BaoBao has just found a grid with $n$ rows and $m$ columns in his left pocket, where the cell in the $j$-th column of the $i$-th row (indicated by $(i, j)$) contains an arrow (pointing either upwards, downwards, leftwards or rightwards) and an intege…
We call a string as a 0689-string if this string only consists of digits '0', '6', '8' and '9'. Given a 0689-string $s$ of length $n$, one must do the following operation exactly once: select a non-empty substring of $s$ and rotate it 180 degrees. Mo…
Tree Ming and Hong are playing a simple game called nim game. They have nn piles of stones numbered 11 to nn ,the ii-th pile of stones has a_iai​ stones. There are n - 1n−1 bidirectional roads in total. For any two piles, there is a unique path from…
Travel There are nn planets in the MOT galaxy, and each planet has a unique number from 1 \sim n1∼n. Each planet is connected to other planets through some transmission channels. There are mm transmission channels in the galaxy. Each transmission cha…
Swap There is a sequence of numbers of length nn, and each number in the sequence is different. There are two operations: Swap the first half and the last half of the sequence (if nn is odd, the middle number does not change) Swap all the numbers in…
Angel's Journey “Miyane!” This day Hana asks Miyako for help again. Hana plays the part of angel on the stage show of the cultural festival, and she is going to look for her human friend, Hinata. So she must find the shortest path to Hinata’s house.…
Tasks It's too late now, but you still have too much work to do. There are nn tasks on your list. The ii-th task costs you t_iti​seconds. You want to go to bed TT seconds later. During the TT seconds, you can choose some tasks to do in order to finis…
链接:https://nanti.jisuanke.com/t/39277 思路: 一开始看着很像树分治,就用树分治写了下,发现因为异或操作的特殊性,我们是可以优化树分治中的容斥操作的,不合理的情况只有当两点在一条链上才存在,那么直接一遍dfs从根节点向下跑途中维护一下前缀和,把所有情况中不合理情况造成的值修正. 这样的话时间复杂度就可以降得非常低了,感觉还可以优化,但是懒得写了 代码耗时:142ms. 实现代码: #include<bits/stdc++.h> using namespace…
题目来源 The 2018 ACM-ICPC China JiangSu Provincial Programming Contest 35.4% 1000ms 65536K Persona5 Persona5 is a famous video game. In the game, you are going to build relationship with your friends. You have N friends and each friends have his upper b…
Let's consider some math problems. JSZKC has a set A=A={1,2,...,N}. He defines a subset of A as 'Meo set' if there doesn't exist two integers in this subset with difference one. For example, When A={1,2,3},{1},{2},{3},{1,3} are 'Meo set'. For each 'M…
JSZKC is going to spend his vacation! His vacation has N days. Each day, he can choose a T-shirt to wear. Obviously, he doesn't want to wear a singer color T-shirt since others will consider he has worn one T-shirt all the time. To avoid this problem…
A Plague Inc Plague Inc. is a famous game, which player develop virus to ruin the world. JSZKC wants to model this game. Let's consider the world has N×Mimes MN×M cities. The world has N rows and M columns. The city in the X row and the Y column has…
目录 Contest Info Solutions A. Attack B. Polynomial E. Interesting Trip F. Sequence G. Winner H. Another Sequence I. Hamster Sort J. Prefix K. A Good Game Contest Info Practice Link Solved A B C D E F G H I J K 9/11 O O - - Ø O Ø O Ø O O O 在比赛中通过 Ø 赛后通…
比赛链接https://www.jisuanke.com/contest/3098?view=challenges B题 拉格朗日插值 题意  T组输入.一个n次多项式 f(x) ,每项的系数不知道,只知道f(0),f(1)..f(n) 的值,m个询问,L,R.计算$\sum_{i=L}^{R}f(i)\quad mod(9999991)$ $(1\leq T\leq 5) $ $(1\leq n\leq 1000) $ $(1\leq m\leq 2000) $ $(1\leq L\leq R…
题意:给你一个长度为$n$的数组,定义函数$f(l,r)=a_{l} \oplus a_{l+1} \oplus...\oplus a_{r}$,$F(l,r)=f(l,l)\oplus f(l,l+1)\oplus ...\oplus f(l,r)\oplus f(l+1,l+1)\oplus ...f(l+1,r)\oplus ...\oplus f(r,r)$,有两种操作,第一种将数组中某个元素$a[x]$变为$y$,第二种计算$F(l,r)$的值. 思路:打表后发现只有当$l$和$r$同…
