Coded triangle numbers Problem 42 The nth term of the sequence of triangle numbers is given by, tn = ½n(n+1); so the first ten triangle numbers are: 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, - By converting each letter in a word to a number corresponding…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5312 Sequence Time Limit: 2000/2000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 1336 Accepted Submission(s): 410 Problem Description Today, Soda has learned a…
本题来自 Project Euler 第12题:https://projecteuler.net/problem=12 # Project Euler: Problem 12: Highly divisible triangular number # The sequence of triangle numbers is generated by adding the natural numbers. # So the 7th triangle number would be 1 + 2 + 3…
递归方法解决数塔问题 状态转移方程:d[i][j]=a[i][j]+max{d[i+1][j],d[i+1][j+1]} 注意:1\d[i][j]表示从i,j出发的最大总和;2\变界值设为0;3\递归变界为n;4\结果为d[1][1] #include<iostream> #include<algorithm> using namespace std; #define maxn 1000+5 int n; int a[maxn][maxn]; int d[maxn][maxn];…
1.直接用递归函数计算状态转移方程,效率十分低下,可以考虑用递推方法,其实就是“正着推导,逆着计算” #include<iostream> #include<algorithm> using namespace std; #define maxn 1000+5 int n; int a[maxn][maxn]; int d[maxn][maxn]; int main(){ for(;cin>>n && n;){ memset(d,,sizeof(d));…
极角排序后枚举每个点,计算其与原点连线的左侧的半平面内的点与其组成的三角形数(二分/尺取),这些都不是黄金三角形. 补集转化,用平面内所有三角形的个数(C(n,3))减去这些即可. 精度很宽松,几乎不用管. #include<cstdio> #include<algorithm> #include<cmath> using namespace std; typedef long long ll; typedef double db; #define N 100001 c…
The nth term of the sequence of triangle numbers is given by, tn = ½n(n+1); so the first ten triangle numbers are: 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ... By converting each letter in a word to a number corresponding to its alphabetical position and…
题目链接:https://vjudge.net/problem/ZOJ-3430 Detect the Virus Time Limit: 2 Seconds Memory Limit: 65536 KB One day, Nobita found that his computer is extremely slow. After several hours' work, he finally found that it was a virus that made his poor…
Anagramic squares By replacing each of the letters in the word CARE with 1, 2, 9, and 6 respectively, we form a square number: 1296 = 362. What is remarkable is that, by using the same digital substitutions, the anagram, RACE, also forms a square num…
觉得有用的话,欢迎一起讨论相互学习~Follow Me tf.image.decode_png(contents, channels=None, name=None) Decode a PNG-encoded image to a uint8 tensor. 将一个png编码的图像解码成一个uint8张量. The attr channels indicates the desired number of color channels for the decoded image. 参数"chan…
