POJ——T2553 The Bottom of a Graph】的更多相关文章

http://poj.org/problem?id=2553 Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 10987   Accepted: 4516 Description We will use the following (standard) definitions from graph theory. Let V be a nonempty and finite set, its elements being…
POJ 2553 The Bottom of a Graph 题目链接 题意:给定一个有向图,求出度为0的强连通分量 思路:缩点搞就可以 代码: #include <cstdio> #include <cstring> #include <algorithm> #include <vector> #include <stack> using namespace std; const int N = 5005; int n, m; vector&l…
题目地址:http://poj.org/problem?id=2553 The Bottom of a Graph Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 7881   Accepted: 3263 Description We will use the following (standard) definitions from graph theory. Let V be a nonempty and finit…
The Bottom of a Graph Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 11981   Accepted: 4931 Description We will use the following (standard) definitions from graph theory. Let V be a nonempty and finite set, its elements being called ve…
The Bottom of a Graph Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 9641   Accepted: 4008 Description We will use the following (standard) definitions from graph theory. Let V be a nonempty and finite set, its elements being called ver…
Description We will use the following (standard) definitions from graph theory. Let V be a nonempty and finite set, its elements being called vertices (or nodes). Let E be a subset of the Cartesian product V×V, its elements being called edges. Then G…
/** problem: http://poj.org/problem?id=2553 将所有出度为0环中的点排序输出即可. **/ #include<stdio.h> #include<stack> #include<vector> #include<algorithm> using namespace std; class Graphics{ ; const static int MAXM = MAXN * MAXN; private: struct E…
题目地址:POJ 2553 题目意思不好理解.题意是:G图中从v可达的全部点w,也都能够达到v,这种v称为sink.然后升序输出全部的sink. 对于一个强连通分量来说,全部的点都符合这一条件,可是假设这个分量还连接其它分量的话,则肯定都不是sink.所以仅仅须要找出度为0的强连通分量就可以. 代码例如以下: #include <iostream> #include <string.h> #include <math.h> #include <queue>…
http://poj.org/problem?id=2186 给定n头牛,m个关系,每个关系a,b表示a认为b是受欢迎的,但是不代表b认为a是受欢迎的,关系之间还有传递性,假如a->b,b->c 则a->c,问有多少头牛被其他所有的牛欢迎. 统计出度为0的点,如果不为1,则表示不存在这样的牛,为1的话就输出这个集合点的数量. #include <iostream> #include <cstdio> #include <cmath> #include…
求解的是有向图中满足“自己可达的顶点都能到达自己”的顶点个数如果强连通分量中某个顶点,还能到达分量外的顶点,则该连通分量不满足要求// 因此,本题要求的是将强连通分量缩点后所构造的新图中出度为0的顶点个数 // 如果某个新图的节点出度数为0 且是缩点而来 那么该强连通分量里面的点都是符合要求的#include <iostream> #include <algorithm> #include <queue> #include <stack> #include…