iphone dev 入门实例2:Pass Data Between View Controllers using segue
Assigning View Controller Class
In the first tutorial, we simply create a view controller that serves as the detail view of recipe in the Storyboard editor. The view controller is assigned with the UIViewController class by default.
Default View Controller - UIViewController
Let’s revisit our problem. The label in the view should be changed with respect to the selected recipe. Obviously, there must be a variable in the UIViewController for storing the name of recipe.
The fact is the UIViewController class only provides the fundamental view management model. It corresponds to a blank view. There is no variable assigned for storing the recipe name. Thus, instead of using UIViewController directly, we extend from it and create our own class (known as the subclass of UIViewController).
In the Project Navigator, right-click the “RecipeBook” folder and select “New File…”.
Create New File in Xcode Project
Choose “Objective-C Class” under Cocoa Touch as the class template.
Select Objective C Class
Name the class as “RecipeDetailViewController” and it’s a subclass of “UIViewController”. Make sure you uncheck the option of “With XIB for user interface”. As we’re using Storyboards for designing the user interface, we do not need to create a separate interface builder file. Click “Next” and save the file in your project folder.
Create a RecipeDetailViewController class (Subclass of UIViewController)
Next, we have to assign the RecipeDetailViewController class to the view controller. Go back to the Storyboards editor and select the detail view controller. In the identity inspector, change the class to “RecipeDetailViewController”.
Change View Controller Class
Adding Variables to the Custom Class
We’ve just created our custom view controller class by extending from the UIViewController class. However, it doesn’t differ from the parent class until we add our own variables and methods. There are a couple of things we have to change:
- Assign a variable (recipeName) for data passing – when user selects a recipe in the Recipe view, there must be a way to pass the name of recipe to the detail view.
- Assign a variable (recipeLabel) for the text label – presently the label is static. It should be updated as the name of recipe changes.
Okay, let’s add these two variables (recipeLabel and recipeName). Select the “RecipeDetailViewController.h” and adds two properties for the interface:
|
1
2 3 4 5 6 |
@interface RecipeDetailViewController : UIViewController
@property (nonatomic, strong) IBOutlet UILabel *recipeLabel; @end |
Go to the “RecipeDetailViewController.m” and add the synthesis for the variables. Make sure you place the code under “@implementation RecipeDetailViewController”:
|
1
2 3 4 |
@implementation RecipeDetailViewController
@synthesize recipeLabel; |
Establish a Connection Between Variable and UI Element
Next, we have to link up the “recipeLabel” variable with the visual Label. In the Storyboards editor, press & hold the command key and then click the “Recipe Detail View Controller” icon, drag it to the Label object. Release both buttons and a pop-up shows variables for your selection. Choose the “recipeLabel” variable.
Establish the Connection between UI element and Variable
That’s it. Now you’ve linked up the variable with the Label UI element. Any change in the variable will be reflected visually. But there is still one thing left. We want to have the label to display the recipe name. So in viewDidLoad function, we add the following code that sets the label text the same as the recipe name.
|
1
2 3 4 5 6 |
- (void)viewDidLoad
{ [super viewDidLoad]; // Set the Label text with the selected recipe recipeLabel.text = recipeName; } |
Try to compile and run your app. Oops! The detail view is completely blank after selecting any recipe. That’s the expected behavior. We haven’t written any code to pass along the recipe name. Yet, the “recipeName” variable is blank that contributes to the empty text label.
Receipe App with Empty Detail Controller
Passing Data Using Segue
This comes to the core part of tutorial about how to pass data between view controller using Segue. Segues manages the transition between view controllers. On top of this, segue objects are used to prepare for the transition from one view controller to another. When a segue is triggered, before the visual transition occurs, the storyboard runtime invokes prepareForSegue:sender: method of the current view controller (in our example, it’s the RecipeBookViewController). By implementing this method, we can pass any needed data to the view controller that is about to be displayed.
However, the best practice is to give each segue in your Storyboards an unique identifier. This identifier is a string that your application uses to distinguish one segue from another. As your app becomes more complex, it’s likely you’ll have more than one segue in the view controllers.
To assign the identifier, select the segue and set it in the identity inspector. Let’s name the segue as “showRecipeDetail”.
Storyboard Segue Identifier
Next, we’ll implement the prepareForSegue:sender: method in “Recipe Book View Controller”, which is the source view controller of the segue. Select the “RecipeBookViewController.m” and add the following code:
|
|
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
if ([segue.identifier isEqualToString:@"showRecipeDetail"]) { NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow]; RecipeDetailViewController *destViewController = segue.destinationViewController; destViewController.recipeName = [recipes objectAtIndex:indexPath.row]; } } |
The prepareForSegue method will be called when the transition begins. The 1st line is used to verify the identifier of segue. In this case, the identifier is “showRecipeDetail”. The 2nd line of code invokes the tableView:indexPathForSelectedRow to retrieve the selected table row. Once we have the selected row, we’ll pass it to the RecipeDetailViewController. A Segue object contains the view controller whose contents should be displayed at the end of the segue. You can always use “segue.destinationViewController” to retrieve the destination controller. In this case, the destination controller is the RecipeDetailViewController. The rest of the code is to pass the recipe name to the destination controller.
You can’t run your app right now. After you copy & paste the above method into RecipeBookViewController.m, you should see a number of errors.
prepareForSegue Error
There are three errors as shown above. But we can summarize them into two:
- The property “tableView” is not found in RecipeDetailViewController.
- What’s RecipeDetailViewController? Xcode doesn’t know what it is.
