using System; using System.Collections; using System.Collections.Generic; using System.Diagnostics; using System.Linq; namespace ConsoleTest { class Program { static void Main(string[] args) { List<string> listTest = new List<string>(); ; i &l…
二分法: 平均时间复杂度:O(log2n) int halfFuntion(int a[], int length, int number) { int start = 0; int end = length - 1; int index = 0; while(start < end) { index = start + (end - start)/2 if(a[index] == number){ return index; } else if(a[index] < number){…
题目地址 分析:如果用二分法,关键是score和aid分开排序,score排序是为了充分利用中位数的性质,这样就可以确定m左右必须各选N/2个,到这之后有人是用dp求最优解,可以再次按照aid排序一次,可以直接确定最优解(肯定是从最小的开始选择!): #include <cstdio> #include <algorithm> #include <cstring> using namespace std; int N, C, F; ; struct Cow{ int i…
题目来源:https://leetcode.com/problems/two-sum/ Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1…
凸多边形 Time Limit: 2000 MS Memory Limit: 65536 K Total Submit: 130(24 users) Total Accepted: 40(18 users) Rating: Special Judge: No Description 已知一个凸多边形A(包含n个点,点按照顺时针给出),和一个点集B(包含m个点),请判断这m个点是否都严格在凸多边形A内部. Input 输入包含多组测试数据. 对于每组测试数据:…
使用二分法在一个数组中查找一个数: package com.test; public class BinaryFind { private final static int size = 500000; public static void main(String[] args) { int[] a = new int[size]; for (int i = 0; i < size; i++) { a[i] = i + 1; } find(a, -500001155); } private st…
冒泡算法: #-*- coding: UTF-8 -*-#冒泡排序 def func(lt):if type(lt).__name__ !='list' and type(lt).__name__ !='tuple':returnif type(lt).__name__ == 'tuple':return list(lt)for i in range(1,len(lt)-1): for j in range(1,len(lt)-i): if lt[j] > lt[j+1]…
#include <stdio.h> #define LEN 10 /* 折半查找(二分法检索). */ int index_of(int *a, int k) { ; ; int m; while(l <= r) { m = (r + l) >> ; //右移(即除以2). if(k == a[m]) return m; //找到,则直接返回下标. else if(k > a[m]) l = m + ; else r = m - ; } ; //结束循环后,仍未找到,…
