poj2083 Fractal】的更多相关文章

我一开始的想法是间断性的输出空格和solve(k-1) 但是发现问题很大. 雨菲:可以用一个数组保存啊 我:那不爆了? 雨菲:不会爆. 我一算:729 × 729,还真没爆. 然后就直接WA了...... 仔细观察,发现要输出X,而我输出x 然后就A了. 大水题. #include <cstdio> /** made with Unity poj 2083 */ using namespace std; ; char G[N][N]; inline int pow(int a, int b)…
$AcWing$ $Sol$ 一年前做过差不多的南蛮图腾,当时做出来还是很有成就感的$OvO$ $N<=7$,就是模拟模拟,预处理一下,$over$ $Code$ #include<bits/stdc++.h> #define il inline #define Rg register #define go(i,a,b) for(Rg int i=a;i<=b;++i) #define yes(i,a,b) for(Rg int i=a;i>=b;--i) #define m…
在目前的Mysql数据库中,使用最广泛的是innodb存储引擎.innodb确实是个很不错的存储引擎,就连高性能Mysql里都说了,如果不是有什么很特别的要求,innodb就是最好的选择.当然,这偏文章讲的是TokuDB,不是innodb,相比innodb,TokuDB有着自己的特点. BTree和Fractal tree的比较: 目前无论是SQL Server,还是MySQL的innodb,都是用的B+Tree(SQL Server用的是标准的B-Tree)的索引结构.从理论上来说,这个结构在…
Fractal Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 6646   Accepted: 3297 Description A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not exhibit exactly…
Description Consider a regular triangular area, divide it into four equal triangles of half height and remove the one in the middle. Apply the same operation recursively to each of the three remaining triangles. If we repeated this procedure infinite…
在目前的Mysql数据库中,使用最广泛的是innodb存储引擎.innodb确实是个很不错的存储引擎,就连高性能Mysql里都说了,如果不是有什么很特别的要求,innodb就是最好的选择.当然,这偏文章讲的是TokuDB,不是innodb,相比innodb,TokuDB有着自己的特点. 转自:http://www.kryptosx.info/archives/931.html BTree和Fractal tree的比较: 目前无论是SQL Server,还是MySQL的innodb,都是用的B+…
Description A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not exhibit exactly the same structure at all scales, but the same "type" of structures must appear on al…
Fractal Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://hihocoder.com/contest/acmicpc2015beijingonline/problem/8 Description This is the logo of PKUACM 2016. More specifically, the logo is generated as follows: 1. Put four points A0(0,0), B0(0,1),…
Fractal Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 8341   Accepted: 3965 Description A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not exhibit exactly…
C - Fractal(3.4.1) Time Limit:1000MS    Memory Limit:30000KB    64bit IO Format:%I64d & %I64u SubmitStatus Description A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not…
36B - Fractal 思路:分形 代码: #include<bits/stdc++.h> using namespace std; #define ll long long #define pb push_back #define mem(a,b) memset(a,b,sizeof(a)) ][]; ][]; void dfs1(int x,int y,int k,char color){ ){ mp[x][y]=color; return ; } if(color=='.'){ df…
http://poj.org/problem?id=2083 Fractal Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 8317   Accepted: 3957 Description A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The…
这两天自学了一线算法导论里分治策略的内容,秉着只有真正投入投入编程,才能更好的理解一种算法的思想的想法,兴致勃勃地找一些入门的题来学习. 搜了一下最后把目光锁定在了Poj fractal这一个题上.以前一直对这种题无从下手,通过对这一条题的分析与理解,算是第一次对分治思想有一个较为具象的了解. 分治思想的依托为递归. 下面我尝试用分支策略的思想描述这一题. 分解: 在这条题里,通过分析题目可以知道:每一个更大一点的图形都是由前一个状态的小图形放置在对应位置组成的:而每一个小图形的又由更前一个状态…
Description Fractals are really cool mathematical objects. They have a lot of interesting properties, often including: 1. fine structure at arbitrarily small scales; 2. self-similarity, i.e., magnified it looks like a copy of itself; 3. a simple, rec…
题目传送门 代码有注释. #include<iostream> #include<algorithm> #include<cstdlib> #include<sstream> #include<cstring> #include<bitset> #include<cstdio> #include<string> #include<deque> #include<stack> #inclu…
How to Fold a Julia FractalA tale of numbers that like to turn http://acko.net/blog/how-to-fold-a-julia-fractal/ 介绍如何生成Julia分形,非常好看的动态效果,叹为观止.…
