Galaxy Problem's Link:   http://acm.hdu.edu.cn/showproblem.php?pid=5073 Mean: 在一条数轴上,有n颗卫星,现在你可以改变k颗卫星的位置,使得剩下的n-k颗卫星到某个点(不固定)的距离的平方和最小. 抽象成数学语言后等价于:数轴上有n个点,现在去掉k个点,使得剩下的n-k个点的方差最小,求方差*n的值. analyse: 一道让人很容易想偏的数学题.首先说一下我的思路: 1)我们最终的目的是让这n-k个点尽量的集中,所以去…

Hatsune Miku Problem's Link:   http://acm.hdu.edu.cn/showproblem.php?pid=5074 Mean: 有m种音符(note),现在要从这m种音符中选出n个来组成一首歌,相邻两个音符之间会有一个评分的方式,即score(i,j),而score(i,j)题目已经给出,现在要你按照题目的规定来选出n个音符来使得最终的分数最高. analyse: 鞍山赛区第二大水题,很简单的dp. 具体思路:dp[i][j]表示第i个音符选择的是第j种.…

Osu! Problem's Link:   http://acm.hdu.edu.cn/showproblem.php?pid=5078 Mean: 略. analyse: 签到题,直接扫一遍就得答案,但是现场赛的时候也是卡了好久,估计队友也是被爆int坑了吧. Time complexity: O(n) Source code:  // Memory Time // 1347K 0MS // by : Snarl_jsb // 2014-11-15-10.58 #include<algori…

推公式 #include <cstdio> #include <cmath> #include <iomanip> #include <iostream> #include <algorithm> using namespace std; typedef long long ll; const int N = 50000+3; ll a[N], b[N]; int main() { int T, n, m, len; ll x, sum, ans…

简单dp #include <stdio.h> #include <cstring> #include <iostream> #include <map> using namespace std; typedef unsigned long long ull; const int N = 105; int n, m, a[N]; int s[N][N], dp[2][N]; void pt(int x ){ for(int i = 1; i <= m;…

模拟题: add的时候出现过的则不再添加 close的时候会影响到top rotate(Prior.Choose)的时候会影响到top /*=============================================================== * Copyright (C) 2014 All rights reserved. * * File Name: hdu5071.cpp * Author:sunshine * Created Time: 2014-11-11 *…

最后一次参加亚洲区…… 题意:给出n(3 ≤ n ≤ 105)个数字,每个数ai满足1 ≤ ai ≤ 105,求有多少对(a,b,c)满足[(a, b) = (b, c) = (a, c) = 1] or [(a, b) ≠ 1 and (a, c) ≠ 1 and (b, c) ≠ 1],都互素或都不互素. 思路:如果是两个数,互素比较好求,边遍历边分解质因子,利用容斥原理即可知道前面与自己互素的有多少.left_prime[i]表示左边与自己互素的,left_no_prime[i]表示左边与…

题目I - Osu! - HDU 5078 题目分析:最水的一道题吧,求两点间的距离和时间差值的最大比值 #include<stdio.h> #include<math.h> #include<algorithm> using namespace std; ; ; struct Point { double x, y, time; }; double Dist(Point a, Point b) { return sqrt((a.x-b.x)*(a.x-b.x)+(a.…

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5150 题目大意:给一幅N个点M条边的无向图,有一些边,其中一部分只能涂红色,一部分只能涂黑色,一部分两种颜色都可以涂.现要求红色的边不超过K条的生成树个数模1e9+7的值. 思路:感谢昂神滋磁,贴链接:http://sd-invol…

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5155 There are N guests checking in at the front desk of the hotel. 2K (0 ≤ 2K ≤ N) of them are twins.There are M room…

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5153 In an infinite chess board, some pawns are placed on some cells.You have a rectangular bomb that is W width and H…

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5159 In normal football games, the winner team gets 3 points, loser team gets 0 point, and if there is a drawgame, bot…

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5151You have a rectangle of size N × M, N rows from top to bottom and M columns from left to right,that is divided int…

Long long ago there is a strong tribe living on the earth. They always have wars and eonquer others.One day, there is another tribe become their target. The strong tribe has decide to terminate them!!!There are m villages in the other tribe. Each vil…

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5160 There is a tree with N nodes, and every node has a weighted value. A RIP (restricted increasing path)is a directe…

Galaxy Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 556    Accepted Submission(s): 127 Special Judge Problem Description Good news for us: to release the financial pressure, the government…

