1067 Sort with Swap(0, i) (25 分)   Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may…

Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the fo…

Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the fo…

题意: 输入一个正整数N(<=100000),接着输入N个正整数(0~N-1的排列).每次操作可以将0和另一个数的位置进行交换,输出最少操作次数使得排列为升序. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ],b[]; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(…

题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/678 5-16 Sort with Swap(0, i)   (25分) Given any permutation of the numbers {0, 1, 2,..., N-1N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is…

Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the fo…

题目 Given any permutation of the numbers {0, 1, 2,-, N-1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the f…

Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the fo…

一.技术总结 题目要求是,只能使用0,进行交换位置,然后达到按序排列,所使用的最少交换次数 输入时,用数组记录好每个数字所在的位置. 然后使用for循环,查看i当前位置是否为该数字,核心是等待0回到自己的位置上,如果没有一直与其他的数字进行交换.如果这个过程中,i回到自己位置上就不用调换,如果不是那么直接与0位置进行调换,直到所有位置都到指定位置上面. 二.参考代码 #include<iostream> #include<algorithm> using namespace std…

题目链接:1067 Sort with Swap(0, i) (25 分) 题意 给定长度为 \(n\) 的排列,如果每次只能把某个数和第 \(0\) 个数交换,那么要使排列是升序的最少需要交换几次. 思路 贪心 由于是排列,所以排序后第 \(i\) 个位置上的数就是 \(i\).所以当 \(a[0] \neq 0\) 时,把 \(a[0]\) 位置上的元素交换到相应位置.如果 \(a[0] = 0\),就找到第一个不在正确位置上的数,把它与第 \(0\) 个数交换,那么下一次又是第一种情况了,…

1067. Sort with Swap(0,*) (25)   Given any permutation of the numbers {0, 1, 2,..., N-1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may ap…

题目信息 1067. Sort with Swap(0,*) (25) 时间限制150 ms 内存限制65536 kB 代码长度限制16000 B Given any permutation of the numbers {0, 1, 2,-, N-1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For exa…

1067 Sort with Swap(0, i) (25 分) Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may ap…

PAT甲级:1066 Root of AVL Tree (25分) 题干 An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to rest…

时间限制 150 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given any permutation of the numbers {0, 1, 2,..., N-1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example…

传送门:点我 Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in…

Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the fo…

Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the fo…

1002 A+B for Polynomials (25 分) This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial…

1079 Total Sales of Supply Chain (25 分)   A supply chain is a network of retailers(零售商), distributors(经销商), and suppliers(供应商)-- everyone involved in moving a product from supplier to customer. Starting from one root supplier, everyone on the chain b…

只对没有归位的数进行交换. 分两种情况: 如果0在最前面,那么随便拿一个没有归位的数和0交换位置. 如果0不在最前面,那么必然可以归位一个数字,将那个数字归位. 这样模拟一下即可. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include…

贪心算法 次数最少的方法,即:1.每次都将0与应该放置在0位置的数字交换即可.2.如果0处在自己位置上,那么随便与一个不处在自己位置上的数交换,重复上一步即可.拿样例举例:   0 1 2 3 4 5 6 7 8 90:3 5 7 2 6 4 9 0 8 1 1:3 5 0 2 6 4 9 7 8 12:3 5 2 0 6 4 9 7 8 13:0 5 2 3 6 4 9 7 8 1 (如果0处在自己位置上,那么找一个不在自己位置上的数val与之交换)4:5 0 2 3 6 4 9 7 8 15…

题意: 输入一个正整数N(<=10),接着输入0~N-1每个结点的左右儿子结点,输出这颗二叉树的反转的层次遍历和中序遍历. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ][]; ]; void bfs(int r){ queue<int>q; q.push(r); cout<<r; while(!q.empty()){ in…

题意: 输入一个九位整数,输出它的汉字读法(用拼音表示). trick: 字符串数组""其实会输出一个空格,而不是什么都不输出,导致测试点0和4格式错误. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; ]={"","yi","er","san",&qu…

题意: 输入两个正整数N和K(N<=1e5,K<=1000),接着输入N行,每行包括一位老板的名字,年龄和财富.K次询问,每次输入三个正整数M,L,R(M<=100,L,R<=200),输出至多M位年龄区间在L,R之间的老板的名字年龄和财富,按照财富降序,年龄升序,姓名字典序输出. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; st…

题意: 输入两个正整数N和K(N<=40000,K<=2500),接下来输入N行,每行包括一个学生的名字和所选课程的门数,接着输入每门所选课程的序号.输出每门课程有多少学生选择并按字典序输出学生的名字. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; vector<]; int main(){ ios::sync_with_stdio…

题意: 输入两个正整数N和K(N<=40000,K<=2500),分别为学生和课程的数量.接下来输入K门课的信息,先输入每门课的ID再输入有多少学生选了这门课,接下来输入学生们的ID.最后N次询问,输入学生的ID输出该学生选了多少们课,输出所选课程的数量,按照递增序输出课程的ID. trick: 第5个数据点出现段错误,把原本以map存学生对应ID再映射vector存储该学生所选课程改成vector嵌套在map内,就没有段错误的问题出现,疑似映射过程中指针漂移??? AAAAAccepted…

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6803291.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 题意:给你一个插入的序列,问你最后AVL树的根节点是多少 AVL树模板题如果会AVL树,那么就是水题如果不会的话,那么就是难题我刚开始也不会,所以根本写不出来AVL树...后来花了一些时间学习了下,感觉网上很多模板都是用class写的,太麻烦了模板就是应该要…

1029 Median (25 分)   Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1 = { 11, 12, 13, 14 } is 12, and the median of S2 = { 9, 10, 15, 16, 17 } is 15. The median of two sequen…

题意: 输入一个正整数N(<=20),接着输入N个结点的值,依次插入一颗AVL树,输出最终根结点的值. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; typedef struct node{ int val; node*left,*right; }; node*left_rotate(node*root){ node*tamp=root->…