1740: [Usaco2005 mar]Yogurt factory 奶酪工厂 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 119  Solved: 100[Submit][Status][Discuss] Description The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10…

Description The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10,000) weeks, the price of milk and labor will fluctuate weekly such that it will cost the company C_i (1 <= C_i <= 5,000) c…

bzoj1680[Usaco2005 Mar]Yogurt factory bzoj1740[Usaco2005 mar]Yogurt factory 奶酪工厂 题意: n个月,每月有一个酸奶需求量(吨)和酸奶成本(元每吨).酸奶可以保存,费用为S(元每月每吨),求最小总费用.n≤10000 题解: 第i月每吨酸奶的成本为Cj+s*(i-j),j∈[1,i],化简得Cj-s*j+s*i,因为s*i只和当前相关,所以维护一个最小的Cj-s*j即可.注意开long long. 代码: #includ…

接下来的N(1≤N10000)星期中,奶酪工厂在第i个星期要花C_i分来生产一个单位的奶酪.约克奶酪工厂拥有一个无限大的仓库,每个星期生产的多余的奶酪都会放在这里.而且每个星期存放一个单位的奶酪要花费S分.工厂最近收到了客戶N个星期的订单,第i个星期要向客戶提供Y_i 个单位的奶酪.当然这些奶酪可以在第i个星期时生产,也可以从仓库中拿取.采用怎样的生产策略约克奶酪工厂的花费最小呢?Input第一行两个整数:N和S:接下来的N行中,第i行的两个数表示:C_i和Y_i.Output仅一行,即工厂生产…

n<=10000天每天Ci块生产一东西,S块保存一天,每天要交Yi件东西,求最少花多少钱. 这个我都不知道归哪类了.. #include<stdio.h> #include<string.h> #include<stdlib.h> #include<algorithm> //#include<iostream> using namespace std; int n,m; #define maxn 10011 int a,b; #define…

1680: [Usaco2005 Mar]Yogurt factory Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 106  Solved: 74[Submit][Status][Discuss] Description The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10,000)…

http://www.lydsy.com/JudgeOnline/problem.php?id=1680 看不懂英文.. 题意是有n天,第i天生产的费用是c[i],要生产y[i]个产品,可以用当天的也可以用以前的(多生产的).每单位产品保存一天的费用是s.求最小费用 显然贪心,每次查找之前有没有哪一天保存到现在的价值最小,然后比较更新.. #include <cstdio> #include <cstring> #include <cmath> #include <…

题目链接:http://www.lydsy.com/JudgeOnline/problem.php?id=1680 题意: 在接下来的n周内,第i周生产一吨酸奶的成本为c[i],订单为y[i]吨酸奶. 酸奶可以提前生产,可以存放无限长的时间,存放一周的花费为s. 问你在完成所有订单的前提下,最小的花费为多少. 题解: 贪心. p[i]代表第i周的最小成本. 对于p[i],只用考虑p[i-1],因为已经保证了p[i-1]是i-1之前所有周的最优答案. 所以转移为:p[i] = min(c[i],…

贪心,一边读入一边更新mn,用mn更新答案,mn每次加s #include<iostream> #include<cstdio> using namespace std; int n,s,mn=1e9; long long ans; int main() { scanf("%d%d",&n,&s); for(int i=1,w,c;i<=n;i++) { scanf("%d%d",&w,&c); mn+=…

Description The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10,000) weeks, the price of milk and labor will fluctuate weekly such that it will cost the company C_i (1 <= C_i <= 5,000) c…

Yogurt factory Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 14771   Accepted: 7437 Description The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10,000) weeks, the price of milk…

2393:Yogurt factory 总时间限制:  1000ms 内存限制:  65536kB 描述 The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10,000) weeks, the price of milk and labor will fluctuate weekly such that it will cost th…

http://poj.org/problem?id=2393 Yogurt factory Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7341   Accepted: 3757 Description The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10…

Factory method工厂方法模式是一种实现了“工厂”概念的面向对象设计模式.就像其他创建型模式一样,它也是处理在不指定对象具体类型的情况下创建对象的问题.工厂方法模式的实质是“定义一个创建对象的接口,但让实现这个接口的类来决定实例化哪个类.工厂方法让类的实例化推迟到子类中进行.” 创建一个对象常常需要复杂的过程,所以不适合包含在一个复合对象中.创建对象可能会导致大量的重复代码,可能会需要复合对象访问不到的信息,也可能提供不了足够级别的抽象,还可能并不是复合对象概念的一部分.工厂方法模式通…

Yogurt factory Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8205   Accepted: 4197 Description The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10,000) weeks, the price of milk…

