1103 Integer Factorization (30 分)   The K−P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K−P factorization of N for any positive integers N, K…

The K-P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K-P factorization of N for any positive integers N, K and P. Input Specification: Each in…

The K-P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K-P factorization of N for any positive integers N, K and P. Input Specification: Each in…

题意: 输入三个正整数N,K,P(N<=400,K<=N,2<=P<=7),降序输出由K个正整数的P次方和为N的等式,否则输出"Impossible". //找到最大可能的整数pos后从大到小爆搜,sample 1给的输出好像不是最大的序列.....…

暴力搜索. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; int n,k,p,top; ]; ; ],ans_num=,ans_len; void d…

该题还不错~. 题意:给定N.K.P,使得可以分解成N = n1^P + … nk^P的形式,如果可以,输出sum(ni)最大的划分,如果sum一样,输出序列较大的那个.否则输出Impossible. dfs枚举,为了防止超时,这里要预先将从1开始的i^p的值存储在factor数组中,直到i^p>n.然后dfs深度优先搜索,相当于把问题一步步分解,即若第一个因子是n1,则接下来我们要判断N-n1^p.k-1是否可行.同时存储当前因子的总和sum,要取sum最大的:还有上一次相加的因子的索引las…

本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90574720 1103 Integer Factorization (30 分)   The K−P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write…

1103 Integer Factorization(30 分) The K−P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K−P factorization of N for any positive integers N, K an…

PAT甲级1103. Integer Factorization 题意: 正整数N的K-P分解是将N写入K个正整数的P次幂的和.你应该写一个程序来找到任何正整数N,K和P的N的K-P分解. 输入规格: 每个输入文件包含一个测试用例,它给出一行三个正整数N(<= 400), K(<= N)和P(1 <P <= 7).一行中的数字用空格分隔. 输出规格: 对于每种情况,如果解决方案存在,输出格式如下: N = n1 ^ P + ... nK ^ P 其中ni(i = 1,... K)是…

The K−P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K−P factorization of N for any positive integers N, K and P. Input Specification: Each in…

The K-P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K-P factorization of N for any positive integers N, K and P. Input Specification: Each in…

题目:https://pintia.cn/problem-sets/994805342720868352/problems/994805364711604224 题意: 给定一个数n,要求从1~n中找出k个数,使得这些数的p次方之和等于n 思路: 因为n为400,所以dfs加剪枝[本来还在想dp来着] 他要求输出的方案是数字之和最大的,如果之和相等要输出字典序较大的. 所以还需维护一个数字之和. 一个剪枝的方法是从大到小进行dfs,后面被选的数一定比前面被选的要小,这里不限制的话显然会出现重复.…

题意:给出一个正整数N,以及k,p,要求把N分解成k个因式,即N=n1^p + n2^p + ... + nk^p.要求n1,n2,...按降序排列,若有多个解,则选择n1+n2+...+nk最大的,若还有多个解,则选择数字序列较大的.若不存在解,则输出Impossible. 思路:这是深度优先搜索的经典例题.详见: 代码: #include <cstdio> #include <cstdlib> #include <cmath> #include <vector…

Source: PAT A1103 Integer Factorization (30 分) Description: The K−P factorization of a positive integer N is to write N as the sum of the P-th power of Kpositive integers. You are supposed to write a program to find the K−P factorization of N for any…

The K−P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K−P factorization of N for any positive integers N, K and P. Input Specification: Each in…

The K-P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K-P factorization of N for any positive integers N, K and P. Input Specification: Each in…

The K−P factorization of a positive integer N is to write N as the sum of the P-th power of Kpositive integers. You are supposed to write a program to find the K−P factorization of N for any positive integers N, K and P. Input Specification: Each inp…

线性dfs,注意每次深搜完状态的维护~ #include<bits/stdc++.h> using namespace std; ; vector<int> v,tmp,path; int n,k,p; void init () { ,cnt=; while (t<=n) { v.push_back(t); t=pow(cnt,p); cnt++; } } ; void dfs (int nowindex,int nowsum,int nowK,int facSum) { i…

