POJ.1330 Nearest Common Ancestors (LCA 倍增) 题意分析 给出一棵树,树上有n个点(n-1)条边,n-1个父子的边的关系a-b.接下来给出xy,求出xy的lca节点编号. LCA裸题,用倍增思想. 代码总览 #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #define nmax 80520 #define demen…

Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 19728   Accepted: 10460 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:    In the figure, e…

Nearest Common Ancestors Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:  In the figure, each node is labeled with an integer from {1, 2,...,16}. Node 8 is the root of the tree.…

题目链接:http://poj.org/problem?id=1330 A rooted tree is a well-known data structure in computer science and engineering. An example is shown below: In the figure, each node is labeled with an integer from {1, 2,...,16}. Node 8 is the root of the tree. N…

/* *********************************************** Author :kuangbin Created Time :2013-9-5 9:45:17 File Name :F:\2013ACM练习\专题学习\LCA\POJ1330_3.cpp ************************************************ */ #include <stdio.h> #include <string.h> #inclu…

给定一棵树求任意两个节点的公共祖先 tarjan离线求LCA思想是,先把所有的查询保存起来,然后dfs一遍树的时候在判断.如果当前节点是要求的两个节点当中的一个,那么再判断另外一个是否已经访问过,如果访问过的话,那么它的最近公共祖先就是当前节点祖先. 下面是tarjan离线模板: #include <cstdio> #include <cstring> #include <algorithm> using namespace std; ; struct Edge { i…

POJ - 1330 Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000KB   64bit IO Format: %lld & %llu Submit Status Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:  In t…

POJ 1330 Nearest Common Ancestors / UVALive 2525 Nearest Common Ancestors (最近公共祖先LCA) Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below: In the figure, each node is labeled with an…

POJ 1330 Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 24209   Accepted: 12604 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:  In the fi…

POJ 1330 Nearest Common Ancestors A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:  In the figure, each node is labeled with an integer from {1, 2,...,16}. Node 8 is the root of the tree. No…

POJ 1330 Nearest Common Ancestors 题意:最近公共祖先的裸题 思路:LCA和ST我们已经很熟悉了,但是这里的f[i][j]却有相似却又不同的含义.f[i][j]表示i节点的第2j个父亲是多少   这个代码不是我的,转自 邝斌博客 /* *********************************************** Author :kuangbin Created Time :2013-9-5 9:45:17 File Name :F:\2013AC…

任意门:http://poj.org/problem?id=1330 Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 34942   Accepted: 17695 Description A rooted tree is a well-known data structure in computer science and engineering. An example…

pku 1330 Nearest Common Ancestors 题目链接: http://poj.org/problem?id=1330 题目大意: 给定一棵树的边关系,注意是有向边,因为这个WA一发.然后N个顶点给出了N-1有向边,求一对点之间的最近公共祖先 思路: 裸的离线tarjan Lca即可,但注意是有向边,需要先找出根节点,数组标记.其次要注意前向星存的时候只存一条边即可 代码: #include <iostream> #include <string.h> usi…

Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 20715   Accepted: 10910 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below: In the figure, each…

Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 14902   Accepted: 7963 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:  In the figure, each…

传送门 Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 26612   Accepted: 13734 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:    In the figur…

Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 30147   Accepted: 15413 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:  In the figure, eac…

Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 19919   Accepted: 10544 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below: In the figure, each…

Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 39596   Accepted: 19628 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below: In the figure, each…

Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 27316   Accepted: 14052 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:  In the figure, eac…

Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 14698   Accepted: 7839 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:  In the figure, each…

Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 24618   Accepted: 12792 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below: In the figure, each…

Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 30082   Accepted: 15386 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:  In the figure, eac…

题目:Nearest Common Ancestors 根据输入建立树,然后求2个结点的最近共同祖先. 注意几点: (1)记录每个结点的父亲,比较层级时要用: (2)记录层级: (3)记录每个结点的孩子,vector<int> v[M]写在主函数里面,放在外面超时. 代码: #include<iostream> #include<vector> #include<cstdio> #include<cstdlib> #include<cstr…

Nearest Common Ancestors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 37386   Accepted: 18694 Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below: In the figure, each…

题目链接:http://poj.org/problem?id=1330 题意:给定一个n个节点的有根树,以及树中的两个节点u,v,求u,v的最近公共祖先. 数据范围:n [2, 10000] 思路:从树根出发进行后序深度优先遍历,设置vis数组实时记录是否已被访问. 每遍历完一棵子树r,把它并入以r的父节点p为代表元的集合.这时判断p是不是所要求的u, v节点之一,如果r==u,且v已访问过,则lca(u, v)必为v所属集合的代表元.p==v的情况类似. 我的第一道LCA问题的Tarjan算法…

Description A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:    In the figure, each node is labeled with an integer from {1, 2,...,16}. Node 8 is the root of the tree. Node x is an ancestor…

题目链接:http://poj.org/problem?id=1330 题意:给定一个n个节点的有根树,以及树中的两个节点u,v,求u,v的最近公共祖先. 数据范围:n [2, 10000] 思路:从树根出发进行后序深度优先遍历,设置vis数组实时记录是否已被访问. 每遍历完一棵子树r,把它并入以r的父节点p为代表元的集合.这时判断p是不是所要求的u, v节点之一,如果r==u,且v已访问过,则lca(u, v)必为v所属集合的代表元.p==v的情况类似. 我的第一道LCA问题的Tarjan算法…

1.输入树中的节点数N,输入树中的N-1条边.最后输入2个点,输出它们的最近公共祖先. 2.裸的最近公共祖先. 3. dfs+ST在线算法: /* LCA(POJ 1330) 在线算法 DFS+ST */ #include<iostream> #include<stdio.h> #include<string.h> using namespace std; ; *MAXN];//rmq数组,就是欧拉序列对应的深度序列 struct ST{ *MAXN]; *MAXN][…

题目链接:http://poj.org/problem?id=1330 题意就是求一组最近公共祖先,昨晚学了离线tarjan,今天来实现一下. 个人感觉tarjan算法是利用了dfs序和节点深度的关系,大致的意思:dfs如果不递归到递归基,那么dfs就会越递归越深,这个时候深度也是相应增加的,所以这个时候任意在已经遍历过的节点中选取两个点,计算他们的lca也就相当于是用并查集求他们的root.而dfs执行到递归基,转而执行下一个分支的时候,这个时候dfs的节点应当是小于等于之前执行到递归基的节点…