小 R 和室友小 B 在寝室里玩游戏.他们一共玩了 $n$ 局游戏,每局游戏的结果要么是小 R 获胜,要么是小 B 获胜. 第 $1$ 局游戏小 R 获胜的概率是 $p_1$,小 B 获胜的概率是 $1-p_1$.除了第一局游戏之外,每一局游戏小 R 获胜的概率与上一局游戏小 R 是否获胜有关. 具体来说: 如果第 $i-1\ (1< i\le n)$ 局游戏小 R 获胜,那么第 $i$ 局游戏小 R 获胜的概率为 $p_i$,小 B 获胜的概率为 $1-p_i$. 如果第 $i-1\ (1<…
新版Windows设置 详见 https://github.com/obsproject/obs-studio/wiki/Laptop-Troubleshooting 新版的Windows 10: latest Windows 10 builds overwrite the selection you make in the NVIDIA Control Panel. The setting is now accessible in the main Settings app (cog icon…
Partition Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2472 Accepted Submission(s): 978 Problem Description Define f(n) as the number of ways to perform n in format of the sum of some pos…
package com.hello.test; import java.util.Scanner; public class TestGame { public static void main(String[] args) { Player p = new Player() ; //实例化玩家对象 Game g = new Game(p) ;//实例化游戏对象 g.startGame();//调用方法 } } //游戏类 class Game { private Player p ; //设置…