题目 1739: [Usaco2005 mar]Space Elevator 太空电梯 Time Limit: 5 Sec  Memory Limit: 64 MB Description The cows are going to space! They plan to achieve orbit by building a sort of space elevator: a giant tower of blocks. They have K (1 <= K <= 400) differe…

一道水题WA了这么多次真是.... 统考终于完 ( 挂 ) 了...可以好好写题了... 先floyd跑出各个点的最短路 , 然后二分答案 m , 再建图. 每个 farm 拆成一个 cow 点和一个 shelter 点, 然后对于每个 farm x : S -> cow( x ) = cow( x ) 数量 , shelter( x ) -> T = shelter( x ) 容量 ; 对于每个dist( u , v ) <= m 的 cow( u ) -> shelter( v…

1682: [Usaco2005 Mar]Out of Hay 干草危机 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 391  Solved: 258[Submit][Status] Description The cows have run out of hay, a horrible event that must be remedied immediately. Bessie intends to visit the other farms…

The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10,000) weeks, the price of milk and labor will fluctuate weekly such that it will cost the company C_i (1 <= C_i <= 5,000) cents to prod…

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Description The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10,000) weeks, the price of milk and labor will fluctuate weekly such that it will cost the company C_i (1 <= C_i <= 5,000) c…

Factory Methord 工厂方法模式(创建型模式) 从耦合关系谈起耦合关系直接决定着软件面对变化时的行为 -模块与模块之间的紧耦合使得软件面对变化时,相关的模块都要随之变更 -模块与模块之间的松耦合使得软件面对变化时,一些模块更容易被替换或者更改,但其他模块保持不变 对代码的关注要在理解了设计模式之后,对于不同的代码但是解决的是同一类问题,他们就是同一种设计模式.解决了哪一类的问题就是哪一类的设计模式. 软件需求的变化是软件工程的一部分,是我们要解决的问题. 把模块分为主模块.次模块主模…

Abstract Factory 抽象工厂(创建型模式) 常见的对象创建方法:    //创建一个Road对象    Road road=new Road();    new的问题:    -实现依赖,不能应对“具体实例化类型”的变化    解决思路:    -封装变化点——那里变化,封装那里    -潜台词:如果没有变化,当然不需要额外的封装    工厂模式的缘起    变化点在“对象创建”,因此就封装“对象创建”    面向接口编程——依赖接口,而非依赖实现    最简单的解决方法:    …

Yogurt factory Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6821   Accepted: 3488 Description The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10,000) weeks, the price of milk…

Yogurt factory Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 16669   Accepted: 8176 Description The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10,000) weeks, the price of milk…

bzoj1682[Usaco2005 Mar]Out of Hay 干草危机 题意: 给个图,每个节点都和1联通,奶牛要从1到每个节点(可以走回头路),希望经过的最长边最短. 题解: 求最小生成树即可. 代码: #include <cstdio> #include <cstring> #include <algorithm> #include <queue> #define inc(i,j,k) for(int i=j;i<=k;i++) #defin…

本文源自深入浅出设计模式. 只不过我是使用C#/.NET Core实现的例子. 前言 当你看见new这个关键字的时候, 就应该想到它是具体的实现. 这就是一个具体的类, 为了更灵活, 我们应该使用的是接口(interface). 有时候, 你可能会写出这样的代码: 这里有多个具体的类被实例化了, 是根据不同情况在运行时被实例化的. 当你看到这样的代码, 你就会知道当有需求需要对其进行修改或者扩展的时候, 你就得把这个文件打开, 然后看看在这里应该添加或者删除点什么. 这类的代码经常会分散在程序的…

Factory is a design pattern in common usage. Please implement a ToyFactory which can generate proper toy based on the given type. ExampleToyFactory tf = ToyFactory();Toy toy = tf.getToy('Dog');toy.talk(); >> Wow toy = tf.getToy('Cat');toy.talk();>…

Factory is a design pattern in common usage. Implement a ShapeFactory that can generate correct shape. You can assume that we have only tree different shapes: Triangle, Square and Rectangle. Example ShapeFactory sf = new ShapeFactory(); Shape shape =…

1.意图 定义一个用于创建对象的接口,让子类决定实例化哪一个类.Factory Method使一个类的实例化延迟到其子类. 2.动机 框架使用抽象类定义和维护对象之间的关系.这些对象的创建通常也由框架负责. 3.适用性 当一个类不知道它所必须创建的对象的类的时候. 当一个类希望由它的子类来指定它所创建的对象的时候. 当类将创建对象的职责委托给多个帮助子类中的某一个,并且你希望将哪一个帮助子类是代理者这一局部化的时候. 4.结构 5.代码实例 class Product { public: ; }…