#1234 : Fractal 时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 This is the logo of PKUACM 2016. More specifically, the logo is generated as follows: 1. Put four points A0(0,0), B0(0,1), C0(1,1), D0(1,0) on a cartesian coordinate system. 2. Link A0B0, B0C0, C0…
Description A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not exhibit exactly the same structure at all scales, but the same "type" of structures must appear on al…
Description A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not exhibit exactly the same structure at all scales, but the same "type" of structures must appear on al…
总时间限制: 1000ms 内存限制: 65536kB 描述 Consider a regular triangular area, divide it into four equal triangles of half height and remove the one in the middle. Apply the same operation recursively to each of the three remaining triangles. If we repeated this…
Fractal 时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 This is the logo of PKUACM 2016. More specifically, the logo is generated as follows: 1. Put four points A0(0,0), B0(0,1), C0(1,1), D0(1,0) on a cartesian coordinate system. 2. Link A0B0, B0C0, C0D0, D0A0…
生物信息学-序列拼接方法 物理学方法 Fractal Dimension of Exon and Intron Sequences --------------CGCGGCGTGTGTTATA -------------- 数学方法:Relative Complexity in Exon, Intron and Flanks 序列复杂度依据不同组合出现的次数,windows变大之后发现coding比non-coding复杂度变多. COINCIDENT INDEX OF EXON AND INT…
之前的博客实现了最基础的分形树,在这个基础上略微调整一些参数可以得到很多有趣的由分形树发展出的图案. private void drawShape(Graphics g, double x1, double y1, double angle, double depth) { if (depth == 0) { } else { double x2 = x1 + Math.cos(Math.toRadians(angle)) * depth * 15.0; double y2 = y1 + Mat…
尝试使用递归方式实现一棵简单的分形树,给出初始点的坐标,在此基础上根据坐标轴旋转的规则计算出子树干与根节点的坐标关系,依次递归画出左子树干和右子树干,并提供一个递归的深度用于控制画的子树的数目. 在二维坐标系中,坐标轴旋转的公式如下: In two dimensions, every rotation matrix has the following form, This rotates column vectors by means of the following matrix multip…
//poj 1941 //sep9 #include <iostream> using namespace std; const int maxW=2048; const int maxH=1024; int pow2[32]; char g[maxH+10][maxW+10]; void print(int x,int y,int n) { if(n==1){ g[x][y+1]='/'; g[x][y+2]='\\'; g[x+1][y]='/'; g[x+1][y+1]='_'; g[x…
题目链接 题意:题中给了图,所以不看字大概也知道  求的是第n个图形的面积. 就是找规律 递推 一类的... 先给结论: 很鬼畜的公式:    $\displaystyle\frac{3\times 17^n+2\times 7^n}{5}$ 递推式是:  $\displaystyle S_n = S_{n-1}\times 17-4\times 7^{n-1}$ 重点在于17和7是怎么来的. 在题图的基础上画些个框框 观察可以发现 图1中的 $1\times 1$的方格变成了图2中$\sqrt…
题目大意:给出A,B两个点的坐标,以及T,每次找到A.B的四等分点C,D,然后以AB/2为边长,C,D为顶点,构建一个等边三角形,E为另外一个顶点,然后再对C,E:E,D做同样的操作,直到构建的等边三角形的边长小于T时.输出所有过程中的点,按照x坐标排序,相同的按照y坐标. 解题思路:dfs模拟,用ans记录点,最后排序,C,D,E可以根据向量的方法从A,B得到. #include <cstdio> #include <vector> #include <cmath>…
时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 This is the logo of PKUACM 2016. More specifically, the logo is generated as follows: 1. Put four points A0(0,0), B0(0,1), C0(1,1), D0(1,0) on a cartesian coordinate system. 2. Link A0B0, B0C0, C0D0, D0A0 separat…
去年校赛团队赛就有一道分形让所有大一新生欲生欲死…… 当时就想学了 结果一直拖到…… 今天上午…… 马上要省选了 才会一点基础分形…… 还是自己不够努力啊…… 分形主要是要找到递归点…… 还有深度…… 还有深度对应的长度 宽度…… 看了好久才看懂…… 最后要'\0'…… 还要清空格…… 打出来觉得不是很难…… 但就是怕像高中班任说的那样 换个数就不会了…… 希望能学以致用…… 还有两个小时省选…… 总感觉这次省选凶多吉少…… 不管怎么样 正常发挥就好…… 希望可以去商大打省赛…… #includ…
 1.案例描述 树干为80,分叉角度为20,树枝长度小于5则停止.树枝长小于30,可以当作树叶了,树叶部分为绿色,其余为树干部分设为棕色. 2.案例分析 由于分形树具有对称性,自相似性,所以我们可以用递归来完成绘制.只要确定开始树枝长.每层树枝的减短长度和树枝分叉的角度,我们就可以把分形树画出来啦!! 递归基本逻辑(原路返回):右侧树枝绘制递出处理+左侧树枝绘制递出处理+归来时处理(递出和归来两个模型结合).最大优点是逻辑容易理解,最大缺点是重复操作较多易有性能问题. 3.分形几何学 客观事物具…