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 时隔两年,又开始刷题啦,这篇用于PAT甲级题解,会随着不断刷题持续更新中,至于更新速度呢,嘿嘿,无法估计,不知道什么时候刷完这100多道题. 带*的是我认为比较不错的题目,其它的难点也顶多是细节处理的问题~ 做着做着,发现有些题目真的是太水了,都不想写题解了…

1103. Integer Factorization (30) 时间限制 1200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue The K-P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program…

最短路径 Emergency (25)-PAT甲级真题(Dijkstra算法) Public Bike Management (30)-PAT甲级真题(Dijkstra + DFS) Travel Plan (30)-PAT甲级真题(Dijkstra + DFS,输出路径,边权) All Roads Lead to Rome (30)-PAT甲级真题-Dijkstra + DFS Online Map (30)-PAT甲级真题(Dijkstra + DFS) 最短路径扩展问题 要求数最短路径有多…

深度优先搜索是一种枚举所有完整路径以遍历所有情况的搜索方法.(不撞南墙不回头) DFS一般用递归来实现,其伪代码思路过程一般如下: void DFS(必要的参数){    if (符和遍历到一条完整路径的尾部){        更新某个全局变量的值    }    if (跳出循环的临界条件){        return;    }    对所有可能出现的情况进行递归} 常见题型1: 代码实现: #include <stdio.h> ; ; // 物品减数, 背包容量,最大价值maxValu…

代码: #include <iostream> #include <algorithm> #include <vector> using namespace std; ; //序列A中n各数选k个数使得和为x,最大平方和为maxSumSqu , A[maxn]; vector<int> temp, ans; void dfs(int index, int nowK, int sum, int sumSqu){ if (nowK == k &&…

1091 Acute Stroke (30point(s)) 基础的搜索,但是直接用递归会导致段错误,改用队列之后就不会了,这说明递归调用在空间利用率上还是很吃亏的. #include <cstdio> #include <cstring> #include <string> #include <algorithm> #include <iostream> #include <cmath> #include <map> #…

考虑到PAT甲级考试和开学后的XCPC比赛,决定寒假把PAT (Advanced Level) Practice刷完,进度条会在这篇博客下更新.由于主要以记录为主,大体上不会像单篇题解那么详细,但是对问题的思考,代码的简洁性.可读性还是有保障的,欢迎看到的小伙伴和我讨论 2021.1.10 1001 A+B Format (20分) 很久没写题了,没想到卡了半个小时,惭愧.这里是要把结果用逗号分隔成三组,即以千为单位,不足的话则不必要填逗号,我最多只添了一个逗号,要看清题目意思再动笔 #incl…

2019/4/3 1063 Set Similarity n个序列分别先放进集合里去重.在询问的时候,遍历A集合中每个数,判断下该数在B集合中是否存在,统计存在个数(分子),分母就是两个集合大小减去分子. // 1063 Set Similarity #include <set> #include <map> #include <cstdio> #include <iostream> #include <algorithm> using name…

树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain…

package com.lxm.basics; public class IntegerTest { public static void main(String[] args) { Integer a1 = 45; int a2 = 45; Integer a3 = Integer.valueOf(45); Integer a4 = new Integer(45); Integer a5 = new Integer(45); System.out.println("a1==a2:"+…

如果面试官问Integer与int的区别:估计大多数人只会说道两点,(1)Ingeter是int的包装类,int的初值为0:(2)Ingeter的 初值为null.但是如果面试官再问一下Integer i = 1;int ii = 1; i==ii为true还是为false?估计就有一部分人答不出来了,如果再问一下其他的,估计更多的人会头脑一片混乱.所以我对它们进行了总结,希望对 大家有帮助. 首先看代码: 1 package com.test; 2 /** 3 * 4 * @author 刘玲…

今天在做一个算法时,由于为了和其他人保持接口的数据类型一致,就把之前的int换为Integer,前几天测了几组数据,和之前的结果一样,但是今天在测其它数据 的时候,突然出现了一个奇怪的bug,由于之前我的模块所有的数据(就是当时数据类型还是int)都测过,这个算法整体由三个所写的模块构成(包括我在内),所以其他 两位同伴都去检测各自的模块,但是后来发现是我传出来的数据有点问题,当时我也是百思不得其解,就一路打断点,加肉眼查看数据,后来终于发现是两个Integer类型的 值在本应该相等的地方进入相…