Let’s talk about the second error first. In RecipeBookViewController, it has no idea about RecipeDetailViewController. In Objective C, you use the “#import” directive to import the header file of other class. By importing the header file of “RecipeDetailViewController”, RecipeBookViewController can access the properties and methods of the detail view controller. Place the following code at the very beginning to fix the error:
|
1
|
#import "RecipeDetailViewController.h"
|
Regarding the first error, you should know how to fix it. This is similar to the Label UI element we discussed earlier. There should be a corresponding tableView variable that connects with the UI element.
So, in the RecipeBookViewController.h, add the following code before “@end”:
|
1
|
@property (nonatomic, strong) IBOutlet UITableView *tableView;
|
For the RecipeBookViewController.m, add the synthesis directive to tell the compiler to generate the accessor methods for the tableView variable.
|
1
2 3 4 5 |
@implementation RecipeBookViewController {
NSArray *recipes; } @synthesize tableView; // Add this line of code |
Lastly, go back to the Storyboards and link up the variable with the UI element. In the “Recipe Book View Controller”, hold the command key and click the view controller icon, drag it to the table view. Release both buttons and select “tableView”.
Establish connection with the tableView variable
Now, all the errors should be resolved. Let’s try to compile and run the app. This time, your app should work as expected. Try to select any recipe and the detail view should display the name of the selected item.
From:http://www.appcoda.com/storyboards-ios-tutorial-pass-data-between-view-controller-with-segue/
iphone dev 入门实例2:Pass Data Between View Controllers using segue的更多相关文章
- iphone dev 入门实例4:CoreData入门
The iPhone Core Data Example Application The application developed in this chapter will take the for ...
- iphone dev 入门实例5:Get the User Location & Address in iPhone App
Create the Project and Design the Interface First, create a new Xcode project using the Single View ...
- iphone dev 入门实例7:How to Add Splash Screen in Your iOS App
http://www.appcoda.com/how-to-add-splash-screen-in-your-ios-app/ What’s Splash Screen? For those who ...
- iphone dev 入门实例6:How To Use UIScrollView to Scroll and Zoom and Page
http://www.raywenderlich.com/10518/how-to-use-uiscrollview-to-scroll-and-zoom-content Getting Starte ...
- iphone dev 入门实例3:Delete a Row from UITableView
How To Delete a Row from UITableView I hope you have a better understanding about Model-View-Control ...
- iphone dev 入门实例1:Use Storyboards to Build Table View
http://www.appcoda.com/use-storyboards-to-build-navigation-controller-and-table-view/ Creating Navig ...
- iphone Dev 开发实例9:Create Grid Layout Using UICollectionView in iOS 6
In this tutorial, we will build a simple app to display a collection of recipe photos in grid layout ...
- iphone Dev 开发实例8: Parsing an RSS Feed Using NSXMLParser
From : http://useyourloaf.com/blog/2010/10/16/parsing-an-rss-feed-using-nsxmlparser.html Structure o ...
- iphone Dev 开发实例10:How To Add a Slide-out Sidebar Menu in Your Apps
Creating the Xcode Project With a basic idea about what we’ll build, let’s move on. You can create t ...
随机推荐
- C++ Primer : 第十三章 : 拷贝控制之拷贝、赋值与销毁
拷贝构造函数 一个构造函数的第一个参数是自身类类型的引用,额外的参数(如果有)都有默认值,那么这个构造函数是拷贝构造函数.拷贝构造函数的第一个参数必须是一个引用类型. 合成的拷贝构造函数 在我们没 ...
- 网站不能访问(httperrLog【Timer_MinBytesPerSecond】【Timer_ConnectionIdle】)(转载)
在\LogFiles\HTTPERR的日志(C:\Windows\System32\LogFiles\HTTPERR)中发现了大量Timer_MinBytesPerSecond,Timer_Conne ...
- Apache使用mod_deflate模块压缩页面优化传输速度
可以写为一行,也可以写多行,默认为gzip SetOutputFilter DEFLATE # Restrict compression to these MIME types AddOutputFi ...
- 状态压缩dp 入门
1.有一张n*m (n<=m)的棋盘,在上面放n个中国象棋里的车,使得任意两个车不能相互攻击,总共有多少种不同的方案. 2.有一张n*m (n<=m)的棋盘,其中有些格子里面不能放,在上面 ...
- [转] JAVA网站高并发解决方案
http://blog.csdn.net/herrapfel/article/details/9630911
- jQuery插件 -- 表单验证插件jquery.validate.js, jquery.metadata.js
原文地址:http://blog.csdn.net/zzq58157383/article/details/7718352 最常使用JavaScript的场合就是表单的验证,而jQuery作为一个 ...
- SQL2005中设置自动编号字段【转】
如果希望重新定义在表中添加新记录时该列中自动生成并存储于列中的序列号,则可以更改该列的标识属性.在每个表中只能设置一个列的标识属性. 具有标识属性的列包含系统生成的连续值,该值唯一地标识表中的每一行( ...
- jspm 是浏览器包管理工具
jspm 是浏览器包管理工具. jspm 是 SystemJS 通用模块加载器的包管理器,基于动态 ES6 模块加载器 直接从任意的 registry(比如 npm 或者 GitHub)加载任意模块格 ...
- 解决Win10默认占用80端口
方案1: 以管理员身份运行cmd;输入net stop http;如果提示是否真的需要停止这些服务,则选择“Y”;完成后输入:sc config http start=disabled 方案2: Ct ...
- mysql四种事务隔离级的说明
·未提交读(Read Uncommitted):允许脏读,也就是可能读取到其他会话中未提交事务修改的数据 ·提交读(Read Committed):只能读取到已经提交的数据.Oracle等多数数据库默 ...