Given an array A, we may rotate it by a non-negative integer K so that the array becomes A[K], A[K+1], A{K+2], ... A[A.length - 1], A[0], A[1], ..., A[K-1].  Afterward, any entries that are less than or equal to their index are worth 1 point. For exa…
Given an array A, we may rotate it by a non-negative integer K so that the array becomes A[K], A[K+1], A{K+2], ... A[A.length - 1], A[0], A[1], ..., A[K-1]. Afterward, any entries that are less than or equal to their index are worth 1 point. For exam…
Given an array A, we may rotate it by a non-negative integer K so that the array becomes A[K], A[K+1], A{K+2], ... A[A.length - 1], A[0], A[1], ..., A[K-1].  Afterward, any entries that are less than or equal to their index are worth 1 point. For exa…
题目如下: Given an array A, we may rotate it by a non-negative integer K so that the array becomes A[K], A[K+1], A{K+2], ... A[A.length - 1], A[0], A[1], ..., A[K-1]. Afterward, any entries that are less than or equal to their index are worth 1 point. Fo…
Given an array A, we may rotate it by a non-negative integer K so that the array becomes A[K], A[K+1], A{K+2], ... A[A.length - 1], A[0], A[1], ..., A[K-1].  Afterward, any entries that are less than or equal to their index are worth 1 point. For exa…
Leetcode之动态规划(DP)专题-746. 使用最小花费爬楼梯(Min Cost Climbing Stairs) 数组的每个索引做为一个阶梯,第 i个阶梯对应着一个非负数的体力花费值 cost[i](索引从0开始). 每当你爬上一个阶梯你都要花费对应的体力花费值,然后你可以选择继续爬一个阶梯或者爬两个阶梯. 您需要找到达到楼层顶部的最低花费.在开始时,你可以选择从索引为 0 或 1 的元素作为初始阶梯. 示例 1: 输入: cost = [10, 15, 20] 输出: 15 解释: 最…
An image is represented by a binary matrix with 0 as a white pixel and 1 as a black pixel. The black pixels are connected, i.e., there is only one black region. Pixels are connected horizontally and vertically. Given the location (x, y) of one of the…
原题链接在这里:https://leetcode.com/problems/smallest-rectangle-enclosing-black-pixels/ 题目: An image is represented by a binary matrix with 0 as a white pixel and 1 as a black pixel. The black pixels are connected, i.e., there is only one black region. Pixe…
You have k lists of sorted integers in ascending order. Find the smallest range that includes at least one number from each of the k lists. We define the range [a,b] is smaller than range [c,d] if b-a < d-c or a < c if b-a == d-c. Example 1: Input:[…
For an integer n, we call k>=2 a good base of n, if all digits of n base k are 1. Now given a string representing n, you should return the smallest good base of n in string format. Example 1: Input: "13" Output: "3" Explanation: 13…
856. 括号的分数 856. Score of Parentheses 题目描述 给定一个平衡括号字符串 S,按下述规则计算该字符串的分数: () 得 1 分. AB 得 A + B 分,其中 A 和 B 是平衡括号字符串. (A) 得 2 * A 分,其中 A 是平衡括号字符串. LeetCode856. Score of Parentheses中等 示例 1: 输入: "()" 输出: 1 示例 2: 输入: "(())" 输出: 2 示例 3: 输入: &q…
一.Nth Highest Salary Write a SQL query to get the nth highest salary from the Employee table. +----+--------+ | Id | Salary | +----+--------+ | 1 | 100 | | 2 | 200 | | 3 | 300 | +----+--------+ For example, given the above Employee table, the nth hig…
Given a binary tree rooted at root, the depth of each node is the shortest distance to the root. A node is deepest if it has the largest depth possible among any node in the entire tree. The subtree of a node is that node, plus the set of all descend…
题目链接:https://leetcode.com/problems/nth-highest-salary/description/ 题意:查询出表中工资第N高的值 思路: 1.先按照工资从高到低排序(注意去重) select distinct Salary from Employee order by Salary desc 2.使用rownum给查询出的数据标注行号 select rownum ro, s.Salary from (select distinct Salary from Em…
数据范围是3500,3500也就是说n的平方是可以接受的.这里告诉你就是有序的,也就是在提醒你可能会是一个类似于二分的算法,所以的话其实基于这两个认识的话我们就可以利用一个枚举叫二分的算法来解决这道题.怎么做呢?就首先的话我们要枚举一端,一端的话我们可以把所有的这个lists的里面所有元素都给去重然后对它进行左端的一个枚举,然后右端的话的呢我们就分别对每一个list进行一个二分来查找它可能包含所有至少来查找这个至少包含一个元素的最大的这么一个区间是什么.然后我们每次枚举的时候把这些最大的区间找一…
[LeetCode]Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 递归和非递归,此提比较简单.广度优先遍历即可.关键之处就在于如何保持访问深度. 下面是4种代码: im…
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 题目标签:Array, Binary Search 题目给了…
Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 题目标题:Tree 这道题目给了我们一个二叉树,让我们找到它最小的深度,注意这里的最小深度是指root 到一个 leaf node. 举个例子: 1 /   2 / 3 这种情况,…
Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4…
There are N piles of stones arranged in a row.  The i-th pile has stones[i] stones. A move consists of merging exactly K consecutive piles into one pile, and the cost of this move is equal to the total number of stones in these K piles. Find the mini…
[Leetcode] Maximum and Minimum Depth of Binary Tree 二叉树的最小最大深度 (最小有3种解法) 描述 解析 递归深度优先搜索 当求最大深度时,我们只要在左右子树中取较大的就行了. 然而最小深度时,如果左右子树中有一个为空会返回0,这时我们是不能算做有效深度的. 所以分成了三种情况,左子树为空,右子树为空,左右子树都不为空.当然,如果左右子树都为空的话,就会返回1. 广度优先搜索(类似层序遍历的思想) 递归解法本质是深度优先搜索,但因为我们是求最小…
On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…
  Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,  [0,1,2,4,5,6,7] might become  [4,5,6,7,0,1,2]). Find the minimum element. The array may contain duplicates. Example 1: Input: [1,3,5] Output: 1 E…
Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 给一个二叉树,找出它的最小深度.最小深度是从根节点向下到最近的叶节点的最短路径,就是最短路径的节点个数. 解法1:DFS 解法2: BFS Java: DFS, Time Comp…
Follow up for "Find Minimum in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might be…
1.原题: https://leetcode.com/problems/minimum-time-visiting-all-points/ On a plane there are n points with integer coordinates points[i] = [xi, yi]. Your task is to find the minimum time in seconds to visit all points. You can move according to the nex…
题目: Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 说明: 1)和1比只是有重复的数字,整体仍采用二分查找 2)方法二 : 实现:  …
要求:此题正好和Maximum Depth of Binary Tree一题是相反的,即寻找二叉树的最小的深度值:从根节点到最近的叶子节点的距离. 结题思路:和找最大距离不同之处在于:找最小距离要注意(l<r)? l+1:r+1的区别应用,因为可能存在左右子树为空的情况,此时值就为0,但显然值是不为0的(只有当二叉树为空才为0),所以,在这里注意一下即可! 代码如下: struct TreeNode { int val; TreeNode *left; TreeNode *right; Tree…
Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 方法一: 层次遍历.主体的思想不变,程序的主体结构也不变,具体遍历过程参照二叉树的层次遍历.关键在于终止条件,在某一层中,节点遍历的顺序是从左往右的,若是最短路径出现在该层中,则其…
Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. class Solution { public: bool search(int A[],…