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题目: Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 题解: 这道题主要难点是改写Comparator. Comparator接口定义了两个方法:compare( )和equals( ).这里给出的compare( )方法按顺序比较了两个元素: int comp…
题目: Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], insert and me…
lc57 Insert Interval 仔细分析题目,发现我们只需要处理那些与插入interval重叠的interval即可,换句话说,那些end早于插入start以及start晚于插入end的interval都可以保留.我们只需要两个指针,i&j分别保存重叠interval中最早start和最晚end即可,然后将interval [i, j]插入即可 class Solution { public int[][] insert(int[][] intervals, int[] newInte…
目录 题目链接 注意点 解法 小结 题目链接 Merge Intervals - LeetCode 注意点 区间是无序的 每个区间start一定小于end 解法 解法一:首先以start的值从小到大来排序,排完序我们就可以开始合并了.先把第一个区间存入ret,然后从第二个开始遍历所有区间,如果与ret中最后一个区间有重叠就更新,否则就直接存入ret.时间复杂度O(n) /** * Definition for an interval. * struct Interval { * int star…
56. Merge Interval 0. 参考文献 序号 文献 1 花花酱 LeetCode 56. Merge Intervals 2 [LeetCode] Merge Intervals 合并区间 1. 题目 Given a collection of intervals, merge all overlapping intervals. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]…
题目: Follow up for N-Queens problem. Now, instead outputting board configurations, return the total number of distinct solutions. 题解: 这道题跟NQueens的解法完全一样(具体解法参照N QueensN Queens leetcode java),只不过要求的返回值不同了..所以要记录的result稍微改一下就好了... 因为涉及到递归,result传进去引用类型(…
LintCode 156: Merge Interval 题目描述 给出若干闭合区间,合并所有重叠的部分. 样例 给出的区间列表 => 合并后的区间列表: [ [ [1, 3], [1, 6], [2, 6], => [8, 10], [8, 10], [15, 18] [15, 18] ] ] Fri Feb 24 2017 思路 首先将区间们按照开始元素的大小排序,然后从头到尾遍历一遍,若遇到该区间的开始元素小于前一个区间的结束元素时,将两个区间合并. 区间合并可以直接修改前一个区间的结束…
Merge Interval: Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 算法分析:首先要对给定序列排序.然后再去遍历合并. class Interval { int start; int end; Interval() { start = 0; end = 0…
Interval的合并时比较常见的一类题目,网上的Amazon面经上也有面试这道题的记录.这里以LeetCode上的例题做练习. Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. /** * Definition for an inter…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […
Merge Intervals 2014.2.26 21:28 Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. Solution: The problem didn't guarantee that the set of intervals is sorted, so…
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 使用分治法,时间复杂度是nlogk, n是所有元素个数的总和,k是k个lists, 这种方法和依次merge每一个list的方法的时间复杂度不同. 如果第一个list有n-k个元素,其余每个list是1个元素, 两两分治合并,每个元素参与了logk次合并, 如果是依次合并(第一个和第二个合并,之后的结…
问题描述: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 分析: 将k个sorted list合并为一个sorted list借鉴归并排序的方法,自顶向下,先递归地对链表的前半部分和后半部分进行归并排序,最后再merge. 二分时,mid = (len - 1)/ 2,这样划分更为均匀,而不是 len / 2 算法: /** * 方法一.Link…
题目: Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B a…
题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题解: 这道题是链表操作题,题解方法很直观. 首先,进行边界条件判断,如果任一一个表是空表,就返回另外一个表. 然后,对于新表选取第一个node,选择两个表表头最小的那个作为新表表头,指针后挪. 然后同时遍历…
Question 56. Merge Intervals Solution 题目大意: 一个坐标轴,给你n个范围,把重叠的范围合并,返回合并后的坐标对 思路: 先排序,再遍历判断下一个开始是否在上一个范围内,如果在且结束坐标大于上一个坐标就合并 Java实现: public List<Interval> merge(List<Interval> intervals) { if (intervals == null || intervals.size() == 0) return i…
Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 题目大意:给定一个组区间,实现一个函数,合并这些区间. 解题思路:首先根据start排序,然后开始循环,判断当前end和下一个的start是否有overlap,没有的话,可以输出当前这个区间,有的话把后一个的end设置为…
这里记录一下自己刷的LeetCode题目. 有些博客用英文阐述自己的思路和收获,相当于练习一下英文的表达能力. 比较好的题目有加粗. 1. Two Sum 3. Longest Substring Without Repeating Characters 5. Longest Palindromic Substring 7. Reverse Integer 9. Palindrome Number 8. String to Integer (atoi) 溢出的处理 21. Merge Two S…
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Reference: http://blog.csdn.net/lbyxiafei/article/details/9375735  题目: Implement int sqrt(int x). Compute and return the square root of x. 题解: 这道题很巧妙的运用了二分查找法的特性,有序,查找pos(在这道题中pos=value),找到返回pos,找不到返回邻近值. 因为是求数x(x>=0) 的平方根, 因此,结果一定是小于等于x且大于等于0,所以用二分查…
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Candy There are N children standing in a line. Each child is assigned a rating value. You are giving candies to these children subjected to the following requirements: Each child must have at least one candy. Children with a higher rating get more ca…
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example,"A man, a plan, a canal: Panama" is a palindrome."race a car" is not a palindrome. Note:Have you consider that th…
问题描述: Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 提示:bit manipulation(位操作) 参考:http…
题目: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we ma…
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题目: Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example, Given n = 3, there are a total of 5 unique BST's. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3 题解:  这道题我自己是没啥思路的,感觉就是一种排列组合的计算,但是又不太会..然后…
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题目: Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, given s = "leetcode", dict = ["leet", "code"]. Return true bec…