Problem C Updating a Dictionary】的更多相关文章

Problem C     Updating a Dictionary In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionary and a new dictionary, find out what were changed. Eac…
http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1113 1113: Updating a Dictionary Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 491  Solved: 121[Submit][Status][Web Board] Description In this problem, a dictionary is collection of key-value pairs, w…
  Updating a Dictionary  In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionary and a new dictionary, find out what were changed. Each dictionar…
UVA12504 - Updating a Dictionary 给出两个字符串,以相同的格式表示原字典和更新后的字典.要求找出新字典和旧字典的不同,以规定的格式输出. 算法操作: (1)处理旧字典,将旧字典中的每对关键字及其价值从字典串中截取出来,压入容器中.用做新旧字典对比检索. (2)处理新字典,将新字典中的每对关键字及其价值从字典串中截取出来.对于每个关键字,在容器中检索相同的关键字.若检索不成功,该关键字是新字典新增的,处理存储到相关的串数组中.若检索成功,提取容器中该关键字的价值与新…
题意:对比新老字典的区别:内容多了.少了还是修改了. 代码:(Accepted,0.000s) //UVa12504 - Updating a Dictionary //#define _XieNaoban_ #include<iostream> #include<sstream> #include<string> #include<vector> #include<map> using namespace std; int T; int mai…
传送门 Time Limit: 1000MS   Memory Limit: 131072KB   64bit IO Format: %lld & %llu Description In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionar…
In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionary and a new dictionary, find out what were changed. Each dictionary is formatting as follow…
题目链接:http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1113 解题报告:输入两个字符串,第一个是原来的字典,第二个是新字典,字典中的元素的格式为一个关键字对应一个值,输入格式如下: {a:3,b:4,c:10,f:6} {a:3,c:5,d:10,ee:4}冒号前面的表示关键字,冒号后面的数字表示值,关键字由小写字母组成.现在让你判断,如果新的字典相对于原来的字典有新增的关键字以以下格式输出 :+key1,key2,....如果新的字典相对…
大致题意:用{ key:value, key:value, key:value }的形式表示一个字典key表示建,在一个字典内没有重复,value则可能重复 题目输入两个字典,如{a:3,b:4,c:10,f:16}  {a:3,c:5,d:10,ee:4} 于新字典相比,找出旧字典的不同,并且输出用相应格式,增加的用'+',如 +d,ee 减少的用'-',如 -b,f value变化的用*,如 *c 没有不同则输出"No changes"" 如果使用java,则可以用Tre…
全是字符串相关处理,截取长度等相关操作的练习 AC代码: #include <iostream> #include <cstdio> #include <cstdlib> #include <cctype> #include <cstring> #include <string> #include <sstream> #include <vector> #include <set> #include…
题目 题目     分析 第一次用stringstream,真TMD的好用     代码 #include <bits/stdc++.h> using namespace std; int main() { int n; cin>>n; getchar();//回车 while(n--) { string s1,s2; getline(cin,s1); getline(cin,s2); for(int i=0;i<s1.length();i++) if(!isalpha(s1…
题目描述: 解题思路: 1.根据:和,获得字符串 2.使用两个map进行比较: #include <iostream> #include <algorithm> #include <string> #include <map> using namespace std; map<string, string>::iterator it; map<]; ]; int main(int argc, char *argv[]) { int t ;…
[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 不确定某个map里面是否有某个关键字的时候. 要用find来确定. 如果直接用访问下标的形式去做的话. 会强行给他加一个那个关键字(原来没有). (当然那个关键字的映射为空就是了); [代码] #include <bits/stdc++.h> using namespace std; string s; map<string, string> mmap1, mmap2; vector <string>…
A 三家人 Description 有三户人家共拥有一座花园,每户人家的太太均需帮忙整理花园.A 太太工作了5 天,B 太太则工作了4 天,才将花园整理完毕.C 太太因为正身怀六甲无法加入她们的行列,便出了90元.请问这笔钱如何分给A.B 二位太太较为恰当?A 应得多少元?90/(5+4)*5=$50 元?如果这么想你就上当了!正确答案是60 元.如果没想通的话再想想吧. 下面回答一个一般性的问题:假定A 太太工作了x 天,B 太太工作了y 天,C 太太出了90元,则A 太太应得多少元?输入保证…
上一节分析到了JobTracker把作业从队列里取出来并进行了初始化,所谓的初始化,主要是获取了Map.Reduce任务的数量,并统计了哪些DataNode所在的服务器可以处理哪些Split等等,将这些信息缓存起来,但还没有进行实质的分配.等待TaskTracker跟自己通信. TaskTracker一般运行于DataNode之上,下面是它的声明,可见,是一个线程类: /******************************************************* * TaskT…
