Dungeon Master Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 16748   Accepted: 6522 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled…

You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot move diagonal…

POJ 2251 题目大意: 给出一三维空间的地牢,要求求出由字符'S'到字符'E'的最短路径,移动方向可以是上,下,左,右,前,后,六个方向,每移动一次就耗费一分钟,要求输出最快的走出时间.不同L层的地图,相同RC坐标处是相连通的.(.可走,#为墙) 解题思路:从起点开始分别往6个方向进行BFS(即入队),并记录步数,直至队为空.若一直找不到,则困住. /* POJ 2251 Dungeon Master --- 三维BFS(用BFS求最短路) */ #include <cstdio> #i…

题目链接:http://poj.org/problem?id=2251 Dungeon Master Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 51402   Accepted: 19261 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit…

Dungeon Master Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with r…

You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot move diagonal…

Dungeon Master Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 45743 Accepted: 17256 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled wi…

Dungeon Master  Descriptions: You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or…

题目链接 http://poj.org/problem?id=2251 题意 给出一个三维地图 给出一个起点 和 一个终点 '#' 表示 墙 走不通 '.' 表示 路 可以走通 求 从起点到终点的 最短路径 走不通输出 Trapped! 方向 是可以 上,下,东南西北 六个方向 思路 BFS板子题 注意要记录 S 和 E 的位置 因为不一定是固定的 要标记访问 AC代码 #include <cstdio> #include <cstring> #include <ctype.…

Dungeon Master Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or dow…

    学习点: scanf可以自动过滤空行 搜索时要先判断是否越界(L R C),再判断其他条件是否满足 bfs搜索时可以在入口处(push时)判断是否达到目标,也可以在出口处(pop时)   #include<cstdio> #include<cstring> #include<iostream> #include<string> #include<queue> using namespace std; ; , , , , , }; , ,…

1棋盘问题 在一个给定形状的棋盘(形状可能是不规则的)上面摆放棋子,棋子没有区别.要求摆放时任意的两个棋子不能放在棋盘中的同一行或者同一列,请编程求解对于给定形状和大小的棋盘,摆放k个棋子的所有可行的摆放方案C. Input 输入含有多组测试数据. 每组数据的第一行是两个正整数,n k,用一个空格隔开,表示了将在一个n*n的矩阵内描述棋盘,以及摆放棋子的数目. n <= 8 , k <= n 当为-1 -1时表示输入结束. 随后的n行描述了棋盘的形状:每行有n个字符,其中 # 表示棋盘区域,…

Problem Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You…

题目链接:http://poj.org/problem?id=3984 Description 定义一个二维数组: int maze[5][5] = { 0, 1, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 1, 0, }; 它表示一个迷宫,其中的1表示墙壁,0表示可以走的路,只能横着走或竖着走,不能斜着走,要求编程序找出从左上角到右下角的最短路线. Input 一个5 × 5的二维数组,表示一个迷宫.数据保证有…

传送门:http://poj.org/problem?id=1287 题意:给出n个点 m条边 ,求最小生成树的权 思路:最小生树的模板题,直接跑一遍kruskal即可 代码: #include<iostream> #include<cstdio> #include<algorithm> #include<string.h> using namespace std; const int maxn = 5005; struct node { int u; in…

题目链接:http://icpc.njust.edu.cn/Problem/Hdu/1242/ 这次的迷宫是有守卫的,杀死一个守卫需要花费1个单位的时间,所以以走的步数为深度,在每一层进行搜索,由于走一步的花费不一定是1,所以我们需要用优先队列寻找最优值.这个题目真是模板题. 代码如下: #include<bits/stdc++.h> using namespace std; typedef unsigned int ui; typedef long long ll; typedef unsi…

题目: BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to benchmark…

<题目链接> 题目大意:给你一棵树,然后进行q次询问,然后要你统计这q次询问中指定的两个节点最近公共祖先出现的次数. 解题分析:LCA模板题,下面用的是离线Tarjan来解决.并且为了代码的简洁,本代码用的是vector存图. #include<iostream> #include<cstdio> #include<cstring> #include<vector> using namespace std; ; vector<int>…

<题目链接> 题目大意: 给定一段序列,进行q次询问,输出每次询问区间的最大值与最小值之差. 解题分析: RMQ模板题,用ST表求解,ST表用了倍增的原理. #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> using namespace std; typedef long long ll; ; int n,q; ll maxsum[M][],mi…

<题目链接> 题目大意: 给出一棵树,问任意两个点的最近公共祖先的编号. 解题分析:LCA模板题,下面用的是树上倍增求解. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> using namespace std; ; const int INF = 0x3f3f3f3f; struct Edge…

"Shortest" pair of paths Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 1215   Accepted: 491 Description A chemical company has an unusual shortest path problem. There are N depots (vertices) where chemicals can be stored. There ar…

题目: http://poj.org/problem?id=2251 #include <stdio.h> #include <string.h> #include <queue> using namespace std; ][][]; ][][]; ][] = {{,,}, {,,}, {,,}, {,,-}, {,-,}, {-,,}}; struct Point { int x, y, z, step; }; struct Point start; queue&l…

Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot m…

Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot m…

题意:给出一个三维坐标的牢,给出起点st,给出终点en,问能够在多少秒内逃出. 学习的第一题三维的广搜@_@ 过程和二维的一样,只是搜索方向可以有6个方向(x,y,z的正半轴,负半轴) 另外这一题的输入的方式还要再多看看--@_@-- #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<queue> #define maxn 55 u…

Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot m…

BUPT2017 wintertraining(16) #5 B POJ - 2251 题意 3维的地图,求从S到E的最短路径长度 题解 bfs 代码 #include <cstdio> #include <cstring> #include <algorithm> #include <queue> #define N 35 using namespace std; struct node{ int x,y,z,d; }s,e; int L,R,C; int…

个人心得:一开始用DFS弄了半天一直输出不了结果,后面发现并没有进行判断:好不容易能够得出答案,结果超时了,才发现原来要用BFS: 对于DFS: 从一个点开始模拟能走的所有步骤,注意边界条件,走到不能走时返回上一步继续循环:耗时比较大,主要要注意当前的动作 格式的话 void dfs(int step) { 判断边界 尝试每一种可能 { 注意标记: 继续下一步: } 返回 } BFS广度搜索,能够走得位置都走,将能到达的位置进入队列,当一个位置的所有动作完成时出队列,注意标志不改变,当队列为空时…

原题传送:http://poj.org/problem?id=3461 Oulipo Time Limit: 1000MS Memory Limit: 65536K Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from th…

题目 http://poj.org/problem?id=3126 题意 多组数据,每组数据有一个起点四位数s, 要变为终点四位数e, 此处s和e都是大于1000的质数,现在要找一个最短的路径把s变为e,每步可以做如下操作,把当前的s中的四位数上的某一位改变,比如1009可以变为2009,1008,1309,1049,然后检验结果是否为大于1000的质数,如果是,那就可以把s变为这个数. 思路 质数明显需要先处理出来,然后采用bfs获取结果即可. 感想 下次需要先计算空间复杂度, 1e8的空间复…