[LeetCode] 380. Insert Delete GetRandom O(1) 插入删除获得随机数O(1)时间
Design a data structure that supports all following operations in average O(1) time.
insert(val): Inserts an item val to the set if not already present.remove(val): Removes an item val from the set if present.getRandom: Returns a random element from current set of elements. Each element must have the same probability of being returned.
Example:
// Init an empty set.
RandomizedSet randomSet = new RandomizedSet(); // Inserts 1 to the set. Returns true as 1 was inserted successfully.
randomSet.insert(1); // Returns false as 2 does not exist in the set.
randomSet.remove(2); // Inserts 2 to the set, returns true. Set now contains [1,2].
randomSet.insert(2); // getRandom should return either 1 or 2 randomly.
randomSet.getRandom(); // Removes 1 from the set, returns true. Set now contains [2].
randomSet.remove(1); // 2 was already in the set, so return false.
randomSet.insert(2); // Since 1 is the only number in the set, getRandom always return 1.
randomSet.getRandom();
设计一个数据结构在O(1)时间内完成:insert(val),remove(val),getRandom()
由于是O(1)时间,要用哈希表 + 数组(HashMap + Array),数组用来保存数字,哈希表用来建立每个数字和其在数组中的位置之间的映射。
插入操作:先判断是否在HashMap里,如果存在则不需要插入,直接返回false。不存在的话,把此数插入到数组的末尾,然后在HashMap中建立数字和其位置的映射。
删除操作:先判断是否在HashMap里,如果没有,直接返回false。由于HashMap的删除是O(1)时间,而数组并不是。为了保证了O(1)时间内的删除,把要删除的数字和数组的最后一个数调换个位置,然后修改对应的HashMap中的值,删除数组的最后一个元素即可。
返回随机数:随机生成一个数组位置,返回该位置上的数字。
Java:
public class RandomizedSet {
Map<Integer, Integer> map;//<val, index in arrlist>
List<Integer> list;//keep a record of value for get random
int size;//map and list are the same size
Random rand;
/** Initialize your data structure here. */
public RandomizedSet() {
this.map = new HashMap<>();
this.list = new ArrayList<>();
this.size = 0;
this.rand = new Random();
}
/** Inserts a value to the set. Returns true if the set did not already contain the specified element. */
public boolean insert(int val) {
if(map.containsKey(val)) return false;
map.put(val, size);
list.add(val);
size++;
return true;
}
/** Removes a value from the set. Returns true if the set contained the specified element. */
public boolean remove(int val) {
if(map.containsKey(val)){
int last = list.get(size - 1);
list.set(map.get(val), last);//use last added ele to fill the element to be removed
map.put(last, map.get(val));//update last added ele's index in list
map.remove(val);
list.remove(size - 1);//remove at end is constant
size--;
return true;
}
return false;
}
/** Get a random element from the set. */
public int getRandom() {
return list.get(rand.nextInt(size));
}
}
Python:
import random
class RandomizedSet(object): def __init__(self):
"""
Initialize your data structure here.
"""
self.dataMap = {}
self.dataList = [] def insert(self, val):
"""
Inserts a value to the set. Returns true if the set did not already contain the specified element.
:type val: int
:rtype: bool
"""
if val in self.dataMap:
return False
self.dataMap[val] = len(self.dataList)
self.dataList.append(val)
return True def remove(self, val):
"""
Removes a value from the set. Returns true if the set contained the specified element.
:type val: int
:rtype: bool
"""
if val not in self.dataMap:
return False
idx = self.dataMap[val]
tail = self.dataList.pop()
if idx < len(self.dataList):
self.dataList[idx] = tail
self.dataMap[tail] = idx
del self.dataMap[val]
return True def getRandom(self):
"""
Get a random element from the set.
:rtype: int
"""
return random.choice(self.dataList)
C++:
class RandomizedSet {
public:
/** Initialize your data structure here. */
RandomizedSet() {}
/** Inserts a value to the set. Returns true if the set did not already contain the specified element. */
bool insert(int val) {
if (m.count(val)) return false;
nums.push_back(val);
m[val] = nums.size() - 1;
return true;
}
/** Removes a value from the set. Returns true if the set contained the specified element. */
bool remove(int val) {
if (!m.count(val)) return false;
int last = nums.back();
m[last] = m[val];
nums[m[val]] = last;
nums.pop_back();
m.erase(val);
return true;
}
/** Get a random element from the set. */
int getRandom() {
return nums[rand() % nums.size()];
}
private:
vector<int> nums;
unordered_map<int, int> m;
};
类似题目:
[LeetCode] 381. Insert Delete GetRandom O(1) - Duplicates allowed 插入删除和获得随机数O(1)时间 - 允许重复
All LeetCode Questions List 题目汇总
[LeetCode] 380. Insert Delete GetRandom O(1) 插入删除获得随机数O(1)时间的更多相关文章
- LeetCode 380. Insert Delete GetRandom O(1)
