POJ 1064_Cable master】的更多相关文章

题意: 给定一系列长度的电缆,将他们切成K条相等长度的电缆,问每条最长有多长? 分析: 对长度进行二分,判断能否满足K条. 二分搜索: 在求解最大化或最小化问题中,能够比较简单的判断条件是否满足,那么使用二分搜索法可以很好地解决问题. 结束判定: 正常处理整数时,对于[l,r)结束范围即为l=r,但是小数的处理就涉及精度的要求了. 在输出小数时,需要设置合理的结束条件满足精度的要求,可以指定循环次数作为终止条件,一次循环把区间的范围缩小一半,100次的循环可达到10−30的精度范围.也可以把终止…
Dungeon Master Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 16748   Accepted: 6522 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled…
Dungeon Master Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 25379   Accepted: 9856 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled…
Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot m…
Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot m…
本文为原创,转载请注明:http://www.cnblogs.com/kylewilson/ 题目出处: http://poj.org/problem?id=2533 题目描述: 如果ai1 < ai2 < ... < aik ,1 <= i1 < i2 < ... < iK <= N,则该序列为有序:给一个序列,找出一个最长的上升序列,如 (a1, a2, ..., aN)有一个上升序列为 (ai1, ai2, ..., aiK),1 <= i1 &…
本文为原创,转载请注明:http://www.cnblogs.com/kylewilson/ 题目出处: http://poj.org/problem?id=1088 题目描述: 区域由一个二维数组给出.数组的每个数字代表点的高度.如下: 1 2 3 4 5 16 17 18 19 6 15 24 25 20 7 14 23 22 21 8 13 12 11 10 9 一个人可以从某个点滑向上下左右相邻四个点之一,当且仅当高度减小.在上面的例子中,一条可滑行的滑坡为24-17-16-1.当然25…
本文为原创,转载请注明:http://www.cnblogs.com/kylewilson/ 题目出处: http://poj.org/problem?id=3468 题目描述: 给N个数A1, A2, ... , AN. 你需要处理两种操作,一种操作是在一个区间上每个数都增加一个数,别一种操作是查询一个区间所有数的和 输入 第一行两个数N, Q, 1 ≤ N,Q ≤ 100000 第二行N个数,数组初始值A1, A2, ... , AN. -1000000000 ≤ Ai ≤ 10000000…
http://poj.org/problem?id=2251 Dungeon Master Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 18773   Accepted: 7285 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes…
POJ 2251 题目大意: 给出一三维空间的地牢,要求求出由字符'S'到字符'E'的最短路径,移动方向可以是上,下,左,右,前,后,六个方向,每移动一次就耗费一分钟,要求输出最快的走出时间.不同L层的地图,相同RC坐标处是相连通的.(.可走,#为墙) 解题思路:从起点开始分别往6个方向进行BFS(即入队),并记录步数,直至队为空.若一直找不到,则困住. /* POJ 2251 Dungeon Master --- 三维BFS(用BFS求最短路) */ #include <cstdio> #i…