An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to restore this property. Figures 1-4 illustrate the rotation rules.

 

 

Now given a sequence of insertions, you are supposed to tell the root of the resulting AVL tree.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (≤) which is the total number of keys to be inserted. Then Ndistinct integer keys are given in the next line. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print the root of the resulting AVL tree in one line.

Sample Input 1:

5
88 70 61 96 120

Sample Output 1:

70

Sample Input 2:

7
88 70 61 96 120 90 65

Sample Output 2:

88
#include<cstdio>
#include<algorithm>
using namespace std; struct Node{
int v;
int height;
Node* lchild;
Node* rchild;
}*root; int getHeight(Node* root);
void updateHeight(Node* root);
int getBalanceFactor(Node* root);
Node* NewNode(int v);
void Insert(Node* &root, int v);
void L(Node* &root);
void R(Node* &root); int main(){
int n,v;
scanf("%d",&n);
for(int i = ; i < n; i++){
scanf("%d",&v);
Insert(root,v);
}
printf("%d",root->v);
return ;
}
void Insert(Node* &root, int v){
if(root == NULL){
root = NewNode(v);
return;
}
if(root->v > v){
Insert(root->lchild,v);
updateHeight(root);
if(getBalanceFactor(root) == ){
if(getBalanceFactor(root->lchild) == ){
R(root);
}else if(getBalanceFactor(root->lchild) == -){
L(root->lchild);
R(root);
}
}
}else{
Insert(root->rchild,v);
updateHeight(root);
if(getBalanceFactor(root) == -){
if(getBalanceFactor(root->rchild) == -){
L(root);
}else if(getBalanceFactor(root->rchild) == ){
R(root->rchild);
L(root);
}
}
}
} Node* NewNode(int v){
Node* node = new Node;
node->v = v;
node->lchild = node->rchild = NULL;
node->height = ;
return node;
} void updateHeight(Node* root){
root->height = max(getHeight(root->lchild),getHeight(root->rchild))+;
} int getHeight(Node* root){
if(root == NULL) return ;
return root->height;
} int getBalanceFactor(Node* root){
return getHeight(root->lchild) - getHeight(root->rchild);
} void L(Node* &root){
Node* temp = root->rchild;
root->rchild = temp->lchild;
temp->lchild = root;
updateHeight(root);
updateHeight(temp);
root = temp;
} void R(Node* &root){
Node* temp = root->lchild;
root->lchild = temp->rchild;
temp->rchild = root;
updateHeight(root);
updateHeight(temp);
root = temp;
}

04-树5 Root of AVL Tree (25 分)的更多相关文章

  1. PTA 04-树5 Root of AVL Tree (25分)

    题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/668 5-6 Root of AVL Tree   (25分) An AVL tree ...

  2. PAT甲级:1066 Root of AVL Tree (25分)

    PAT甲级:1066 Root of AVL Tree (25分) 题干 An AVL tree is a self-balancing binary search tree. In an AVL t ...

  3. PAT 甲级 1066 Root of AVL Tree (25 分)(快速掌握平衡二叉树的旋转,内含代码和注解)***

    1066 Root of AVL Tree (25 分)   An AVL tree is a self-balancing binary search tree. In an AVL tree, t ...

  4. 1066 Root of AVL Tree (25分)(AVL树的实现)

    An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...

  5. 04-树5 Root of AVL Tree (25 分)

    An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...

  6. 【PAT甲级】1066 Root of AVL Tree (25 分)(AVL树建树模板)

    题意: 输入一个正整数N(<=20),接着输入N个结点的值,依次插入一颗AVL树,输出最终根结点的值. AAAAAccepted code: #define HAVE_STRUCT_TIMESP ...

  7. 04-树4. Root of AVL Tree (25)

    04-树4. Root of AVL Tree (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHEN, Yue An A ...

  8. pat04-树4. Root of AVL Tree (25)

    04-树4. Root of AVL Tree (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHEN, Yue An A ...

  9. pat 甲级 1066. Root of AVL Tree (25)

    1066. Root of AVL Tree (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue An A ...

  10. pat1066. Root of AVL Tree (25)

    1066. Root of AVL Tree (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue An A ...

随机推荐

  1. c++沉思录中 对字符串进行围边 横向连接 竖向连接操作的练习

    // MyPics.cpp : 定义控制台应用程序的入口点. // #include "stdafx.h" #include <string> #include < ...

  2. RabbitMQ client ( java )

    Maven 依赖 <dependency> <groupId>com.rabbitmq</groupId> <artifactId>amqp-clien ...

  3. Tempdb--monitoring and troubleshooting

    TempDB用来存放临时表.全局临时表.表变量以及排序或HASH等操作引发的中间结果集 TempDB在每次实例重启时重新创建,TempDB数据库文件的初始化大小取决于Model数据库的文件大小或显示A ...

  4. Sql里时间加减

    简单的时间加减 DATEADD(dd,-30, GETDATE())) 使用DateADD方法: 参数1:间隔,表示要添加的时间间隔,一天还是一月还是一年 参数2:要加或减的个数,加一年或加一月 参数 ...

  5. Impala源码之资源管理与资源隔离

    本文由  网易云发布. 前言 Impala是一个MPP架构的查询系统,为了做到平台化服务,首先需要考虑就是如何做到资源隔离,多个产品之间尽可能小的甚至毫无影响.对于这种需求,最好的隔离方案无疑是物理机 ...

  6. Android TextView 嵌套图片及其点击,TextView 部分文字点击,文字多颜色

    1. TextView 中嵌套图片的方法 TextView textView... textView.setText("..."); textView.append(Html.fr ...

  7. Mysql 优化与测试

    由于经常被抓取文章内容,在此附上博客文章网址:,偶尔会更新某些出错的数据或文字,建议到我博客地址 :  --> 点击这里 以下的测试数据根据环境的不同所耗费的时间有所不同,例如我在腾讯云上的测试 ...

  8. 关于布尔值bool值

    1.空或0布尔值为false,非0或非空为true 2.多个判断连在一起判断优先级:(括号)>not >and >or and:    print(27 and 1>4)  - ...

  9. JUC中Executor基本知识

    Future And Callable 引用 http://www.cnblogs.com/dolphin0520/p/3949310.html http://www.iocoder.cn/JUC/ ...

  10. html页面pc显示正常,在手机端适配也可以看整个页面

    <meta name="viewport" content="width=1250,initial-scale=0,maximum-scale=2"/&g ...