感想: 今天三个人的状态比昨天计院校赛的状态要好很多,然而三个人都慢热体质导致签到题wa了很多发.最后虽然跟大家题数一样(6题),然而输在罚时. 只能说,水题还是刷得少,看到签到都没灵感实在不应该. 题目链接:http://acm.zju.edu.cn/onlinejudge/showContestProblems.do?contestId=391 A:简单贪心,按高度sort一下就好了,这里用优先队列处理 #include <cstdio> #include <queue> #i…
A:Martadella Stikes Again 水. #include <bits/stdc++.h> using namespace std; #define ll long long int t; ll R, r; int main() { scanf("%d", &t); while (t--) { scanf("%lld%lld", &R, &r); if (R * R > 2ll * r * r) puts(&…
目录 Contest Info Solutions A. Maximum Element In A Stack B. Rolling The Polygon C. Caesar Cipherq D. Take Your Seat E. 2-3-4 Tree F. Moving On G. Factories H. Fight Against Monsters J. Nested Triangles K. Vertex Covers L. Continuous Intervals Contest…
链接:https://codeforc.es/gym/102267 A. Picky Eater 直接比较 int main(){ int x ,y; scanf("%d %d" ,&x ,&y); if(x>=y){ ; } ; ; } B. Primes 素数筛,log判断 ; int vis[maxn]; void is_prime(int N){ ;i<=N;i++){ if(!vis[i]){ prime[num_prime++] = i; vis…
题意:在二维坐标轴上给你一堆点,在x轴上找一个点,使得该点到其他点的最大距离最小. 题解:随便找几个点画个图,不难发现,答案具有凹凸性,有极小值,所以我们直接三分来找即可. 代码: int n; long double x[N],y[N]; long double check(long double s){ long double res=0; long double tmp; for(int i=1;i<=n;++i){ tmp=sqrt((s-x[i])*(s-x[i])+(y[i]*y[i…
The Preliminary Contest for ICPC China Nanchang National Invitational 题目一览表 考察知识点 I. Max answer 单调栈+暴力?? J. Distance on the tree 树链剖分 M. Subsequence 思维??…
目录 ACM ICPC China final G Pandaria ACM ICPC China final G Pandaria 题意:给一张\(n\)个点\(m\)条边的无向图,\(c[i]\)代表点\(i\)的颜色,每条边有一个权值 现在有q个询问如下 u w代表从点u出发,每次只能走权值不超过w的边,经过的颜色中次数最多的是哪种颜色,若有多种,输出编号最小的. $ 1<=n<=1e5$ $ 1<=m,q<=2e5$ $ 1<=c_i<=n$ $ 1<=w…
2019 ICPC 南昌网络赛 比赛时间:2019.9.8 比赛链接:The 2019 Asia Nanchang First Round Online Programming Contest 总结 // 史上排名最高一次,开场不到两小时队友各A一题加水题共四题,排名瞬间升至三四十名 // 然后后三小时就自闭了,一题都没有突破...最后排名211 hhhh     B. Fire-Fighting Hero 题意 队友做的,待补.   AC代码 #include<cstdio> #includ…
2019 ICPC Asia Nanjing Regional A - Hard Problem 计蒜客 - 42395 若 n = 10,可以先取:6,7,8,9,10.然后随便从1,2,3,4,5里面选一个都肯定符合题意 若 n = 9,可以先取:5,6,7,8,9,然后随便从1,2,3,4里面选一个都肯定符合题意. 所以答案就是后半部分的数量+1 #include <cstdio> #include <iostream> #include <cmath> #inc…
Secrete Master Plan Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 429    Accepted Submission(s): 244 Problem Description Master Mind KongMing gave Fei Zhang a secrete master plan stashed in a…
Game Rooms Time Limit: 4000/4000MS (Java/Others)     Memory Limit: 65535/65535KB (Java/Others) Submit Status Your company has just constructed a new skyscraper, but you just noticed a terrible problem: there is only space to put one game room on each…
2016 China Collegiate Programming Contest Final Table of Contents 2016 China Collegiate Programming Contest FinalProblem A:Problem J:Problem H: Problem A: 题意:喝咖啡,每三杯就又可以有免费一杯,求最少花费: 分析:贪心: #include <bits/stdc++.h> using namespace std; const int inf…
AtCoder diverta 2019 Programming Contest 2 看起来我也不知道是一个啥比赛. 然后就写写题解QWQ. A - Ball Distribution 有\(n\)个气球\(k\)个人,每个人至少要拿一个气球.问所有分配方案中拿走气球最多的那个人可以比最少的那个人多拿多少个. 打比赛的时候一开始没看到题,别人说输出\(n\% k\)就过了,然后我就过了. 现在重新一看题解... 应该是\(k=1\)时,答案是\(0\),否则答案是\(n-k\). #includ…
2018 China Collegiate Programming Contest Final (CCPC-Final 2018)-K - Mr. Panda and Kakin-中国剩余定理+同余定理 [Problem Description] \[ 求解x^{2^{30}+3}=c\pmod n \] 其中\(n=p\cdot q\),\(p\)为小于\(x\)的最大素数,\(q\)为大于\(x\)的最小素数,\(x\)为\([10^5,10^9]\)内随机选择的数.\(0< c<n\).…
diverta 2019 Programming Contest 2 A - Ball Distribution 特判一下一个人的,否则是\(N - (K - 1) - 1\) #include <bits/stdc++.h> #define fi first #define se second #define pii pair<int,int> #define mp make_pair #define pb push_back #define space putchar(' ')…