz.NET介绍: Quartz.NET是一个开源的作业调度框架,是OpenSymphony 的 Quartz API的.NET移植,它用C#写成,可用于winform和asp.net应用中. ...

  2. 虚拟机单一网卡设置两个IP

    一.在虚拟机里修改虚拟网卡配置 cd /ect/sysconfig/network-scripts/ vi ifcfg-eth0 改BOOTPROTO=static cp ifcfg-eth0 ifc ...

  3. C++结构体对象数组的二进制方式读写

    以一个学生信息的结构体数组为例. #include<iostream>#include<string>#include<fstream>using namespac ...

  4. CentOS 开启GD库

    在php.ini 中没有找到"extension=php_gd2.dll"这行代码,这是因为CentOS一般没有预装GD库. 解决办法: 1.在线安装GD库 yum -y inst ...

  5. linear-gradient 的“高能”用法

    首先,让我们来了解一下“linear-gradient”的基本用法: 说明:用线性渐变创建图像 语法: <linear-gradient> = linear-gradient([ [ &l ...

  6. 《Junit实战》读书笔记

    核心原则:任何没有经过自动测试的程序功能都可以当做不存在 单元测试框架的大三规则: 1.每个单元测试都必须独立于其他所有单元测试而运行 2.框架应该以单个测试为单元来检测和报告错误 3.应该易于定义要 ...

  7. 【BZOJ】1925: [Sdoi2010]地精部落 DP+滚动数组

    题目链接:http://www.lydsy.com/JudgeOnline/problem.php?id=1925 题意:输入一个数N(1 <= N <= 4200),问将这些数排列成折线 ...

  8. Monitor All SQL Queries in MySQL (alias mysql profiler)

    video from youtube: http://www.youtube.com/watch?v=79NWqv3aPRI one blog post: Monitor All SQL Querie ...

  9. BZOJ 3715: [PA2014]Lustra

    Description Byteasar公司专门外包生产带有镜子的衣柜.刚刚举行的招标会上,有n个工厂参加竞标.所有镜子都是长方形的,每个工厂能够制造的镜子都有其各自的最大.最小宽度和最大.最小高度. ...

  10. Seven Python Tools All Data Scientists Should Know How to Use

    Seven Python Tools All Data Scientists Should Know How to Use If you’re an aspiring data scientist, ...