Galaxy                                                                   Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)                                                                                  Total Subm…

主题链接:http://acm.hdu.edu.cn/showproblem.php? pid=5073 Galaxy Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 768    Accepted Submission(s): 179 Special Judge Problem Description Good news for…

主题链接:http://acm.hdu.edu.cn/showproblem.php? pid=5073 Galaxy Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 768    Accepted Submission(s): 179 Special Judge Problem Description Good news for…

HDU 5073 Galaxy (2014 Anshan D简单数学) 题目链接http://acm.hdu.edu.cn/showproblem.php?pid=5073 Description Good news for us: to release the financial pressure, the government started selling galaxies and we can buy them from now on! The first one who bought…

The 2014 ACM-ICPC Asia Mudanjiang Regional Contest A.Average Score B.Building Fire Stations C.Card Game D.Domination E.Excavator Contest F.Fiber-optic Network G.Garden and Sprinklers H.Hierarchical Notation I.Information Entropy J.Jacobi Pattern K.Kn…

The 2014 ACM-ICPC Asia Mudanjiang Regional Contest 题目链接 没去现场.做的网络同步赛.感觉还能够,搞了6题 A:这是签到题,对于A堆除掉.假设没剩余在减一.B堆直接除掉 + 1就能够了 B:二分贪心,二分长度.然后会发现本质上是在树上最长链上找两点,那么有二分出来的长度了,就从两端分别往里移动那么长,那两个位置就是放置位置.然后在推断一下就能够了 D:概率DP.首先知道放一个棋子.能够等价移动到右上角区域,那么就能够dp[x][y][k],表示…

GCC Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 3867    Accepted Submission(s): 1272 Problem Description The GNU Compiler Collection (usually shortened to GCC) is a compiler system produc…

WHUgirls Time Limit: 3000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 2068    Accepted Submission(s): 785 Problem Description There are many pretty girls in Wuhan University, and as we know, every girl lo…

Conquer a New Region Time Limit: 5 Seconds      Memory Limit: 32768 KB The wheel of the history rolling forward, our king conquered a new region in a distant continent. There are N towns (numbered from 1 to N) in this region connected by several road…

摘要 本文主要给出了2018 ACM-ICPC Asia Beijing Regional Contest的部分题解,意即熟悉区域赛题型,保持比赛感觉. Jin Yong’s Wukong Ranking List 题意 输入关系组数n和n组关系,每组关系是s1 > s2,问第一出现矛盾的组,或者没有矛盾就输出0. 解题思路 第一感觉是拓扑排序,未完,又写了一个深搜的传递闭包,1 A,和2018年河南省赛的题很像. 代码 #include <cstdio> #include <ma…

摘要 本文主要给出了2014-2015 ACM-ICPC, Asia Xian Regional Contest的部分题解,说明了每题的题意.解题思路和代码实现,意即熟悉区域赛比赛题型. Built with Qinghuai and Ari Factor 题意 判断是否是Q数列,只要数列中每个数均能够被3整除就是Q数列. 解题思路 需要特判一下0的情况. 代码 #include <cstdio> int main() { int T; int n; ; scanf("%d"…

摘要: 本文是The 2018 ACM-ICPC Asia Qingdao Regional Contest(青岛现场赛)的部分解题报告,给出了出题率较高的几道题的题解,希望熟悉区域赛的题型,进而对其他区域赛的准备有借鉴意义. Function and Function 题意 给出x和k,计算gk(x). 解题思路 通过观察发现,g函数经过一定次数的递推一定会在0和1之间变换,所以循环内加判断提前结束递推即可. 易错分析 注意计算f(0)返回的是1的问题,下面的写法避免了这种错误. 代码实现 #…

The 2018 ACM-ICPC Asia Qingdao Regional Contest 青岛总体来说只会3题 C #include<bits/stdc++.h> using namespace std; #define maxn 3000005 char a[maxn],b[maxn]; int c[maxn],ll[maxn],rr[maxn]; int main(){ int t; cin>>t; while(t--){ int n; scanf("%d&qu…

2017-2018 ACM-ICPC, Asia Tsukuba Regional Contest A Secret of Chocolate Poles 思路:暴力枚举黑巧克力的个数和厚黑巧克力的个数 代码: #pragma GCC optimize(2) #pragma GCC optimize(3) #pragma GCC optimize(4) #include<bits/stdc++.h> using namespace std; #define fi first #define s…