题目链接: 传送门 Graph Construction Time Limit: 3000MS Memory Limit: 65536K Description Graph is a collection of edges E and vertices V. Graph has a wide variety of applications in computer. There are different ways to represent graph in computer. It can…
题目链接: 题目 Graph Construction Time limit: 3.000 seconds 问题描述 Graph is a collection of edges E and vertices V. Graph has a wide variety of applications in computer. There are different ways to represent graph in computer. It can be represented by adjace…
Description You are to write a program that tries to find an optimal coloring for a given graph. Colors are applied to the nodes of the graph and the only available colors are black and white. The coloring of the graph is called optimal if a maximum…
Pool construction You are working for the International Company for Pool Construction, a construction company whichspecializes in building swimming pools. A new client wants to build several new pool areas.A pool area is a rectangular grid of w × h s…
Lily: “Chantarelle was part of my exotic phase.”Buffy: “It’s nice. It’s a mushroom.”Lily: “It is? That’s really embarrassing.”Buffy: “Well, it’s an exotic mushroom, if that’s any comfort.”Joss Whedon, "Anne".A little girl whose name is Anne Spetri…
题意: 给一个h*w的矩阵,每个格子中是'#'和'.'两个符号之一,分别代表草和洞.现在要将洞给围起来(将草和洞分离),每条边需花费b元(即将一个洞包起来需要4边,将2个连续的洞包起来需要6边,省了2条边).有个特殊能力,能将洞变成草,花费f.当然也能将草变成洞,花费d.围起洞来需要多少花费.矩阵四周最边边的格子都必须是草,即出现洞就必须转草. 转换:洞--->草--->洞 f d (元/格) 围洞: b元/边. 思路: 如果能够尽量让洞都靠在一起,那肯定是最小花费,因为少了…
题意:图上的点染色,给出的边的两个点不能都染成黑色,问最多可以染多少黑色. 很水的一题,用dfs回溯即可.先判断和当前点相连的点是否染成黑色,看这一点是否能染黑色,能染色就分染成黑色和白色两种情况递归,如果不能就单递归白色. 代码: #include <cstdio> #include <cstring> const int maxn = 110; int cas, v, e, M; bool g[maxn][maxn]; int color[maxn], rec[maxn]; v…
题意: 给一个无向图,再给一系列操作(以下3种),输出最后的平均查询结果. (1)D X 删除第x条边. (2)Q X k 查询与点X相连的连通分量中第k大的点的权值. (3)C X v 将点X的权值改为v. 思路: 第一点,由于需要删除边,不是很方便,所以可以先将所有操作存起来,反序来操作,这样删边就变成加边,方便了不少.每次加边时若两点不属于同个连通分量,就将点少的整个连通分量中的点逐个插入到另一个连通分量中. 第二点,查第k大,这个比较简单,只需要维护Treap上每个点的的左右孩子数量…
题目链接:E - New Year and the Acquaintance Estimation 题解参考: Havel–Hakimi algorithm 和 Erdős–Gallai theorem 按照后面那个定理说的,枚举$k∈[1,n]$,对于每一个$k$,计算出向等式两边加入$a_{n+1}$的合法范围,最后所有范围求交即可 最后按照前面那个定理说的,枚举最终区间的时候,对于合法真正的$a_{n+1}$进行输出即可 比赛的时候没看见后面那个定理,推了半天 --------------…
@http://www-cs-faculty.stanford.edu/people/karpathy/cvpr2015papers/ CVPR 2015 papers (in nicer format than this) maintained by @karpathy NEW: This year I also embedded the (1,2-gram) tfidf vectors of all papers with t-sne and placed them in an interf…
Large Scale Distributed Semi-Supervised Learning Using Streaming Approximation Google 2016.10.06 官方 Blog 链接:https://research.googleblog.com/2016/10/graph-powered-machine-learning-at-google.html 今天讲的是一个基于 streaming approximation 的大规模分布式半监督学习框架,出自 Goo…
Graph-powered Machine Learning at Google Thursday, October 06, 2016 Posted by Sujith Ravi, Staff Research Scientist, Google ResearchRecently, there have been significant advances in Machine Learning that enable computer systems to solve compl…
用后感: 拼个小基因组还好,对于很大的基因组,文库很多的,还是不要用了.服务器768G内存,都不够用.... 主页: http://bioinf.spbau.ru/spades 说明书: http://spades.bioinf.spbau.ru/release3.6.1/manual.html Note, that SPAdes was initially designed for small genomes. It was tested on single-cell and standard…
转自:https://dev.to/alagrede/why-i-dont-want-use-jpa-anymore-fl Great words for what is considered by many as the greatest invention in the Java world. JPA is everywhere and it is inconceivable today to writing a Java application without him. Neverthel…
1)背景 组装:短的reads通过overlap来组装成contig 局限性:repeat 大于overlap导致ambiguous reconstructions and fragment the assembly 两个策略:increasing the effective read length(增加reads长度), and separating nonexact repeats based on copy-specific variants(通过特定的copy-变异分离repeats)…
Effective TensorFlow Table of Contents TensorFlow Basics Understanding static and dynamic shapes Scopes and when to use them Broadcasting the good and the ugly Feeding data to TensorFlow Take advantage of the overloaded operators Understanding order…