前言 :本文旨在理清在Hadoop中一个MapReduce作业(Job)在提交到框架后的整个生命周期过程,权作总结和日后参考,如有问题,请不吝赐教.本文不涉及Hadoop的架构设计,如有兴趣请参考相关书籍和文献.在梳 理过程中,我对一些感兴趣的源码也会逐行研究学习,以期强化基础. 作者 :Jaytalent 开始日期 :2013年9月9日 参考资料:[1]<Hadoop技术内幕--深入解析MapReduce架构设计与实现原理>董西成                   [2]   Hadoop…
链接地址:http://stackoverflow.com/questions/18735847/ios-7-auto-layout-on-ios-versions-prior-to-6-0 Stack Overflow is a question and answer site for professional and enthusiast programmers. It's 100% free, no registration required. iOS 7 - Auto Layout on…
Up-to-date cache with EclipseLink and Oracle One of the most useful feature provided by ORM libraries is a second-level cache, usually called L2. L2 object cache reduces database access for entities and their relationships. It is enabled by default i…
Update Entity Graph using DbContext: Updating an entity graph in disconnected scenario is a complex task. It is easy to add a new entity graph in disconnected mode, but to update an entity graph needs careful design consideration. The problem in upda…
一.前言 今天事不是很多,正好在Java交流群里,看到一个比较有意思的问题,于是花了点时间研究了一下,这里做个简单的分享. 先贴一份测试代码,大家可以先猜测一下,执行结果会是怎样的: import java.util.concurrent.TimeUnit; public class TestClassLoading { public static class A{ static { System.out.println("class A init"); try { TimeUnit.…
Problem C: Andy’s First DictionaryTime Limit: 1 Sec Memory Limit: 128 MBSubmit: 18 Solved: 5[Submit][Status][Web Board]DescriptionAndy, 8, has a dream – he wants to produce his very own dictionary. This is not an easy task for him, as the number of w…
题目链接:Problem C 题意:输入一个文本,找出所有不同的单词,按照字典序从小到大输出,单词不区分大小写. 思路:将字母序列都存为小写,非字母的字符变成空格,然后利用stringstream实现sting对象的自动格式化. note: stringstream对象的使用 #include<sstream> #include<iostream> using namespace std; int main() { string line,word; while(getline(c…
Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…
It's my new PC with a new os of ubuntu. every time when I want to install software or update apt-get, this error will appear: First, as the most usual functions the website given: to type these commands: sudo rm /var/lib/apt/lists/* -vf sudo apt-get…
运行 eclipse 把 eclipse exe 修改为 eclipse.exe.back 再运行 updates 升级成功…
Hi Dear Today we will use tensorflow to implement the softmax regression and linear classifier algorithm. not using the library of tensorflow (like tf.nn.softmax), but using tensorflow simple function to implement the softmax. The whole structure of…
转自: http://icesquare.com/wordpress/mysql-starting-mysql-error-the-server-quit-without-updating-pid-file/ 他也是更新系统后出现的这个问题,我是更新之后出现的该问题,所以按照他的思路删掉配置文件就可以启动了,至于为什么会出现这种问题,回头有时间再仔细研究下. This step-by-step guide is mainly for FreeBSD, however the idea is th…
Refresh / Updating a form screen in Oracle D2k Forms 6i ProblemYou want to show number of records processed progress or a progress bar on form through a procedure. SolutionDeclare  nTotalRec Number := 10000;  nCurrRec Number := 1;Begin   For i in 1..…
感觉这道题要比之前几个字符串处理的题目难度要大了一些. 题目大意:给若干行字符串,提取出所有单词并去掉重复的,最后按字典顺序输出. 对于输入大致有两种思路,一种是逐个读入字符,遇到字母的话就放到word里面,直到遇到非字母字符,在word最后放'\0'. 我采用第二种思路,就是用gets()函数逐行读到str字符数组里面,然后逐个把单词提取出来. Count存放的是Dictionary里单词的个数,每提取一个单词,看看Dictionary里有没有该单词,没有的话放到字典里面,并且计数器加1. 由…
Hard problem 题目链接: http://codeforces.com/contest/706/problem/C Description Vasiliy is fond of solving different tasks. Today he found one he wasn't able to solve himself, so he asks you to help. Vasiliy is given n strings consisting of lowercase Engl…