点击查看代码 #include<iostream> using namespace std; const int N = 10; int n; void dfs(int u, int nums[], bool st[]) { if (u > n) { for (int i = 1; i <= n; i++) cout << nums[i] << ' '; cout << endl; } else { for (int i = 1; i <=…
dp [ x ] [ y ] [ z ] 表示二进制y所表示的组合对应的之和mod x余数为z的最小数... 如可用的数字为 1 2 3 4...那么 dp [ 7 ] [ 15 ] [ 2 ] = 1234 .... 输入一个数列后..将dp的表做出来..然后O(1)的输出...题目要求是( T + X ) % K =0 可以转化为 T % K = ( K - ( X % K ) ) % K Program: #include<iostream> #include<stdio.h>…
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note:You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initi…
九九乘法表 i = 0 #while 九九乘法表 j = 0 while i < 9: i += 1 while j<9: j += 1 sum = i + j total="%s + %s = %s"% (i,j,sum) print(total,end=" ") if i == j: j = 0 print("\n") break while实现九九乘法表 for i in range(1,10): # for 九九乘法表 for…
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility) P A H N A P L S I I G Y I R And then read line by line: "PAHNAPLSII…
比较套路的组合数学题 For a sequence a of n integers between 1 and m, inclusive, denote f(a) as the number of distinct subsequences of a (including the empty subsequence). You are given two positive integers n and m. Let S be the set of all sequences of length …
