POJ 3279 Dungeon Master
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 21242 | Accepted: 8265 |
Description
Is an escape possible? If yes, how long will it take?
Input
L is the number of levels making up the dungeon.
R and C are the number of rows and columns making up the plan of each level.
Then there will follow L blocks of R lines each containing C characters. Each character describes one cell of the dungeon. A cell full of rock is indicated by a '#' and empty cells are represented by a '.'. Your starting position is indicated by 'S' and the exit by the letter 'E'. There's a single blank line after each level. Input is terminated by three zeroes for L, R and C.
Output
Escaped in x minute(s).
where x is replaced by the shortest time it takes to escape.
If it is not possible to escape, print the line
Trapped!
Sample Input
3 4 5
S....
.###.
.##..
###.# #####
#####
##.##
##... #####
#####
#.###
####E 1 3 3
S##
#E#
### 0 0 0
Sample Output
Escaped in 11 minute(s).
Trapped!
三维BFS 注意xyz别弄混了
/* ***********************************************
Author :pk29
Created Time :2015/8/19 18:40:40
File Name :4.cpp
************************************************ */
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <stdio.h>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <math.h>
#include <stdlib.h>
#include <iomanip>
#include <list>
#include <deque>
#include <stack>
#define ull unsigned long long
#define ll long long
#define mod 90001
#define INF 0x3f3f3f3f
#define maxn 10000+10
#define cle(a) memset(a,0,sizeof(a))
const ull inf = 1LL << ;
const double eps=1e-;
using namespace std;
struct node{
int x,y,z;
int dist;
};
bool cmp(int a,int b){
return a>b;
}
int l,r,c;
char mp[][][];
int vis[][][];
int sx,sy,sz,ex,ey,ez;
int dir[][]={,,,,,,,,-,,,,-,,,,-,}; void bfs(){
node u,v;
u.x=sx,u.y=sy,u.z=sz, u.dist=;
queue<node>q;
q.push(u);
int mark=;
vis[u.x][u.y][u.z]=;
while(!q.empty()){
u=q.front(),q.pop();
if(u.x==ex&&u.y==ey&&u.z==ez){
mark=;printf("Escaped in %d minute(s).\n",u.dist);break;
}
for(int i=;i<;i++){
int nx=u.x+dir[i][];
int ny=u.y+dir[i][];
int nz=u.z+dir[i][];
if(!vis[nx][ny][nz]&&mp[nx][ny][nz]!='#'&&nx>=&&ny>=&&nz>=&&nx<=r&&ny<=c&&nz<=l){
v.x=nx,v.y=ny,v.z=nz;
v.dist=u.dist+;
q.push(v);
vis[nx][ny][nz]=;
}
}
}
if(!mark)printf("Trapped!\n");
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("in.txt","r",stdin);
#endif
//freopen("out.txt","w",stdout);
while(cin>>l>>r>>c){
if(l==&&c==&&r==)break;
for(int i=;i<=l;i++)
for(int j=;j<=r;j++)
for(int k=;k<=c;k++){
cin>>mp[j][k][i];
if(mp[j][k][i]=='S')sx=j,sy=k,sz=i;
if(mp[j][k][i]=='E')ex=j,ey=k,ez=i;
}
cle(vis);
//cout<<sx<<sy<<sz<<endl;
//cout<<ex<<ey<<ez<<endl; bfs();
}
return ;
}
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