Scrambled Polygon(凸多边形,斜率)】的更多相关文章

Scrambled Polygon Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 7805   Accepted: 3712 Description A closed polygon is a figure bounded by a finite number of line segments. The intersections of the bounding line segments are called the…
Scrambled Polygon Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 7799   Accepted: 3707 Description A closed polygon is a figure bounded by a finite number of line segments. The intersections of the bounding line segments are called the…
Scrambled Polygon Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 7214   Accepted: 3445 Description A closed polygon is a figure bounded by a finite number of line segments. The intersections of the bounding line segments are called the…
Scrambled Polygon Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 8636   Accepted: 4105 Description A closed polygon is a figure bounded by a finite number of line segments. The intersections of the bounding line segments are called the…
Given a list of points that form a polygon when joined sequentially, find if this polygon is convex (Convex polygon definition). Note: There are at least 3 and at most 10,000 points. Coordinates are in the range -10,000 to 10,000. You may assume the…
http://poj.org/problem?id=2007 Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 6701   Accepted: 3185 Description A closed polygon is a figure bounded by a finite number of line segments. The intersections of the bounding line segments ar…
题目传送门 题意:裸的对原点的极角排序,凸包貌似不行. /************************************************ * Author :Running_Time * Created Time :2015/11/3 星期二 14:46:47 * File Name :POJ_2007.cpp ************************************************/ #include <cstdio> #include <al…
题目链接 题意 : 对输入的点极角排序 思路 : 极角排序方法 #include <iostream> #include <cmath> #include <stdio.h> #include <algorithm> using namespace std; struct point { double x,y; }p[],pp; double cross(point a,point b,point c) { return (a.x-c.x)*(b.y-c.y…
给一些点,这些点都是一个凸包上的顶点,以第一个点为起点顺时针把别的点拍排一下序列. 分析:最简单的极坐标排序了..................... 代码如下: -------------------------------------------------------------------------------------------------------------------------- #include<iostream> #include<algorithm>…
/** 极角排序输出,,, 主要atan2(y,x) 容易失精度,,用 bool cmp(point a,point b){ 5 if(cross(a-tmp,b-tmp)>0) 6 return 1; 7 if(cross(a-tmp,b-tmp)==0) 8 return length(a-tmp)<length(b-tmp); 9 return 0; 10 } **/ #include <iostream> #include <algorithm> #includ…