380. Insert Delete GetRandom O(1) Add to List Description Submission Solutions Total Accepted: 21771 ...
- leetcode 380. Insert Delete GetRandom O(1) 、381. Insert Delete GetRandom O(1) - Duplicates allowed
380. Insert Delete GetRandom O(1) 实现插入.删除.获得随机数功能,且时间复杂度都在O(1).实际上在插入.删除两个功能中都包含了查找功能,当然查找也必须是O(1). ...
- [LeetCode] 380. Insert Delete GetRandom O(1) 常数时间内插入删除和获得随机数
Design a data structure that supports all following operations in average O(1) time. insert(val): In ...
- LeetCode 380. Insert Delete GetRandom O(1) (插入删除和获得随机数 常数时间)
Design a data structure that supports all following operations in average O(1) time. insert(val): In ...
- [leetcode]380. Insert Delete GetRandom O(1)常数时间插入删除取随机值
Design a data structure that supports all following operations in average O(1) time. insert(val): In ...
- LeetCode 380. Insert Delete GetRandom O(1) 常数时间插入、删除和获取随机元素(C++/Java)
题目: Design a data structure that supports all following operations in averageO(1) time. insert(val): ...
- [leetcode]380. Insert Delete GetRandom O(1)设计数据结构,实现存,删,随机取的时间复杂度为O(1)
题目: Design a data structure that supports all following operations in average O(1) time.1.insert(val ...
- [LeetCode] 381. Insert Delete GetRandom O(1) - Duplicates allowed 插入删除和获得随机数O(1)时间 - 允许重复
Design a data structure that supports all following operations in average O(1) time. Note: Duplicate ...
- LeetCode 381. Insert Delete GetRandom O(1) - Duplicates allowed O(1) 时间插入、删除和获取随机元素 - 允许重复(C++/Java)
题目: Design a data structure that supports all following operations in averageO(1) time. Note: Duplic ...
随机推荐
- ab 接口压力测试工具使用
安装: yum install httpd-tools 使用: ab -n 1000 -c 100 http://www.baidu.com/; -n 总的请求数; -c 并发数; -k 是否开启长 ...
- P1972 [SDOI2009]HH的项链[离线+树状数组/主席树/分块/模拟]
题目背景 无 题目描述 HH 有一串由各种漂亮的贝壳组成的项链.HH 相信不同的贝壳会带来好运,所以每次散步完后,他都会随意取出一段贝壳,思考它们所表达的含义.HH 不断地收集新的贝壳,因此,他的项链 ...
- RMQ问题及ST表
RMQ(Range Minimum/Maximum Query)问题指的是一类对于给定序列,要求支持查询某区间内的最大.最小值的问题.很显然,如果暴力预处理的话复杂度为 \(O(n^2)\),而此类问 ...
- 洛谷 P3469 [POI2008]BLO-Blockade 题解
一道经典的割点例题,用size数组记录该子树有多少个节点,sum是这棵搜索树上有多少个节点,sum*(n-sum-1)是将点删掉后的数对数量. #include<iostream> #in ...
- navicat设置唯一
https://blog.csdn.net/Song_JiangTao/article/details/82192189
- 后台增删改查的实现——java基础、jsp、servlet、数据库
1.前台和后台的关系: 后台是由工作人员操作的,通过后台系统对数据库实行增删改查等操作,通过前台系统访问数据库,将数据库中的信息通过前台显示. 2.功能实现: (1)显示全部商品信息: home.js ...
- hasura graphql-engine 最近版本的一些更新
好久没有在关注hasura graphql-engine 了,从最新的release 信息可以看到graphql-engine 已经beta 阶段了,而且目前是v1.0.0-beta.2 估计离生产可 ...
- 56、Spark Streaming: transform以及实时黑名单过滤案例实战
一.transform以及实时黑名单过滤案例实战 1.概述 transform操作,应用在DStream上时,可以用于执行任意的RDD到RDD的转换操作.它可以用于实现,DStream API中所没有 ...
- uni-app input text-indent失效解决
有两种方法去解决 第一种 input { padding-left: 10upt } 第二种 input { display: block }
- SpringBoot:关于默认连接池Hikari的源码剖析
1.起因 因为这两天在给公司的一个项目升级SpringBoot版本,遇到了一些坑,升级项目版本:SpringBoot1.5.x到SpringBoot2.0.x 今天早上双库操作遇到一个问题:jdbcU ...